Question: For the Quadratic and Cubic functions, what is the value you're plugging in to get the value of 1 for N1 and 1 for N2 and so on? Edit: Answer: To find the answer, set each equation =1 and solve for the variable. For Quadratic, the values are -1 at node 1, 0 at node 2, and 1 at node 3. For Cubic, the values are -1 at node 1, -1/3 at node 2, 1/3 at node 2, and 1 at node 4. This was so helpful. Both FEM textbooks I have, Seshu and Reddy were impossible to understand on this topic. Thank you so much for providing clarity.
FEM formulation of Cantilever beam can not be done with lagrangian interpolatiob function. So minimum element matrix size would be 4x4 using hermation interpolation function . Use bar instead of beam example at the beginning
Hi, thanks for the video. I have one question, please. In the example when we used single element with 2, 3 or 4 nodes(0:45), will the final, u2 deflection be an accurate number and the same for all examples (2 nodes, 3 nodes and 4 nodes)? So the only errors are the ones in between the edge nodes because we are using an approximation? Thanks
