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Von Mises 2 - Brain Waves.avi 

purdueMET
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25 окт 2024

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Комментарии : 69   
@kamraman123
@kamraman123 9 лет назад
its so easy when you explain it like that! i wish we had more lecturers like you at my uni. i would actually enjoy mech eng more
@CareBear00031
@CareBear00031 11 лет назад
This is the most helpful thing ever. I can't thank you enough! I learned more from this video than I have in any of my lectures. Thank you for being so clear and not trying to just confuse us like so many teachers do!!!!!
@Digressionify
@Digressionify 11 лет назад
2nd year Mechanical Systems student here from Canada - Your video's have been very helpful to me and a great supplement to my lectures, THANKS!
@jeophilip4353
@jeophilip4353 4 года назад
i feel so happy listening to your lectures
@skvetny
@skvetny 11 лет назад
Amazing... I was just killing myself over this issue untill i came across your video. Thank you Mark, you've made another Mech Engineering student's life more easy =]
@purdueMET
@purdueMET 11 лет назад
You are most welcome. My hobby these days is collecting hits on the RU-vid channel. If these videos are particularly helpful to you, please spread the word. I think it would be really cool to get 1 million hits on the channel.
@muchen303
@muchen303 10 лет назад
The fact here is that Tresca criterion( 85+45 > 125) predicts a yielding but Von Mises says no. Therefore Tresca is more conservative!
@Danbarnes92
@Danbarnes92 12 лет назад
this is a massive help for me doing my degree in the UK! thanks!
@naveenkumaruthamanthil3579
@naveenkumaruthamanthil3579 11 лет назад
Thank you for the interesting insight into von Mises failure criteria.
@eugenesmitsmit4781
@eugenesmitsmit4781 7 лет назад
Legend this guy!! I love him!!
@rosschambers1987
@rosschambers1987 11 лет назад
I'll do just that, I'll share with friends on my course. We're studying Aerospace Engineering at the University of Liverpool, 2nd year. Thanks again :-)
@dannycheng7819
@dannycheng7819 9 лет назад
wonderful and clear review on von mises! thanks!
@madeinindia20
@madeinindia20 4 года назад
You are the best! Thank you so much!
@attaponcharoenpon1890
@attaponcharoenpon1890 7 лет назад
Thank for sharing. I got more clearly in vonmises stress. Do you have other video like cauchy stress explanation or derivation?
@rosschambers1987
@rosschambers1987 11 лет назад
Thank you for the excellent video. There are many more which I have found very useful as well which I have not liked or commented on (just because I have forgotten to). Thanks +++
@defendermodsandtravels
@defendermodsandtravels 2 года назад
I think you have drawn the shear stresses in the negative direction. The normal convention is that a +ve stress acts on a +ve face in a +ve direction. You have used this convention for the normal stress components.
@Megan-os5qt
@Megan-os5qt 9 лет назад
thank you! you are always very helpful!
@joelklopstein106
@joelklopstein106 9 лет назад
This guy makes me want to go to Purdue. I would definitely go to his office hours.
@juamascf
@juamascf 9 лет назад
Using Tresca, would we say the element yields since |Sigma1 - Sigma2| = 130MPa which is greater than our yield strength (125MPa)?
@purdueMET
@purdueMET 11 лет назад
Wow. I'm glad the video helped.
@raj144529
@raj144529 4 года назад
Sir can I use your video for translating it to Hindi ( Regional Language of India). So that more students get's benefit.
@parkwaydriven92
@parkwaydriven92 11 лет назад
great videos! but do you have any examples on how to figure out the maximum shear stress when you only have the minimum principal stress and the failure envelope details?
@albertozanardi1
@albertozanardi1 11 лет назад
Great explanation, thanks!
@stooncol619
@stooncol619 6 лет назад
Sir thank you very much it is way clearer than before... just one question in case of pure shear what would be the approach to find von Mises stress
@Ghulumasa101
@Ghulumasa101 8 лет назад
thank you sir, you saved my life
@norestnomercy88
@norestnomercy88 10 лет назад
Thank you! That will be very useful for my exam! :D
@markmcpeake715
@markmcpeake715 10 лет назад
Hi.Quick question: I have never before come across your von Mises equation. I am more used to seeing and using the one which takes into account all 3 principal stresses. Can you point me to where the one you have used comes from please? Also, it seems that you left out the -ve sign when multiplying stress1 and stress2, but your answer is correct.I want also to thank you for all your videos which I have used extensively in my studies and have found extremely helpful and well presented. As a mature student of Open University, your input is invaluable and very welcome. Thank you.
@Bunk_Moreland
@Bunk_Moreland 10 лет назад
because we are working on a 2 dimension problem, component 3 values are zero. so if you substitude σ3 with 0 in the general von mises equation and calculate the bracket squares and add them up, you will get that equation.
