Thermodynamics - Entropy 7.3 Pure Substances

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Thermodynamics - entropy of pure substances
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Опубликовано:

11 июл 2018

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Комментарии : 30

@mebawubeshet6729 Месяц назад

Foe anyone wondering why the specific volume stays the same , it is not because of the rigid tank but because of the rigid tank + mass stays same. rigid tank alone tells us only the volume stays the same not the specific volume

@rutvikshah9922 5 лет назад

Thank you so much for this video..!! This was all I needed..!!

@aminzamani7866 3 года назад

thanks alot to you for helping us undrestanding thermodynamics better.i have question. I use van wylen property table and there is a huge difference between that and which you are using.i am somehow confused which one is better to use??

@enesberkkocak5621 Год назад

on question 5,i cant verify the vfg that you wrote as .18255 i find it as 0.19254 on the table.Can you tell where is my mistake?Where should i look on the property tables?

@yigitcan824 7 месяцев назад

I guess his property table shows different values some times.

@aliozaltn5928 3 года назад

how did you find the s2 and u2 in the last question you solved ?

@engineeringdeciphered 3 года назад

If you know the temp (40 C) and quality (0.45) then you can calculate everything else. Go to the temp table, find the line for 40C, and calculate s = sf + x(sfg). Same thing with u. Does that make sense?

@anasthasyatalitha4209 3 года назад

good day, i would like to ask for the units that are used for number 6. should we convert F, psia, BTU to C, MPa and kJ/kg? or are there any different tables that were used ? thank youu

@engineeringdeciphered 3 года назад

We have tables for English units: appendix 2 here: www.dropbox.com/s/tuqy5e8657ysoda/Property%20Tables%20-%20Appendices%201%20and%202.pdf?dl=0

@anasthasyatalitha4209 3 года назад

@@engineeringdeciphered thank youuu this is really what i need thank you so much

@gabriellajasmine4165 3 года назад

hello, would it be possible if u share the tables that you use ? thanks a lot 🙏🏻

@engineeringdeciphered 3 года назад

www.dropbox.com/s/tuqy5e8657ysoda/Property%20Tables%20-%20Appendices%201%20and%202.pdf?dl=0

@gabriellajasmine4165 3 года назад

@@engineeringdeciphered thats very helpful, thanks again !

@muhd.nurissamuddinbiniskan3912 3 года назад

im sorry but how did u find the vf and y again? because when i try to find from table i cant find it.

@muhd.nurissamuddinbiniskan3912 3 года назад

its okay i found it already. btw nice video. i understand better now

@zaydbhikhu4129 3 года назад

For an isothermal process, isn't change in internal energy zero?

@engineeringdeciphered 3 года назад

For gases, yes, usually internal energy is defined by temperature. But for liquids and especially liq-vapor mixtures, no - something can be isothermal but it is changing states and internal energy is definitely not constant.

@burakemreevrenos8385 Год назад

In question 7, how do we know there's no entrophy generation? ΔS= ∫ δQ/T +σ(entrophy generation term). If T is constant, the integral becomes Q/T but we also have another unknown which is the entrophy generation term

@engineeringdeciphered Год назад

I think because it’s an isothermal heat transfer, there is no entropy generation.

@burakemreevrenos8385 Год назад

@@engineeringdeciphered thanks sir

@yigitcan824 6 месяцев назад

@@burakemreevrenos8385So it must be totally reversible?

@boramerttigli3215 3 года назад

Initially, thank you so much for your helpful videos. At the last part of last question, why did you used u instead of h? I am confused because the tank is not rigid.

@engineeringdeciphered 3 года назад

For problem 7: you’ve got to use u because it is not constant pressure. We use H when it is a constant pressure process, use u for any other process.

@boramerttigli3215 3 года назад

@@engineeringdeciphered Thank you for the answer but at the next video (Thermodynamics - Entropy 7.4 Isentropic processes) you used h in the 8.question(at 6.00 sec). And it is not a constant pressure process.

@engineeringdeciphered 3 года назад

@@boramerttigli3215 oh yes, definitely use h for steady flow devices and flowing fluid as well. I was just talking about closed systems. H combines u and pv so that takes care of both internal energy and flow work (for a flowing fluid) or internal energy and constant pressure boundary work (for closed, constant pressure systems).

@boramerttigli3215 3 года назад

Ok i see now. Thank you very much for your help. 😊