In this video I explained Trick For HydroBoration Oxidation which is an important concept for various competitive exams like IIT JEE, NEET, CET etc. To get more tricks subscribe my channel.
The H in BH3 shouldnt have a partial positive charge, since it it more electronegative than the B. Also the positive charge cant move, but the electrons are able to do so. The arrows should be pointing in the other direction (from the electronpair toward the positive charge)
It's not the actual mechanism for the reaction, it's just a trick to understand it, and she said earlier that she is not giving the mechanism but a trick
Mam....in diboranes is hydride transfer mechanism only .....in diborane H- only transfer....this reaction followed mark.kov addition rule but product is Anti Markov product mam...pls check and tell me mam..
1:48 ❎Here , you have made a mistake. Hydrogen is more electronegative than Boran . Then, it should have partial negative instead of partial positive. It will take a pair of electrons and combined with the carbon of the double bond which is the most substituted. You have also made the arrow wrongly. 1:49 ❎The arrow head should point towards to the electron deficient atom from the electron rich one.
Wrong method yrr🥺🥺!!! From 1:30 in BH3 , after clevage of H-BH2 , H gets negative charge and B gets positive charge because H is more electronegative than B. In boron due to incomplete octet it acts as an electrophilic centre and can easily accept lone pair of electron.Thus, alkene first attack to Boron (B) amd then Hydrogen (H) can itself attack to the carbon. So, finally at 1:41 it doesn't follow anti-markonikoff ,, it obviously also follow the Markonikoff's rule...😡😡😡
Awesome. . 👏👏 Thanks... U r saving my life Plz upload more videos as I'm gonna give neet this year.. It will be a great help.. Thank you Plz upload videos on thermodynamics and equilibrium.. . I need to understand these topics and I know your video will work for me. .. Plzz mam. .
At 0:24, you said that B2H6 is electron deficient species but i guess BF3 is electron deficient and this is the only reason why it forms B2H6 with 3C-2e banana bond to complete its octet? Would you please clear my doubt?
priya sehgal BH3 HAS ONLY 6 ELECTRONS MEANS IN BH3 B HAS ONLY SIX ELECTRONS SO IT IS ELECTRON DEFICIENT (having less than 8 electrons in lewis str.) SO IT DIMERISISES TO B2H6 TO COMPLETE THEIR OCTET.
