TRIGONOMETRY PROBLEM || How to find x from the given equation? 

Ok nice 👍 solution

It will be sinx instead of six.please do the needful.

(First: x 0 mod Pi/2 We also notice that tan(Pi/8) = sqrt(2) - 1 and that cotan(Pi/8) = sqrt(2) +1) We have (1/tan(x)) -tan(x) = 2 or (tan(x)^2 +2.tan(x) -1 = 0 Then tan(x) = sqrt(2) - 1 or tan(x) = -(sqrt(2) +1) *If tan(x) = sqrt(2) - 1 = tan(Pi/8) then x = Pi/8 mod Pi *If tan(x) = -(sqrt(2) - 1) = -cotan(Pi/8) = -tan(Pi/2 - Pi/8) = tan(-3.Pi/8) then x = -3.Pi/8 mod Pi *We can sum up: x = Pi/8 mod Pi/2 (as -3.Pi/8 = Pi/8 - Pi/2)

Where n is a member of Z ... very important to mention too ... thank you sir ...

And degrees