Want to ACE Math Olympiad? Watch This Now!

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Want to ACE Math Olympiad? Watch This Now!
Welcome to infyGyan!
In today's video, we explore a fascinating algebraic simplification problem from Math Olympiad. If you love solving complex expressions and pushing your problem-solving skills to the limit, this is the perfect challenge for you. Join me as we work through this intricate algebra problem step-by-step. Don't forget to like, comment, and subscribe for more math challenges and solutions!
📌 Topics Covered:
Algebraic simplification
Algebraic manipulations
Problem-solving techniques
Algebraic identities
Math Olympiad problem
🔢 What You'll Learn:
Key strategies for simplifying complex expressions
Tips and tricks to approach difficult simplification problems
Step-by-step walkthrough of the solution
🧠 Challenge Yourself:
Pause the video, try to solve the problem on your own, and then watch as we break down the solution. Share your approach and answers in the comments below!
👍 Don't Forget to:
1. Like the video if you found it helpful.
2. Subscribe for more Math Olympiad problems.
3. Hit the bell icon to get notified of new uploads.
4. Join us and enhance your problem-solving skills. Can you master this simplification problem?
Additional Resources:
• Thailand Math Olympiad...
• Brazilian Math Olympia...
• An Engaging Algebra Si...
• A Nice Algebra Simplif...
• Chinese | Math Olympia...
🔔 Don't forget to subscribe and hit the bell icon to stay updated with our latest math challenges and tutorials. If you enjoy the video, please give it a thumbs up and share it with your friends!
💬 Comment below if you have any questions or if you were able to solve the problem. We love hearing from our viewers!
Thank you for watching and happy problem-solving!
#simplification #matholympiad #algebra #mathproblems #expression #problemsolving #mathematics #education #educational #mathtrick
Don't forget to like, share, and subscribe for more Mathematical content!
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Опубликовано:

10 окт 2024

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Комментарии : 7

@Fjfurufjdfjd День назад

Η σχεση που δινεται γραφεται:χ(χ+1)=36 ; χ^2+χ=36 ; χ^2+χ+36=72 ; χ^2+6^2+12χ=72+11χ ; (χ+6)^2=11χ+72 ; θετω (χ+6)=y ; y^2=11y+6 θελω Ε=y^6+(6^6)/y^6=(y^2)^3+[(6/y)^2]^3=........= [y^2+(6/y)^2]^3-3y^2×36/y^2[y^2+36/y^2] αλλα απο y^2=6+11y εχω(y-6/y)^2=121 ; y^2+(36/y^2)=121+12=133 ; (επειδη y-(6/y)=11. Αρα τελικα Ε=133^3-108×133=.......επιστρεφω

@Fjfurufjdfjd День назад

2338273 ( μεγαλο μου φαινεται)

@jasperkok8745 День назад

Would it not be a lot easier to calculate x first (using cross multiplication and the quadratic formula) and then inserting the x value in the second equation? X^2-x=36, so x^2-x-36=0 x=(1+-sqrt((1-4*1*(-36)))/2 x=(1/2+-sqrt(145))/2.