Absolutely nailed it. Have my exams tomorrow and your videos are the best one I can find on youtube, in terms of quality and going straight to the point ✨
Hey ANDY, greetings from Ecuador, you just saved some my first classes. I was struggling a lot about how to introduce the important concepts of UCM. Master!!!
this guy answer my biggest doubt. why acceleration point toward the center? what is the role? why not in the same direction as the velocity? timestamp: 3:48
Hi Andy! Your level of teaching is superb! I, in all honesty, learn the most from YOU! One thing, though: I believe the answer to a_c (time stamp: 13:48), is supposed to be 5.94E-1 m/s^2, or 0.594 m/s^2, assuming all previous answers to be correct, would it not? I calculated it twice, once on my calculator, and once again on Desmos, and both gave me the answer of 0.593609625668. Would you wanna quickly double check? Other than that super minor thing, I cannot thank you enough for posting these lessons for all of us to learn from. You are single-handedly getting us through our physics classes. Best, Rina
Your video is so great. I am in the middle of my May Physics Sl exam. I am sad for finding your channel late but also happy for finding it before my final exam. You explain it so well (much better than my teacher). I am pretty sure all your student get a level 7. Just wonder do you have some IA topic recommandation material that could be shared if you still have it (I know you have left teaching). Thank you for the great content.
My advice for the IA: 1: A good IA is often a middle school-level experiment with high school-level analysis. You don't need to do something crazy, just a simple experiment with a clear independent and dependent variable and a pattern that's either linear or that you can linearize. 2: It's often helpful to look through the IB physics equations and find one that has two variables that you can test. As a very simple example, you could look at F = ma and measure how the acceleration changes when the same force is applied to different masses and rearrange the equation to be a = F(1/m) where a is the dependent and m is the independent variable. Working backwards like this from an equation to an experiment can make it easier to find something you can linearize and analyze in the data analysis section.
@@AndyMasley Thank you so much for your helpful suggestion. I have another quick question, who will mark our IA? I have heard two statement where one says that the teacher marks your IA and one or two IA of your class will be sent to IB to be reviewed and they will decide to increase/decrease the mark of the IA marked by your teacher. And another one states that the teacher only gives you the predicted mark, the IB will review and gives you the final mark. The reason I asked it is because our teacher clearly tells us if we choose a SL topic, is it at most about level 5 and he always suggest us to choose hl topic ot outside the syllabus of IB, so I am concerned if he will be the person to give us the final mark for IA. Thank you very much!
I have a very simple but question. Why doesnt the object collapse into the point. Since the centripetal force is an acceleration is increasing with time it should get to a point where its high enough to pull the object towards its centre. For example: The electron in an atom if not for its stationary state it should be pulled towards the nucleus since the proton and nucleus attract but what keeps it moving in a circular path is the fact that they have fixed energy called stationary States so they can't lose energy. But objects in the real world dont have fixed energy level so what keeps them in circular path? Another example is that if we change the mechanics occurring on the body interms of force, The centripetal force will be the F=m×a but converting the objects tangential velocity into force its F=0 since it has no acceleration.Resolving the 2 forces the object is supposed to move towards the center so why does it still move circular
Great video, but I have a question regarding the Example Problem 1! The formula booklet stated that a = v^2/r = (4 x π^2 x r)/T^2, and in the video you used v^2/r to get a = 4.641. But technically, in the given variables, you already have r and T, so would it not be easier if you just substitute everything inside (4 x π^2 x r)/T^2? That is what I did, however I ended up having a = 4.626 instead. Could you help me verify what went wrong? Because essentially they should be giving the same answer.
You're correct that those formulas are equivalent to each other. Ultimately physics has many formulas that can be rewritten based on convenience. F = ma could also be F = m(Vf -Vi/t) if the variables called for it. Our answers are so close that it's possible that I just rounded incorrectly!
I'm a little confused in example 2, isn't the earth's orbit around the sun not in uniform motion? (Kepler's law) orbit's shape is an ellipse, not a perfect circle.
Correct! It's actually an almost-perfect circle, the ellipse is usually exaggerated in diagrams, but it's technically not uniform circular motion. I find it has enough of the same properties as uniform circular motion (centripetal force and tangential velocity) that it's a useful example to explain UCM, but it's technically not perfectly uniform.
Correct me if im wrong, but when calculating Vt in the last example problem, the answer is actually 2.98x10^4, i kept getting the wrong final answer with 10^-5!!
Hi Andy, thanks for all your efforts in helping us all. I just had a small doubt for the second example problem... By using the formula I was getting 2 π x 149,600,000 x 10^3/ 365 x 24 x 60 x 60. Which was giving me the answer of 29,806 m/s. However you got the answer of 2.98 x 10^5 which is 298,000 m/s. I just wanted to ask if I went wrong in the calculations anywhere or was the displayed answer a typo? Thanks again.
We need to investigate adding multiple rings aounrd the first ring and using smaller and bigger balls. In the rings to change the force to fully understand how the forces are changing
Yeah usually we assume the net force is constant. If the net force changes but the radius and mass stay the same, that implies that the velocity changed, so the circular motion is no longer uniform (at one speed).
sorry I only have a question that why delta 0 = 2.pi ( 8:58) ? and thank you so much, I have learned this lesson for at least 15 times ( included learning from my teacher and internet ) and I still don't understand till I find yours. Its just too easy to understand, and the way you put all of the base-knowledge in just 14:01 video is just so amazing, it really helps me a lot. I have subscribed your channel after only 5 minutes watching yours, and hope that you will make more great video, especially 10 grade physics cause I'm at grade 10 now ^^ hope you will answer my question soon. have a nice day !
So happy it's helpful! Delta theta is 2 pi because that's how many radians one complete circle is. If you need help reviewing radians use this: www.khanacademy.org/math/algebra2/x2ec2f6f830c9fb89:trig/x2ec2f6f830c9fb89:radians/e/degrees_to_radians
for example problem 2, the velocity should be 2.98 * 10^4 not 10^5 when you calculate it, and even for the acceleration, 5.9 * 10^-3 is yielded when we use 2.98 * 10^-4
It's a poorly named term that the IB uses, tangential speed would make more sense! You're exactly right and the IB is just a little lazy with this variable
I need help :( so I have a problem " a 2.0 kg object is attached to a 1.5m long string and swung in a horizontal circle at a constant speed using a centripetal force of 192N. What is the speed of the object?" I'm very confused I looked up vids but can't find one for my scenario:(
