As a sort of analysis on approaches to YT videos, I watched fifteen of them on this exact subject today... yours was my favorite. Clear cut winner. The best explanation, without obtuse analogies. Great job. I'm going to ck out more of your content.
I never understood the relationship until seeing your explanation with the formula and the torque/hp map. Now I understand why peak HP is always on a higher RPM than peak torque and why my torque/hp increases with boost and drops off near redline. It's complicated but simple. Thanks for the lesson.
I actually like how this guy goes into the formula rather than just sit there and point at random engine parts acting like he knows what he's talking about. That's why I always love watching your vids man keep at it!
I'd like to see the difference simple fluids make. Dyno the car as is, then get a reading with new, quality oil, coolant, trans, and diff fluid. That's stuff nearly anyone can do at home, and it all should really be done regularly anyway.
Entertaining and educational. A few additions... The lower case r represents the radial length or radius of the lever circle. The 5252 is a constant derived from the horsepower equation where the radius or radial length is 1 foot. This is the constant that combines the definition of one horsepower, the conversion of minutes to seconds, and the translation of circular motion into linear motion. The constant 5252 is the rounded value of (33,000 ft·lbf/min)/(2π rad/rev). 550 lb ft/sec = 1 horsepower 33,000 lb ft/min = 1 horsepower 1 Minute = 60 seconds 1 Revolution = 3.1416 (Pi) x 2 550 x 60 / 3.1416 x 2 = 5252 33,000 / 6.2832 = 5252 Since the rotational speed is expressed as revolutions per minute (RPM) we need the constant 5252 to accurately complete the equation to calculate Imperial/US Customary and Metric/SI Horsepower units. Because torque and RPM are equally divided by 5252 in the Horsepower calculation, torque and horsepower are always equal at 5252 RPM. When using Metric/SI units to calculate Watts then the constant is 9549. Because torque and RPM are equally divided by 9549 in the Watts calculation, torque and Kilowatts are always equal at 9549 RPM.
thank you, i get the impression lots of people know the effects of torque and hp, but they are too proud to acknowledge they don't know what they actually are nor the equations or why we use them, thank you for explaining!
Your one liners cracked me up. That aside, this was a good reminder of math that we can actually use. If there is a drive pulley system that aids in a power increase, that would be interesting. I've heard of it being done for slalom cars, but never seen one installed.
That would be extremely interesting... like physics is broken, interesting:) Unfortunately you can't always improve performance by changing gearing. Consider a moment in the life of an accelerating car: Could it be accelerating harder by using a higher gear ratio? The answer is always yes *if* that higher gear ratio would result in a larger increase in input (engine) rpm than a resulting decrease in input torque. In other words, yes if the *product* of torque and rpm at the engine (power) is higher. If that higher ratio results in a larger decrease in engine torque than the increase in engine speed, than we have reduced acceleration at this moment. Making sense?
I think that the difference of torque and hp or power are very confusing but the way that you explained it, is very practical and with real examples. Thank you.
Good stuff. That was the clearest explanation of horse power I've seen. It's a concept I can't visualize well, and have trouble with. Torque over time! How have I missed that for so long.
Hard to visualize is right! I can say the idea of "torque over time" is not doing you any favors. That's not what power is at all. The most correct way to think power intuitively in a vehicle is "capacity to accelerate a heavy thing"... promise. Remember that it's just torque times engine speed. Every vehicle has some ratio of engine rpm to ground speed. The thrust propelling the vehicle is proportional to engine torque times this ratio. So the thrust is related to the *product* of engine torque and rpm, not just engine torque. That's why power is so important and engine torque alone tells us nothing.
Thankyou for this explanation! I always knew there was some missing information on how horse power was measured and standardized as a measurement but nothing seems to explain it so i just always seen horse power being the same thing as torque. This makes complete sense
Wtf!! Been looking under every wrench and socket in this garage called the internet for an explanation that makes sense. Your video covered everything. No really, everything! And it is so simple!!! Never knew!!! Thank you!!! SUBSCRIBING!!
A lot of people think if they want to feel fast acceleration they need an engine with high torque like a turbo diesel. A high torque engine feels effortless because it doesn't make too much noise since it runs at low rpm but it doesn't make the car go faster than a low torque with the same power. Actually the power/ torque - rpm curve matters but maximum power gives you a good approximation of the acceleration of the car but the max torque doesn't. Basically you need torque times rpm which is actually power. A turbocharger gives you a better power- rpm curve which makes a car a bit faster having the same max power as a naturally aspirated engine. Turbodiesels are turbocharged and that makes them a bit faster than a non-turbo at same rated power.
The perpendicular notation on the F component denotes a perpendicular force to the handle of the breaker bar, not of the breaker bar being perpendicular to the wheel hub/axle nut. The angle of the handle is not important, only the perpendicular distance from the axle to the handle is needed for the equation, and that perpendicular measurement is implied in physics so it doesn't require a notation as does the F component. So basically, torque values are the force exerted at exactly that one singular point of perfect perpendicularity on, in this case, the handle of your breaker bar.
