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Using a phone accelerometer to create position-time data during a take off 

Dot Physics
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I recorded the acceleration during take off in an airliner using PhyPhox (phyphox.org/). From that, I create velocity vs. time and position vs. time graphs.
Finally, I attempted to animate the motion of the plane during take off - but it didn't exactly work out perfectly.
Still, I got to practice importing from excel to python, so that was nice.

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30 сен 2024

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Комментарии : 22   
@the_old_young_man
@the_old_young_man 2 месяца назад
Hello. Do you have takeoff.xls available? Thank you very much
@hardikharpal
@hardikharpal Год назад
Can I get those sensor data in CSV/EXCEL
@umutg.8383
@umutg.8383 6 месяцев назад
Great stuff! Around 21:13, regarding y component, I think it would be zero IF you held your phone exactly pointed towards the tip of the plane (and exactly level). Since it is not probably exact, all dimensions are slightly intermingled. i.e.: y is not exactly forward-backward, z is not exactly up-down. If you do arctan(ax/ay) which looks like arctan(1/4) from your velocity graph, that give 14. So your phone was perhaps 14 degrees off of the nose of the plane.
@anonymousguy438
@anonymousguy438 Месяц назад
Integrating data collected from a phones accelerometer over more than 2 seconds is naive ... You would never get anywhere closer to correct estimates ... Thats why there is GPS, Barometer which can rectify the calculation errors occuring over larger measurements.
@MuhammadAli-lg5kz
@MuhammadAli-lg5kz 2 года назад
Please don't stop making vidoes and please upload vidoes on different topics of mathematics as well
@elansmith9291
@elansmith9291 2 года назад
Your passion for physics is great man 👏
@hackenshaw
@hackenshaw Год назад
I came for the equations. Thanks
@mariomuysensual
@mariomuysensual 2 года назад
Thanks doctor, as always I learnt something new!!
@gfarj
@gfarj 2 года назад
Great stuff
@KommandorKeen
@KommandorKeen Год назад
surely you don't mutliply each accelleration by dt but multiply the mean eacceleration (between two steps) by dt?
@irfanullah8474
@irfanullah8474 2 года назад
Really good job. You don't need to close the Jupyter just restart the kernel and this will do the trick.
@elizabethmeghana9614
@elizabethmeghana9614 Год назад
Your doing an excellent job!
@DotPhysics
@DotPhysics Год назад
Thank you!
@kevincardenas6629
@kevincardenas6629 2 года назад
So how is it that a phone is able to get the data? I mean the acceleration is measured with respect to ground? How does the phone knows that? ;'p I’m kind of confused
@DotPhysics
@DotPhysics 2 года назад
There is a tiny accelerometer in the phone - think of it like a tiny mass supported by springs. When the phone accelerates, these springs get compressed. By measuring the compression of the springs, you get the acceleration. I'm not sure if that's the answer to the question you were asking.
@cuteko9123
@cuteko9123 2 года назад
Sir can I ask how can I calculate the electric potential due to point charges but r=0?
@DotPhysics
@DotPhysics 2 года назад
If by "r = 0" you mean the distance from the point charge to the location where you want to find the potential (with respect to infinity) - it would be also infinity.
@eraydurakk
@eraydurakk Год назад
Double integration of acceleration to measure distance is not practical and accurate because of the integration error accumulating and causing the measurements to drift from reality. It may work for a few seconds if the sensor is calibrated perfectly. In this case its not.
@good6894
@good6894 Год назад
Ok. How do you suggest this should be done then? I'm quite interested to hear a better way.
@eraydurakk
@eraydurakk Год назад
@@good6894 it has to be aided by some other sensor eg. GNSS to prevent drift. This way u can trust accelerometer in short periode and GNSS long periode. Simply search for complementary filter.
@anonymousguy438
@anonymousguy438 Месяц назад
👍 agreed
@AndyHoladay
@AndyHoladay 2 года назад
This is a cool use of PhyPhox! I wonder if it's a safe assumption that dt is constant. Any chance you could share the data?
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