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TRICK- How to find Log and Antilog without using Log Table - NEET | JEE - Anurag Sir 

Aim4AIIMS
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Anurag Pareek Sir (Chemistry Faculty) explained here how to calculate log and anti-log without using table, log and anti-log .
This trick help students to solve big big competition problems in seconds related to log and anti log concept. Students will surely get help in NEET , AIIMS and JEE exam from this video.
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21 сен 2024

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Комментарии : 759   
@Aim4AIIMS
@Aim4AIIMS 5 лет назад
Download NEET "PrepOnline" App from Google Store for the final punch in your NEET & AIIMS Preparation. Download the app For Free bit.ly/2Hy3uZ1
@anchalyadav6358
@anchalyadav6358 4 года назад
Thanq so much sir😊😊😊....1 more request....plz tell us a shortcut method to find square root of different values...so that we can save ourselves from wasting time in neet.....😢😢😢😢
@dipankarkakde6342
@dipankarkakde6342 4 года назад
Thanks sooo much sir I have overcomed my one of the fear about chemistry👏👏👏👏👏best teacher...
@sushilsharma1416
@sushilsharma1416 3 года назад
This is an amazing video sir 👍👍👍👍
@sakshikochar2916
@sakshikochar2916 3 года назад
Exactlyyyyy Yrr!!
@namanjain5465
@namanjain5465 3 года назад
Please 🙏 reply
@sia00421
@sia00421 3 года назад
Wasted a lot of time in search of best log vdo...and finally get this masterpiece ❤️❤️🙏
@kushmalik261
@kushmalik261 3 года назад
Same here
@dark_knight002
@dark_knight002 3 года назад
Me too
@blackninjaop1765
@blackninjaop1765 3 года назад
Me to
@latesttrends6128
@latesttrends6128 2 года назад
Me2
@akm8822
@akm8822 2 года назад
Truly right
@KALKIATOR
@KALKIATOR 4 года назад
❤️You *proved* it sir "this is the *best video* on RU-vid for *Log & Antilog* " ❤️
@yashdhamale4572
@yashdhamale4572 3 года назад
♥😉❤😘😘😘😘😘😘😘😘😘😘❤u
@ananyaanuraganand4610
@ananyaanuraganand4610 5 лет назад
I dont know why so less views are here...best explaination on you tube.thankyou sir😊
@arpankumarpradhan4423
@arpankumarpradhan4423 4 года назад
Yaa mein yahan wahan dhund raha tha it is the best way
@kuhalidutta410
@kuhalidutta410 4 года назад
@@arpankumarpradhan4423 😌
@sulaxnabhardwaj9277
@sulaxnabhardwaj9277 3 года назад
Ya u r right😎😎😎😎
@krishna80808
@krishna80808 3 года назад
100 percent
@roshnimad2682
@roshnimad2682 3 года назад
Exactly yrr ,this one is the best
@bringeshkonda1464
@bringeshkonda1464 3 года назад
This video is very useful for me I am finding difficult to do some problems in equilibrium because of logs But this video helped me to tackle the problem Thankyou sir
@ankitpatilll
@ankitpatilll 3 года назад
Whenever i get confused in Log i come and watch this video helpful from 2 years. Thank you so much sir
@delectrod3872
@delectrod3872 2 года назад
Bhoi sahab , i declare this as the best video that u will ever found on youtube for log and antilog , for so quick and cover everything, and!!! I applied this in ionic equilibrium, chemical kinetics, electrochemistry Its all working 🔥🔥🔥
@avocadorable10
@avocadorable10 5 лет назад
Thanks a lot to keep your promise.
@panandkumarmsc
@panandkumarmsc 4 года назад
Excellent sir
@naveenchouhan6027
@naveenchouhan6027 4 года назад
Antilog 12:00 Thank you
@satendrar178
@satendrar178 4 года назад
Same here, I also came for that 😂
@mm-majesticminer6389
@mm-majesticminer6389 4 года назад
@@satendrar178 me too
@clasherworld9821
@clasherworld9821 4 года назад
@@satendrar178 are you from ushampur?
