Triangle | Triangle Full Chapter/Tricks/Concept/Formula/Pythagoras Theorem | Triangle Class 10/9/8/7 

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A closed figure bounded by three lines segment is called triangle

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Second last question ans:AE=AB−CD=11−5=6 m (AC)²=(CE)² +(AE) ² =(12)² +(5)² =144+25=169 ⇒AC=13 m

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Class x topic starts from 14:10 Save your time

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Q 12 Distance between their poles = 13m Q 9 Distance of the foot of the ladder from base of the wall = 6m

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In equilatery triangle question AB²=¼AB²+AD² KE BAAD HUM AESA KARE TO 4AB²=AB²+AD² 4AB²-AB²=AD² 3AB²=AD² Pls samjaye

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1. Distance between their tops is 13 m. 2. Distance between the foot of the ladder and the base of the wall is 6 m.

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Question 9 answer is 10 . and question 12 answer is 1 Thank you so much sir for the great explanation ❤❤

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(1)The distance between their top is 13cm. and (2) the distance foot of the ladder from the wall is 6cm.

question 9= Let BA be the wall and AC be the ladder, Therefore, by Pythagoras theorem, AC2 = AB2 + BC2 102 = 82 + BC2 BC2 = 100 - 64 BC2 = 36 BC = 6m --------------------------------------------------------------------------------------------------------------------------------------- question 12= ANS= 13 - - - - - - - - 13M - - - - - 5M - - - - - - - 12M - ---------------------------------------------- - - - - - - - - - - - - - 6M - 6M - - - - - - - - - 12M - 5 2 + 12 2= ? --> 25+144= 169 -----> 13 ANSWER I spend almost 10 min for typing please like and subs dear sir

41:00 Answer is (a) 13m (b) 6 m

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