Nice one again! I really like the 2nd principle. Should also work with a complete blue deck and an extra red backed sticky card on top (with the matching blue card next). Lets you predict any card named by the audience. And if, by chance 1 in 52, the red backed card should be named, you just reveal that this is the only card in red and blue in the deck. (So, Queen of Hearts or Ace of Spades would be a good choice for the red card...) I guess it could also be done with rough backs (and rough front of red card), if one wants to avoid the sticky tape. But then, you can't throw the doubled card around as you did, of course.
Sorry, but I don’t see how you can guarantee that the random moves around the cards will guarantee the paper will land on one of those two positions. Am I missing something? Doesn’t work in my experiments.
try this.. If the spectator has ANY ODD number then by starting on the top poisition will always cause them to end up on either of the two centre cards. If the number is an EVEN number then you must start the counter on either of the centre cards, where by they will end up on any of the cards EXCEPT the two centre cards. Remember the spectator can move back and forth, left or right, but NOT diagonal. Hope that helps. Let me know if not. Cheers
@@eminentdirectors1491 Odd numbers start anywhere but the 2 middle club cards as pointed out in video. if even number, start on either of the 2 club cards. They move up, down, left, right, not diagonal.