@satendrar178
@satendrar178 4 года назад
@@clasherworld9821 no
@nandankarakoti88
@nandankarakoti88 4 года назад
@@clasherworld9821 came via jee prep?😂
@Sureshchauhan-l6f
@Sureshchauhan-l6f 3 года назад
Sir I have 1 query This method is awesome But this is not valid in case of any value between log 1 and log2 e.g; log 1.24 Using this method .. log 1.24= 0.072 But in reality it is 0.093 Sir please help us.🙏
@MathTidbits
@MathTidbits 7 месяцев назад
for values of log between 1 and 2 use this formula 1 log x = _______________________________ (-.0855x + 1.188) + 2.31/(x-1) for your x = 1.24 1 log 1.24 = ________________________________ (-.0855(1.24) + 1.188) + 2.31/(1.24-1 ) 1 log 1.24 = ____________________________________ (-.10602 +1.188) + 2.31/.24 1 log 1.24 = __________________________________________ (1.08198 + 9.625) 1 log 1.24 = ________________________________ 10.70698 log 1.24 = .093397 .... log 1.24 = .093421.... (true value by scientific calculator)
@craveendran2523
@craveendran2523 5 лет назад
Very useful. Thank you so much sir. Most needed topic.
@shivaninegi3344
@shivaninegi3344 5 лет назад
Sir how to find negative antilog
@physicswallah1089
@physicswallah1089 3 года назад
Amazing anurag sir Allah bless you❤❤❤
@jishajunesh5410
@jishajunesh5410 4 года назад
Adipoli, awsome. Malayalis anybdy😍✌✌✌✌
@arshadahmed5861
@arshadahmed5861 4 года назад
😁😁😛
@tejaspillai6118
@tejaspillai6118 3 года назад
👋
@dr.bhubansahoo4767
@dr.bhubansahoo4767 5 лет назад
Brilliant explanation....thanks sir
@sudharsan9154
@sudharsan9154 3 года назад
I watched 9 video on this topic.this is master pieces of all. Love from tamilnadu👌
@kushmalik261
@kushmalik261 3 года назад
Same here
@surthikgp349
@surthikgp349 3 года назад
Same here!
@utj9559
@utj9559 2 года назад
Same
@mdgulamgaush9631
@mdgulamgaush9631 4 года назад
Sach me sir smile la di aapne chehre par,kitna pareshan tha 2-3dino se, questions ke last two lines hi nahi solve kr pata tha but sach me your way of explaining, your videos helped me alot.thank u from bottom of my heart.
@kshitijakawade3789
@kshitijakawade3789 3 года назад
Exactly👍 This is the BEST VIDEO ON LOG AND ANTILOG♥️ I wish I knew it before 😭
@Surbhikajal3001
@Surbhikajal3001 5 лет назад
Thank you so much sir.. For this.. I really need this.. Thank you.. 😊
@prabhjeetsahnienglish
@prabhjeetsahnienglish 5 лет назад
Sir start most wanted series for chemistry for neet aiims plss
@anonymousguy7754
@anonymousguy7754 3 года назад
Recently I was seeing log video on another channel and i was crying after seeing the complex methods....... Your channel made me smile.... Thank you.......
@tonystark9532
@tonystark9532 5 лет назад
He is my chemistry coaching teacher .... He is superb teacher
@natanshrajgor298
@natanshrajgor298 4 года назад
and u r ajey nagar aka carry????
@tonystark9532
@tonystark9532 4 года назад
@@natanshrajgor298 yes
@tonystark9532
@tonystark9532 4 года назад
@@natanshrajgor298 any problem
@natanshrajgor298
@natanshrajgor298 4 года назад
he teaches wonderfully
@tonystark9532
@tonystark9532 4 года назад
@@natanshrajgor298 yes he was my brother teacher actually I m commerce student
@adarshyadav2601
@adarshyadav2601 3 года назад
Very humble and honest person
@priteshrathod6893
@priteshrathod6893 4 года назад
Finally found the easiest way to find log and antilog!! A huge thanks to you Sir. Thank you sooooooo much. 💐💐🙏🙏
@yogeshpatel26100
@yogeshpatel26100 3 года назад
Sirr best shortcut Especially for NEET student Who don't study maths Thankss sir
@CHANDANKUMAR-hw4uf
@CHANDANKUMAR-hw4uf 3 года назад
Thanks sir
@vikramjeetsyalvickysyal8664
@vikramjeetsyalvickysyal8664 4 года назад
One of the best teacher in the world Thanks sir .