@markmcpeake715
@markmcpeake715 9 лет назад
Thank you. I got a distinction in my final which Brain Waves helped me achieve.
@ladieman050893
@ladieman050893 7 лет назад
Thanks professor! Very helpful!
@mustafahlal5533
@mustafahlal5533 5 лет назад
Are you can estimate the radius(maxi shear) by use ruler and multiple the gage in scale????? Without using the law !!!
@luisahumada6081
@luisahumada6081 2 года назад
I work as a Civil Engineering, and when people consider a Von mises stress analysis, people normally consider 0,6 Fy. I believe that this conservative criterion is wrong, and we need to consider just Fy or, maybe, 0,9 Fy if we want to be a little bit conservative... Any comments about it? I'd appreciate them a lot amigos.
@kamatchikarthik8129
@kamatchikarthik8129 6 лет назад
Good explanation. Thank you
@luisconradoalcalabecerra3559
@luisconradoalcalabecerra3559 4 года назад
Great video thank you
@funtastictv9765
@funtastictv9765 10 лет назад
Thank you sir,It was a great explanation
@ashishanand2662
@ashishanand2662 11 лет назад
Nice Explanation!!
@uppalapusrinivasaraju1016
@uppalapusrinivasaraju1016 7 лет назад
One question. The obtained vonmiser stress must be within von miser oval drawn by principal stresses to say that it is safe. but here the vonmiser stress is off course closer to yield stress but not within oval shape. Is that safe?
@purdueMET
@purdueMET 11 лет назад
Thanks a bunch.
@adityamorey5662
@adityamorey5662 11 лет назад
though you didnt use the deviotoric stress tensor to come up with the criterion .. still amazingly explained .. thanks alot ..
@bertverschueren459
@bertverschueren459 4 года назад
Thank you so much!
@pavithrac6922
@pavithrac6922 10 лет назад
how do you say that maximum shear stress is zero. it is not 65MPa
@lhmissio
@lhmissio 5 лет назад
this is so good
@joseemanuelrangelescalante7375
hello , i would like to know if i can work von misses stress in 3d ?with a triaxial test?
@taseerbashir2334
@taseerbashir2334 8 лет назад
Thank you Sir you explanation is great, 5*****
@11Winfield
@11Winfield 12 лет назад
sign convention is arbitrary?? cause i get neg for my shear
@purdueMET
@purdueMET 11 лет назад
Thanks!
@mistrysun1
@mistrysun1 9 лет назад
thanks that was very helpful!
@Souliee
@Souliee 12 лет назад
Really great! Thanks! :]
@cemdemir536
@cemdemir536 10 лет назад
Many thanks :)
@Learning_for_life137
@Learning_for_life137 7 лет назад
Thank you sir
@han34han34
@han34han34 4 года назад
You are fucking AWESOME!
@Tee.NZ.07
@Tee.NZ.07 8 лет назад
Don't know why I get 95 MPa instead of 114.3 MPa..
@danpt2000
@danpt2000 7 лет назад
maybe check your Mohr 's circle
@PkBk2020
@PkBk2020 9 лет назад
Thanks alot....
@yannseillier3801
@yannseillier3801 8 лет назад
Super video ! thank you
@darrowshire11
@darrowshire11 11 лет назад
subscribed!
@yamilduran6735
@yamilduran6735 9 лет назад
thanks!
@265HITMAN265
@265HITMAN265 12 лет назад
i love you
@hasben0
@hasben0 11 лет назад
Well fucking done. thanks alot
@aadithyajeyaranjan6962
@aadithyajeyaranjan6962 10 лет назад
Isn't that shear -25 Mpa ?
@TheAusrali
@TheAusrali 10 лет назад
yeh he got it wrong but i guess it doesnt matter
@benejeneb
@benejeneb 9 лет назад
I was worried that I had it wrong. Cheers! All the rest is great though :) I can't believe he has the time, so useful!
@kristianSilva95
@kristianSilva95 7 лет назад
Yeah i spotted that at well, turns out im smarter than the lecturer
@emrage
@emrage 4 года назад
@@kristianSilva95 Yeah you all sound super smart.. It's the way he's defined his sign convention hence Shear is +ve and his graph Tau is positive up.
@gaylordrama
@gaylordrama 12 лет назад
Double like...
@samarsawant6116
@samarsawant6116 4 года назад
sigma bar= (sigmaX + sigmaY)/2, then it must be (80+40)/2= 60 MPa but you got 20MPa, everything in further calculations is ruined.
@christophermusso
@christophermusso 4 года назад
@samar sawant sigmaY is a compression load and is therefore negative. (80 + (-40))/2 = 20 MPa
@junmingchen8787
@junmingchen8787 4 года назад
thank you so much!
@johnnyodwyer7951
@johnnyodwyer7951 7 лет назад
Thank you sir!
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