Sql one of the most important language asked in most of the analytics interviews, in this i will be solving sql questions which was asked to me in one of the company.
Query
drop table if exists transactions;
CREATE TABLE transactions(transaction_id integer,userid integer,created_at date ,updated_at date,status text,amount int);
INSERT INTO transactions(transaction_id,userid,created_at,updated_at,status,amount)
VALUES (1,1,'04-19-2017','04-21-2017','Fail',105),
(2,3,'12-18-2019','12-19-2019','Success',215),
(3,2,'07-20-2020','07-23-2020','Success',416),
(4,1,'10-23-2019','10-26-2019','Fail',410),
(5,1,'03-19-2018','03-22-2018','Success',254),
(6,3,'12-20-2016','12-23-2016','Fail',227),
(7,1,'11-09-2016','11-11-2016','Success',351),
(8,1,'05-20-2016','05-23-2016','Success',110),
(9,2,'09-24-2017','09-27-2017','Success',135),
(10,1,'03-11-2017','03-14-2017','Fail',281),
(11,1,'03-11-2016','03-12-2016','Success',57),
(12,3,'11-10-2016','11-11-2016','Success',417),
(13,3,'12-07-2017','12-08-2017','Fail',385),
(14,3,'12-15-2016','12-16-2016','Success',329),
(15,2,'11-08-2017','11-10-2017','Fail',67),
(16,2,'09-10-2018','09-13-2018','Success',233);
drop table if exists customer;
CREATE TABLE customer(userid integer,date date);
INSERT INTO customer(userid,date)
VALUES
(1,'09-22-2009'),
(2,'09-10-2011'),
(3,'04-21-2015');
select * from customer ;
select * from transactions;
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6 сен 2024
