29:54 cos c = 7/25 31:48 some people have curly black hair turns brown 40:00 Sin θ- 5/13 Cos θ- 12/13 Tan θ- 5/12 Cosec θ-13/5 Sec θ-13/12/ Cot θ-12/5 50:36 (ii) ans 0
1:53:18 sir this question can also be done by RHS- Rationalise it Apply identify at denominator Cancel Take LCM =LHS Solving- Take RHS =Sin²A/1-cos²A*1+cos /1+cosA =Sin²A(1+cosA)/1-cos²A =Sin²A(1+cosA)/sin²A =1+cosA =1+1/secA =1+secA/secA =RHS Hence proved Please reply Thanks
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2:04:14 more easy way :- Just use the identity "cos2 = 1 - sin2" in both numerator n denominator than the equation becomes :- "1 - sin2 - sin2 / 1 - sin2 / 1 - cos2 - cos2 / 1 - cos2" than easily cut 1 - sin2 and 1 - cos2 n the final ans u get is = sin2 / cos2 = tan2.. XD
sir ye lecture itna acha laga ha meri jitni bhi problems thi trigonometry ki vo sari katam ho gayi aur sir aap ne jo ye chapter explain kara ha vo bohot badiya ha Thanku so much sir 😊😊