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Visual Group Theory, Lecture 5.6: The Sylow theorems 

Professor Macauley
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5 окт 2024

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Комментарии : 35   
@chilling00000
@chilling00000 2 года назад
This is by far the best lecture on Sylow theorems one can find on youtube.
@yusufnzm
@yusufnzm 9 месяцев назад
This video is by far the clearest group theory lecture I watched. It was so good that some ideas really clicked with me for the first time.
@saquibmohammad2860
@saquibmohammad2860 4 года назад
Thank you so much professor. I was stuck on this for last three days
@letslearnsomething0001
@letslearnsomething0001 4 года назад
Army
@jtpmath
@jtpmath 8 месяцев назад
I was stuck for the last 7 years. Ha!
@hritizgogoi3739
@hritizgogoi3739 3 года назад
Thank you Professor for these amazing lectures
@zhuler
@zhuler 2 месяца назад
in 31:05 it's easy to prove that conjugation of a p-subgroup is also a p-subgroup, so the only orbit is not bigger than np but equal to np
@anmolbhanot5350
@anmolbhanot5350 7 лет назад
Thankyou so much for these lectures !!! The way you teach with intuition & understanding is of great help ☺
@余淼-e8b
@余淼-e8b 3 года назад
Amazing videos. Thank you, professor.
@maru3295
@maru3295 3 года назад
Thank you very much sir! I am currently reviewing about Sylow Theorems and this video helped a lot.
@BSplitt
@BSplitt 7 лет назад
I believe there's a small notational error at 25:06. I think it should be [G:H] instead of [G,H].
@AxiomTutor
@AxiomTutor 6 лет назад
Good pictures, clear explanation--very nicely done.
@popoubc
@popoubc Год назад
Thank you for such an amazing presentation of this powerful result!
@Democritus477
@Democritus477 Год назад
Thanks for the very helpful videos. I wanted to let you know that Sylow's name is not pronounced See-low, it is pronounced similarly to Sue-loav (as in loaves).
@hinyikiwilemithi4855
@hinyikiwilemithi4855 3 года назад
Thank you so much. This video was very helpful. I wish you were my lecturer
@kyleyan5974
@kyleyan5974 Год назад
oh my gosh ,why you so great ! I love you!!!You are the one who teach it really easy.I can't agree more!🥳🥳🥳
@alexandergrothendieck1571
@alexandergrothendieck1571 5 лет назад
Merci beaucoup et super travail.
@samwalters3824
@samwalters3824 3 года назад
amazing
@pobodjjd
@pobodjjd 6 лет назад
Really Helpful with graphs!Thank a lot!
@santosinibiswal6853
@santosinibiswal6853 7 лет назад
It's really very helpful sir...thank you
@tianqilong8366
@tianqilong8366 8 месяцев назад
The best!
@truong62
@truong62 5 лет назад
Nice Sylow theorems explanation. Have we the proof of the such normalize group Ng(H) existence ?
@Jd-dw8rn
@Jd-dw8rn 7 лет назад
Thank you very much for these great videos ! Just a small remark: at 18:40, when you say "each of these subgroups contains a nested chain of p-subgroups", we did not yet prove that there is only one chain (if this is even the case) - couldn't there be a lattice of p-subgroups instead of a chain ? Although the proof only shows how to build one such subgroups, couldn't other methods yield distinct p-subgroups ?
@rasraster
@rasraster 7 лет назад
Pretty amazing stuff
@boranerol750
@boranerol750 9 месяцев назад
Hi, To be fully rigorous, wouldn't you also want to show that H' is a subgroup in your proof od the first Sylow Theorem? If this is obvious, how do you see it?
@igna02
@igna02 6 месяцев назад
H' is constructed as the preimage of under the quotient. Then use that the quotient is a group homomorphism and the preimage of a subgroup must be a subgroup.
@ourdreams823
@ourdreams823 7 лет назад
thank you
@dananifadov7261
@dananifadov7261 Год назад
hey! in 11:20 - I wanted to ask in what video do you prove that the order or the quotient group - normalizer of H mod H is a multiple of p? hanks a lot for this video!
@ProfessorMacauley
@ProfessorMacauley Год назад
The previous one, on p-groups
@fsaldan1
@fsaldan1 4 года назад
Does the reasoning behind the normality of P5 generalize? That is, if G contains a subgroup H that is not isomorphic to any other subgroup of G can we conclude that H is normal?
@ProfessorMacauley
@ProfessorMacauley 4 года назад
Yes! Because in that case, xHx^{-1} must be equal to H, for any x.
@ilusoeseconomicas2371
@ilusoeseconomicas2371 4 года назад
@@ProfessorMacauley Thanks. And also thanks for the great videos. The explanations are clear as crystal. Only a few videos about Advanced Linear Algebra? I am waiting for more. And what about Lie Groups and Representation Theory, two other very interesting topics?
@okweonahi6781
@okweonahi6781 6 лет назад
wow!, very awesome.
@leewilliam3417
@leewilliam3417 9 месяцев назад
Mmmmm❤
@wesleysuen4140
@wesleysuen4140 4 года назад
/ˈsyːlɔv/ 😎