@Anjana-on5wr
@Anjana-on5wr 5 лет назад
Tremendous trick sir.
@elonfc
@elonfc 2 года назад
Watched till end thanks Well wishes from my side May universe bless you for your well-being
@pateldishank1345
@pateldishank1345 4 года назад
it was amazing! sir it helped a lot thnkx
@Rocyzvlogs
@Rocyzvlogs 4 месяца назад
Kon kon mr.sudhanshu sir ki baat maan kar yaha aya hai?🥺😅
@tanvigoyal639
@tanvigoyal639 2 года назад
Thank u so much sir this video will be saving by tomorrow's exam of chemistry chemical thermodynamics and energetics. I was so much trouble in finding antilog and log but u told very quickest way to calculate the same thanks a lot🙏🙏🙏☺️
@gauriprakashpathak2857
@gauriprakashpathak2857 3 года назад
i was dying for this kind of video thank you sooo much sir ..now i feel confident about log...you are the best sir🌸🌸
@srikantpanda7993
@srikantpanda7993 3 года назад
wow, really best tricks I have ever seen on youtube. Thanks sir
@65103715
@65103715 4 года назад
The most straight forward video on log on RU-vid. very helpful
@Rajput28522
@Rajput28522 3 года назад
Sir how to find the value of log(1.3).?
@namanjain5465
@namanjain5465 3 года назад
Sir how we find the value of log(462)? Please 🙏 reply please
@omkardatkhile8330
@omkardatkhile8330 3 года назад
I hope it will be helpful for you... 😊😊
@nandan1634
@nandan1634 2 года назад
4.62 x 10^2 do it in that way
@ameypatil346
@ameypatil346 3 года назад
Best on this planet to explain logarithmic
@Zoey31125
@Zoey31125 4 года назад
Only 1 sentence 4 u sir " U R THE BEST 😊 "
@kushmalik261
@kushmalik261 3 года назад
Thank you sir , school k level p ye sikhaya nhi jata but i am preparing for neet so thank you so much very nice explanation
@user-gu9qh9vc3b
@user-gu9qh9vc3b 3 года назад
Supremely helpful to me and I hope to everyone else who has watched this!! Thank you so much sir!!!!!
@amartyadandapat9366
@amartyadandapat9366 3 года назад
yeah it's truly the best and most accurate log trick video on RU-vid
@Minali..
@Minali.. 3 года назад
Thankyou so much sir 🙏मैने यूट्यूब पर बहुत से वीडियो देखे लेकिन आखिरकार मैं सही वीडियो पर आ गया और log nikalna seekh गया। 🙏🙏
@reenaverma9723
@reenaverma9723 3 года назад
Sir log 8 toh 4*2 bhi ho sakta h na Like 0.30+0.60= 0.90
@pallaviroy663
@pallaviroy663 5 лет назад
Thank you so much sir. Its really helpful to me.
@BigmouthO7
@BigmouthO7 4 года назад
Thank you so much sir. From Assam
@nabanitakar6383
@nabanitakar6383 3 года назад
This is the best explanation of log antilog, thank you sir
@monikakashyap2161
@monikakashyap2161 3 года назад
Thankyou sir Is trick ki bahut jarurat thi Heartly ❤ thankyou.......🙏🙏
@alkayadav9868
@alkayadav9868 4 года назад
Thank you so much for this amazing method...helped a lot.
