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Transformer leakage in LLC converters 

Sam Ben-Yaakov
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8 сен 2024

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Комментарии : 24   
@tangy1181
@tangy1181 Месяц назад
Thank you for the detailed explanation! Would it be possible to arrange a seminar focusing on the actual transformer design for a CLLLC converter? I find the aspect of designing the leakage inductance particularly challenging and would greatly appreciate a comprehensive discussion on this topic.
@sambenyaakov
@sambenyaakov Месяц назад
Thanks for input. Yes, controlling the leakage is a challenge. Will try to report on this further.
@DerExperiminator
@DerExperiminator Год назад
Thank You very much for this video. I also watched the other two videos and at the last now, i'm convinced, that You are right. Problem being, that i don't understand it, and i hope, You can give me a hint, where i'm wrong in my understanding: For this i want to look at an LLC circuit, using the T equivalent circuit, with one stray inductance on each side and an ideal tranformer, with a ratio of 1:1. Actually i don't want to look inside the transformer, because You already showed that even an external inductance on on side will not make a diffence, if compared from primary or secondary side. So, for this case, stray inductance shall be either an external inductor or stray inductance of the connections of the transformer, in any case, it is totally clear to which side it belongs. Now, talking about LLC, we have two important resonances, first is Cres with Lstray and second is Cres with Lstray+Lmagnetization. (simplified) I want to look at the second resonance frequency (which actually is the lower one). Let's now look at short circuit and open circuit. With the T-equivalent circuit, L would be Lstray,primary+(Lmagnetization||Lstray,secondary) for short ciruit on secondary side. With the L-equivalten circuit (all stray inductance on primary side), L would be Lstray, which is similar to Lstray,primary+Lstray,secondary, but the influence of Lmagnetization is missing, thus the resonance frequency (with Cres) would not be the same between L- and T-equivalent circuit. Now lets look at open circuit on secundary side: With the T-equivalent circuit, L would be Lstray,primary+Lmagnetization With the L-equivalten circuit, L would be Lstray+Lmagnetization, which is a higher inductance value, because Lstray>Lstray,primary. Again, the resonance frequency wouldn't be the same between L- and T-equivalent circuit. You are working with the mutual inductance, is it totally similar to the magnetization inductance? Or is it perhapps changing slightly btw. L- and T-equivalent ciruit, to compensate the above shown discrepancy? Let me ask the question differently: If i add an external inductor as a stray inductance, you still can explain this ciruit with an L- or T-equivalent circuit, if you do all the math right, but the behavior of a LLC-circuit will differ between putting the external inductor on primary side or secondary side, right?
@sambenyaakov
@sambenyaakov Год назад
The last version of your question is excellent. Never thought about this example. Thank you. Yes, if you put an external inductor on one side the behavior will be different from the other case. BUT, if you put it on one side, find the model of the total assembly, coued inductors plus inductor, and then tranform it to a form of inductor on the orher side, the response will be the same. But the value of reflected inductor will be different. Beautiful example..
@huanzhou4768
@huanzhou4768 Год назад
very interesting presentation ! Thanks professor.
@sambenyaakov
@sambenyaakov Год назад
Thanks
@warrenbaker4171
@warrenbaker4171 Год назад
Excellent professor! Thank you!
@sambenyaakov
@sambenyaakov Год назад
Thanks
@HadiiKarami
@HadiiKarami Год назад
Thanks man i need to learn it
@sambenyaakov
@sambenyaakov Год назад
😊👍
@esijal
@esijal Год назад
Thanks professor 👌🙏
@sambenyaakov
@sambenyaakov Год назад
Thanks
@JonitoFischer
@JonitoFischer 11 месяцев назад
The equivalence between the L and T models are true only if magnetizing inductance is high enough so Lm//Llk(p,s)=Llk(p,s), i.e. Lm can be neglected. If Lm is low, then the most accurate model is the T one....
@JonitoFischer
@JonitoFischer 11 месяцев назад
The unbalanced models are an useful approximation only if magnetizing inductance is high (which in general is a design goal in a good enough transformer, but not in transformers for resonant converters with intentional leakage inductance)
@sambenyaakov
@sambenyaakov 11 месяцев назад
You are mistaken. No difference if the transformation is made correctly. See ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-TUfaN40T1Yg.html
@Chris_Grossman
@Chris_Grossman Год назад
It is easy to believe that all of the representations can be equivalent when all of the elements are linear. In fact any n port linear network can have many related internal models for which the external network parameters are identical. What happens when the transformer elements are non-linear like core hysteresis or saturation? p.s. This was a very interesting series. Thank you
@sambenyaakov
@sambenyaakov Год назад
At any operating point, once linearized, everything is the same, For large signal just use a non linear coupled inductor model - why bother with equivalent circuits?.
@biswajit681
@biswajit681 Год назад
Sir why did you use pulse waveform top of the AC analysis??
@sambenyaakov
@sambenyaakov Год назад
At what minute of video- or slide number?
@Stelios.Posantzis
@Stelios.Posantzis Год назад
5:20 Would it be possible for the very large inductance value to cause numerical errors in LTSpice? Clearly the simulation shows this to be a non-issue but I'm wondering how far one can go with such values.
@sambenyaakov
@sambenyaakov Год назад
Not really
@SteveWard
@SteveWard 11 месяцев назад
@@sambenyaakov I'm replicating these various models for myself in LTspice, it seems that when coupling factor is small (example,K=0.15 used for Tesla coils for example) the model which puts all the leakage on the primary side utilizing an "ideal transformer" for coupling, gives funny results. However with larger coupling coefficients, the different models match very well. I do have to wonder if its not an issue of a "big number" (1E5) divided by a small number (K*K = .0225) giving some numerical errors. When i change 1E5 to a smaller value (1E2) the models match well, but if i try 1E6 or greater, the model shows wildly different results unless i use a larger K = 0.5 or greater.
@tamaseduard5145
@tamaseduard5145 Год назад
👍🙏❤️
@sambenyaakov
@sambenyaakov Год назад
#1 😊🙏
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