Your explanation of torque is really good but I *think* that when you say the wrench has to be perpendicular to the axle because of the formula, it is not because of the formula itself but because when you pivot the breaker bar your are changing the length of the radius. The actual formula is torque=(radius length)(force)(sin(x)), where x is the angle between the radius arm and the force vector, which in this case the the angle of your arm relative to the breaker bar. Since sin(90*)=1, the term disappears and you get the formula you showed which specifies the perpendicular force vector. Hope I'm not a buzzkill lol awesome video man!
Tony J. He was trying to simplify in practice the concepts, not fill ones head with theory. But I do like your theoretical explanation, regards, Stewart, Australia
tl;dl these pics cdn.shopify.com/s/files/1/0646/5139/files/Pinkbike-Torque-Diagram_grande.jpg?2259 lancet.mit.edu/motors/ratchetdiagram.gif so basically, in his explanation, he was not changing the angle that the force was applied at, instead he was changing the distance/ length of the lever used. in a corrected version, he could've shown his arm pushing at right angles to the ratchet, with the force being applied so that all of it is only turning the axle (nut) and none if it is pushing the axle sideways or any other direction.
He's actually right, and your wrong... The equation is F x D = Torque. The "x" doesn't just mean multiplication, but a vector cross product.. you'll probably learn it next year.
Great video! Had a hard time finding someone or a resource to explain it in simple terms. Sick of when asking people questions like what time it is? They tell me how to build a watch.
Being I did work with horse's in the 1970's at Van Courtlant Stables in the Bronx... We had a number of displacements. Blue Bell for example she was a one cylinder but she was also trick.. Dapples my horse pregnant but all 3 firing. Now King... All 8 firing and I figured if I made it past my maiden voyage with him I would make it to today. So far so good. Moral of the story what we really do not understand about Horsepower... You'll know the Real 4 wheel drive when you have ridden on it. Keep in mind they have to like you a lil..
An Audi is my guess on the blurred-out project car, but I'm not acquainted with foreign vehicles, so no guesses as to model. I have a cousin who drives Audi, but I don't know enough to appreciate them - I enjoy hearing/seeing late 1960 muscle cars, or even their 2010+ remakes. Any possibility of a video on top 5 used diesel pick-ups that can tow 13,000+ lbs. for $5000? Haha, I'd have to be a mechanic for that one to work, I bet. Great videos, I enjoy watching your channel. Cheers!
What is the best metaphor to get started? How about Hammer and Nail? You can raise a hammer and slam it down on the nail and if you hit it dead center it might go right through on your first hit. If you place the hammer head on the nail head and push with all your weight, you probably won't move the nail much. You are not any stronger or weaker, heavier, lighter in either case. Does torque explain the sudden and instantaneous impact of that hammer which causes such momentum that it breaks the friction of the wood and nail?
Used to pull up to 1,200 foot pounds manually on the 747. Used a multiplier. Highest we would pull 1:1 was 900 ft lbs. Enerpac with a reaction bar would get us to 2,400 ft lbs.
Torque, simply, is the ability of a vehicle to perform work - specifically, the twisting force applied by the crankshaft. Horsepower is how rapidly the vehicle can perform that work. ... Because there is generally a limit on how fast you can spin an engine, having higher torque allows for greater horsepower at lower rpms
i am doing the cam seals & caps 0n 2.7l Bi -turbo & timing belt . i had cam alignment tool & crankshaft pin in place. while tying to pull exhaust cam pulley. the pulley popped lose & alignment popped off rotating the exhaust cam 2.5 links. appx. I pulled it back two the marks . I changed the exhaust cap seal . i tighten everything back to spec . i rotated engine twice the marks where slightly off. then rotated again the timing are marks even even more off? i think cam chain tensioner is broken . it keeps going up and down but when it goes down it falls. and i can push it down with my hand sometimes!
help! i have fiat punto 1.2 16v petrol year 2001. in the morning when car is cold pulls just fine all the way up 6k rpm, no hesitation. but as the car warms up losses power and hesitates so bad, feels like 50-60 % down in power, i need to step very very slowly on the gas pedal to gain speed more quicly. so far i have changed leads and spark plugs and they made a little diference but the prblem is still there.
you might as well be an engineer. Engineering student here and you explain way simpler than professor. Thanks. Now it makes sense. and lmao @ 550 lb wife!!!
I learned one thing in this video, how to measure torque and you said torque is the force made by the crankshaft. the easiest to understand ever still looking for the easiest explanation of horse power have no idea how to understand that one.
I did your equation and it didn't come to the HP that the dynapack says I have. 158.38 lbft of torque @ 5419 rpms @ 83.7mph and 192.09 hp @ 7010 rpms @ 108.3mph...these were 4th gear pulls on my car.