@leysh-leysh
@leysh-leysh 3 года назад
Literally the best explanation of this topic,Kaash aap hamare subject teacher hote 11th 12th aasan hojata❤️😭🙏🙏🙏
@shrutigupta1786
@shrutigupta1786 3 года назад
Amazing trick after watching so much videos on RU-vid best video on this topic 😊👍🏻
@likhithgowda7561
@likhithgowda7561 3 года назад
Superbb Tricks of All time ⌚ !!
@gayatrirajan9929
@gayatrirajan9929 4 года назад
thank u so much sir...i was never able to clear this doubt, but you made it simple
@omprakashsharma2415
@omprakashsharma2415 3 года назад
Thank you so much, sir. It's the best and easiest method.
@diycreativitybynavi1320
@diycreativitybynavi1320 5 лет назад
Thank you so much sir It's really helpful to me coz im a medical student I am very thankful to you
@user-gu9qh9vc3b
@user-gu9qh9vc3b 3 года назад
Thank you so much sir! This video is of great help.😊
@pratyush2704
@pratyush2704 5 лет назад
Thank-you so much
@Spatanszz
@Spatanszz 3 года назад
Sir fantastic explanation..but i have 1 more doubt ...how to calculate antilog of -0.6425
@factswallah2724
@factswallah2724 4 года назад
How can we calculate value of log1.176
@dvsharathkumar8249
@dvsharathkumar8249 2 года назад
Sir how to find tan inverse 1/3,tan inverse3/2 without log
@mrrosset4669
@mrrosset4669 5 лет назад
Very effective technique thanks sir
@Study_together_28
@Study_together_28 3 года назад
Tell me value of log1.24
@harshraj25090
@harshraj25090 2 года назад
Such a great explanation of log for every Neet Aspirant 💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖💖
@vivekgajare5049
@vivekgajare5049 5 лет назад
so excellent...no more word than this !
@mamtaneersharma
@mamtaneersharma 5 лет назад
Thank u soo much sir...Aim4aiims pls keep updating such videos often
@asamreet6367
@asamreet6367 3 года назад
Sir aankho mein paani aa gya sch mein🙏
@neelampatidar3694
@neelampatidar3694 3 года назад
Never knew that log and antilog is that easy Thank you sir
@sanjaygoyal8083
@sanjaygoyal8083 2 года назад
Thank you sir This is what I needed Again thanks a lot!
@dhruvsingh6650
@dhruvsingh6650 4 года назад
Thank you so much sir!! Couldn't find an easier method...
@SonamSharma-xf6jw
@SonamSharma-xf6jw 2 года назад
sir please tell how to found the value of 0.3862
@simran5897
@simran5897 3 года назад
Amazing trick sir ..thanq so much
@sanchitamukherjee8127
@sanchitamukherjee8127 6 месяцев назад
You are the best teacher on YT for antilog and Log..Thank you soo much sir...❤
@vijayagurudas7374
@vijayagurudas7374 3 года назад
Very beautiful teaching sir. Loved the video. Helpful in competitive exams . Thank you sir🤩☺😊
@encyclopedia1552
@encyclopedia1552 3 года назад
At 8:52 for calculating log 6.7 we have the value of log5=0.7 then why have u taken log6 and log7 difference? Pls reply sir...
@staaaaaa7080
@staaaaaa7080 2 года назад
6.7 is between 6 and 7,that's why sir has taken log6 and log7
@radhikaagrawal8706
@radhikaagrawal8706 4 года назад
Sir how to find the log of negative numbers and log of numbers between 0 and 1 , such as 0.345 etc, by this method
@Anonymous-l5x
@Anonymous-l5x 4 года назад
Then here we have just skip the step of writing integer in the power of 10 . And find antilog of 0.345 That's between 2 and 2.5 so almost 2.4
@yusufdadkhah7561
@yusufdadkhah7561 3 года назад
12:31 the anti log will be explained, this video has english and either Italian in it with it being with a odd accent or Japanese from what i can tell..
