Are you kidding me right now? This is awesome! I am a young teenage math fanatic and absolutely love working with numbers, but unfortunately, I still need someone to give me the knowledge, and you sir, taught me what my math teacher couldn't. Earned a like and sub.
Don’t ever ever comment but hope you see this. This video was sooo helpful and I loved being able to pause to try work out for myself the lessons and then continue to see if I was correct
This was super super helpful! If you would be willing to provide a pdf of the worksheet that would be even more helpful, I'm trying to write it by hand!
Dude, ive never seen these venn diagrams before but had to prepare for an interview and went on RU-vid to see what theyre about, please believe every other video did nothing but confuse where yours bought clarity
There was a question that I would like to respond to, but I am unable to find the comment or even to see the whole comment. I'm not sure what the issue is. The question was about shading (A intersection B) union C. When you see a union between two sets you shade both of them independently. So in this case we would shade (A intersection B) then we would shade C. The result would be a shaded shape that looks like a circle with a little pointed extension on one side. So again, when you are working with union, shade both sets.
@@arwengrunwald4160 we need to point out that there isn't really a specified hierarchy to the set operations, so usually we would use parentheses to indicate what operation we want first. In the case that you have described, I would assume you want the intersection first and then you want the union of that intersection with C. So A
I have learned Venn diagram in my 10th Standard, that’s 7 years ago. A few days ago, one of my neighbours has asked me to gave her a tution on Math, his standard 11 btw. Set is the first chapter. As we learn we come across Venn Diagram. It is at this moment that I realised my concept on Venn diagram was not clear.... You helped a lot. Thank you very much..
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FINALLY I FOUND IT!!!! This kind of explanation is exactly what I have been looking for for a long time!!! I have looked trough numerous PDF's and books and this video nails it. Just tells me how it is, with out some bullshit question which I can't solve because everything was explained to me in a text and not with Venn Diagram examples. Thank you Jeremy for this!
I was stuck for hours and decided to look this up on RU-vid and thankfully I came across your video. The way you explained this just clicked in my brain and I was finally able to make sense of intersections and unions. Thank you.
I think I see what you are doing here. If it had been the case that the eleven liked fast pizza and giant burger, then to get that subset that is just fast pizza and giant burger and not chicken and more you would subtract the overlap of all three from the overlap of the two. Now if that was the question it wouldn't make sense here because you would be subtracting 13 from the 11. In this case we simply write 11 in that space because the description in that bullet point is clear enough to only be referring to the set of people who like both fast pizza and gigantic burger but not chicken and more. Typically you do the subtraction you are referring to if the description is vague enough to encompass two or more of the sets that we see in the Venn Diagram. I hope that makes sense.
The question is asking us to shade in A together with not B. In this case we pretend like C isn't even there. That remaining bit of C is actually in B. It is not shaded in, because we want not B. That's really all there is to it. Notice that the only thing not shaded in is B itself.
Could you please explain this sum? Students in their last year at a school must study at least one of the three main sciences: Biology, Chemistry and Physics. There are 180 students in the last year, of whom 84 study Biology and Chemistry only, 72 study Chemistry and Physics only and 81 study Biology and Physics only. 22 pupils study only Biology, 21 study only Chemistry and 20 study only Physics. Use a Venn diagram to work out how many students study all three sciences
I hope I can help. When looking at the question the way you have written it I am just curious if there has been a mistake. Did you mean to say or when each subject was paired with another one? The words 'and' and 'only' are forcing me to put large numbers in specific regions that then cause the sum to go well beyond 180, but if the word is supposed to be 'or' the numbers work out okay with no one studying all three and six studying none of those courses. Please let me know, and then I'll share what I have.
@@JeremyKlassenThePiMan Thank you for fast reply. Its a question from Cambridge IGCSE textbook. Hope the question is correct. Me also felt the same. Adding i got 300 which is greater than 180. Finally I got the answer as 60. But im not sure.
@@sneharajan8271 I can understand your confusion with it. The word only is hard to work around. I will have another look at it without the word only in where the courses are doubled up
I think if you read it as bio or chem only is 84, Chem or phys only is 72, bio or phys only is 81 then it makes sense. I think the answer you get for all three is then 6. So what i see is that b and c but not p is 41. Then c and p but not B is 31, and finally b and p but not c is 39. Adding all these up gives me 174 which leaves 6 in the center
great explanation but the one part that i got confused was A intersecting (B union C). B and C are unions so why is it that the whole of B and C have not been shaded?
So because the B union C is in brackets we do that first, and that does shade those entirely. Then we have A intersection the B union C and this means that we now shade the region that is common to set A and the union of B and C. So basically, since we only have the three sets we shade the regions where A overlaps with anything else.. I hope that makes sense.
Typically you would subtract the middle term from the values where two sets overlap. Then you would subtract these values from the size of A B or C to get the number of objects that only sit in one set.
Wow ! Really amazing content with plenty of different type of problems. You did a great job sir instead of just showing a simple proof of boolean algebra. Thanks Alot xoxo
