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Like the same way the heart of John's brown mother got thrilled after she rceived the messgw of his son's coming . But after seeing him she was shocked she was unable tore ignise him . His face was blown away. He could hardly stand with the help of emtal brace attached to his spinal cord . John brown breaks his mthers magainataikne hi considers wat to be somting gloeuorus . John brown exeains as soon as he gone there he comoekteley tirgotbthe lruldoe of war. Even the emenmey looked like him . And as soon as the teh relsistikn struck a huge canakn sturckbwith his fac e. Ackridng ti him soldiers are lien apwn gightinbfir saiatufying the intrsts of givg they are like an puppet in the play
Abe ch*tiye woh sphere ko touch karne ko nhi bola tha unhone. Baki thread toh touch kr he skta the aur unhone wahi kara. Khud nashe mai rehte hai aur gyan dene aajate hai chu*** log
Sahi to h There is no external torque, as the thread itself is the axis. Hence I¹w¹ = I²w² As the size of ball decreases, it's Moment of Inertia(I) decreases, and Omega (w) increases
Angular momentum conservation(Iw=constant ,when Fext=0)!!!!!!after he pulled the lower string ,the distance of the adjoining parts from COM reduced i.e. MI decreased, thus angular velocity increased in order to conserve the momentum.
@@bhaskar1157 Nahi woh galat ha, aisi nahi karte kyuki linear velocity constant nahi ha. When Net Torque = 0, Angular momentum is conserved, so when we decrease the radius, the Moment of Inertia increases thus the angular velocity decreases.
Angular Momentum Conservation L = Moment of Inertia x Angular Velocity Mass gets concentrated near centre of mass, so moment of inertia decreases hence angular velocity increases
"Conservation of angular momentum". It states that the total angular momentum of a rotating body is conserved in absence of torque(T=0). i.e., L=mvr=constant. Since the radius of the body decreased the linear velocity of the body increased.
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😊😊Sir mene jese socha tha same wahi tarika aapne apnaya or mene ye har video me notice Kiya h jese mene socha tha wese hi aapne bataya यानी same thinking 🤔🤔🙏🏻🙏🏻🙏🏻
Linear velocity is equal to angular velocity and radius multiplication.When radius decrease ,angular velocity increases when radius increases, angular velocity decrease but the linear velocity remains constant 😊 like if agree with me
Conservation of angular momentum bc the moment of inertia decreased bc the radius of the shape thats close to a hollowsphere decreased so to conserve angular momentum rotational speed should increase
Instead…the omega is increased because of angular momentum conservation as no external torque is applied to the system and IW=constant so as I(moment of inertia decreases….W (angular velocity) increases….
@@lakshmisinghal4816shi h lekin..... Torque external nhi hota puri body ka torque zero hoga because there is no perpendicular torque on system so torque of body is zero than angular momentum is conserved......
When moment of inertia decreases by pulling the string downward then to conserve law of conservation of angular momentum the angular velocity increases.Formula:I1w1=I2w2
Angular Momentum of this system will remain conserve as we haven't applied any external torque. Since Iw= constant; radius of sphere gets decrease when we pull the rope and hence I reduce and w will increase.
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L = mvr For constant Angular Momentum (L) (means no torque is applied), tangential velocity (v) is inversely proportional to the radius (r). This is why you decreased the radius which led to an increase in tangential velocity.
Well I am a 10th grader and I just passed my ninth, according to me,as the momentum is the product of velocity and mass , and we know that any two quantities that are in product so they have inverse relation p,as you decreased its size , it's velocity automatically got a rise
Conservation of angular momentum ... moment of inertia decreases when mass comes nearer to axis of rotation and for conservation of angular momentum angular velocity must be increase .i.e Iw=constant
In the first Arrangement the masses are far away from it's axis of rotation, Compared to second arrangement Due to which the moment of inertia of the system is higher in first arrangement And less in second arrangement , As it is demonstrated in the video, he gave the angular velocity to the first arrangement and then shrink the volume of the first arrangement ( So that all the masses come closer and thus the distance from the rotation of axis decreases) so that the moment of inertia decreased therefore to conserve the angular momentum( Because there is no net external torque applied during the motion), omega increased
here radius from axis of rotation decreases so moment of inertia (I) also decreases as I = 2/5mr^2 now to conserve angular momentum omega should increase itself so rotation in sphere speed up
Radius is inversely proportion to omega(w) (that is angular velocity) When you pull the rope its radius is decreased that's why the angular velocity is increased
Uska chota krne se uska moment of inertia bad jata h or inertia badne se angular velocity km hoti h angular momentum ko conserved rakhne ke liye kyuki us ball per koi ext. Torque nhi lag rh h
As we know that moment of inertia and angular speed depends upon the distribution of mass as we can see that, initially the mass was distributed far from the axis of rotation and when the distribution of mass comes near to the axis , the moment of inertia decreases and the angular speed increases this is the law of conservation of angular momentum❤ Thanks✨
external torque about its axis is zero,hence angular momentum will be conserved,initial moment of inertia jyada but omega kam,nichle string ko kichne se moment of inertia kam hoga jisse omega badha ga bcoz angular momentum is const.
MASS COMING NEAR TO THE AXIS OF ROTATION, HENCE DISTANCE OF MASSES FROM THE AXIS OF ROTATION DECREASES AND MOMENT OF INERTIA ALSO DECREASES AND AS ANGULAR MOMENTUM IS CONSTANT, NO TORQUE ACTING ON THE BODY SO ANGULAR SPEED INCREASES AND THE SPHERE ROTATES WITH GREATER SPEED.
Radius is inversely proportion to omega(w) (that is angular velocity) When you pull the rope its radius is decreased that's why the angular velocity is increased -----------IS IT COREECT----------
During the initial rotation if we reduce the size of that object from the centre of the object the speed will be increase. Reducing the size of an object takes less energy to rotate and then rotate with increased speed. I think so.
Angular velocitu is inversly propotional to the radius.... When radius is decrease by pulling the string below that toy the angular velocity increases becuse radius is decreased👍
angular momentum conservation, Iw = constant, on contraction, masses gathers closer to axis of rotation so I decreases so w increases meaning angular speed increases
Angular momentum is equal to moment of inertia into angular velocity due conservation since the moment of inertia decreases angular velocity increases!!
if mass and angular momentum are constant, than a decrease in radius requires an increase in angular velocity, while the speed of the mass remains constant same speed in a smaller circler means a faster rate of rotation
here angular momentum conservation occur L= IW hota he agar humne rope ko kicha islye masses pass aagaye jisse moment of inertia decrease ho gaya aur angular speed increase ho gai
According to Law of Angular momentum conservation IW =constant I=mr² Sir n mass decrease kiya to overall I decrease hoga than angular speed will be increase hogi qki angular momentum is conserved