@vivekYadav-yw2yn
@vivekYadav-yw2yn 3 года назад
This is the best video ever in you tube 👈👈👈👈👈👈👈👈🔥🔥🔥🔥🔥🔥🔥
@kanhaiyanautiyal7575
@kanhaiyanautiyal7575 5 лет назад
Thankuuuu sir your method of teaching is so sweet ✌️✌️
@yuvrajsinghf57
@yuvrajsinghf57 3 года назад
i dont know how thank it is much useful greatttttttttttttttttttttt
@surekhabhavikatti1477
@surekhabhavikatti1477 4 года назад
How to calculate Log o.132 value without logtable sir
@mahikiran6760
@mahikiran6760 4 года назад
Sir if we want to know the log of 12.6 then how to calculate it? We dont the log 12 value right
@vidhyasingh7260
@vidhyasingh7260 3 года назад
Very good explanation Thanks sir
@tulsimehta5738
@tulsimehta5738 5 лет назад
whatttay a method, no words. amazingggggggggg
@anshikatyagi2165
@anshikatyagi2165 3 года назад
Thnku very much sir you explain very well👍
@snayakumari2071
@snayakumari2071 3 года назад
Thank you so much sir l really need this for chemistry
@Yogendraprasad1
@Yogendraprasad1 3 года назад
This is the best explanation sir👍👍🙏
@MindYourInfo
@MindYourInfo 3 года назад
Take 13 times root subtract 1 multiply by 3558 and get your log answer
@POPPPPPOOODECWEVWR
@POPPPPPOOODECWEVWR 3 года назад
Sir am not a maths student . My stream is PCB-IP . For small numbers we can do this but for big numbers I don’t know how to do this trick . Please help me sir am having chem revision and I don’t know how to solve big numbers .
@sar_bitrate
@sar_bitrate 4 года назад
Thank uu so much sir..this technique is really too good and I am getting benifits using this..calculations regarding log and antilog hv also become easy..thank u soo much😇
@Poregamba
@Poregamba 2 года назад
I never ever thought that this type of superb vids existed🔥I want to thank you sir
@SaurabhGupta-ru4cn
@SaurabhGupta-ru4cn 3 года назад
This is best video , I have found on youtube, to find log and antilog without using log table. Thanks a lot sir
@VinodKumar-cx4is
@VinodKumar-cx4is 3 года назад
I wanted to know to find log and antilog with table value but now there is no need of table. Thank you sir. Your way of teaching & your explanation level is on ∞(infinity).👏🏻👏🏻👏🏻
@fdritupatel275
@fdritupatel275 2 года назад
Wow sir really helpful thankuu sir 🤗🤗😍😍
@SandhyaSingh-kp5sl
@SandhyaSingh-kp5sl 3 года назад
Thankyou very very much sir .🙏🙏🙏
@Biker_gsp
@Biker_gsp 3 года назад
Excellently done 😍
@biomentors5130
@biomentors5130 3 года назад
Best lecture on RU-vid for logrithm... Honest, watched approx 12 videos on it. But this was the father of every single video... Thank u sir a lot. Please keep uploading..
@dipalipatil8885
@dipalipatil8885 3 года назад
You gave very nice explanation sir. Thanks a lot for clearing my doubts. It is very good 👍👍👍
@vinaychaudhary4324
@vinaychaudhary4324 4 года назад
Good energy sir .. :) For my English preparation I must watch Vidya Guru sessions as well. I learnt so many English topics and vocabs from their videos.
@bintehawa6963
@bintehawa6963 3 года назад
How to calculate log of numbers less than zero?
@choudharyytgaming3776
@choudharyytgaming3776 4 года назад
Thank you so much sir for putting your great effort s. It really helped me a lot ☺☺😊☺😊
@chrrchrry7431
@chrrchrry7431 4 года назад
thank you sir the lecture helped me alot and it was really easily explained by you:)
@tanvipednekar5676
@tanvipednekar5676 4 года назад
That was really helpful....not only for me but each one watching this....i have sent it to all my friends. .. thank you very much sir ❤️
@Panda-wv2xj
@Panda-wv2xj 4 года назад
Heyy thank you Tanavi for sharing 👍
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