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What happens at infinity? - The Cantor set 

Zach Star
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7 июн 2024

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Комментарии : 804   
@zachstar
@zachstar 3 года назад
This one came out much longer than expected as it was a more technical video, because of that I had to omit some things I'm going to include in this comment. 1) Since the cantor set is uncountable, that means there are points in it that are NOT endpoints in any of the C_n sets (I brought this up but never acknowledged the answer). In fact, the set being uncountable means there must be irrational numbers in the set since rational numbers are countable. 2) One example of a point in the cantor set which is not an endpoint is 1/4, if you put a dot at 1/4 and move it down, it'll always be in the next C_n set but it will never be an endpoint. 3) 1/4 is known to be in the set because it has a ternary (base 3) form that does not include the number 1 (1/4 = .020202020.... in base 3). I never discussed this in the video but the cantor set consists ONLY of numbers in [0,1] that can be written in base 3 form, without the number 1. (Note: Base 2 = binary, base 3 = ternary). 4) There's a cool property about the cantor set that can be proved graphically, and if you want a challenge try to prove it. Property: For ANY number between 0 and 2 (call it p), there exists two numbers in the cantor set (call them a and b), such that a+b=p. 5) Sorry for anything that wasn't to scale, told the animator to make everything as proportional as possible but he needed room to write everything
@TheSummerLab1
@TheSummerLab1 3 года назад
Video published 9 minutes ago, comment a week ago :V
@elizathegamer413
@elizathegamer413 3 года назад
Facinating video, I feel like you're my math teacher! Though perhaps more interesting
@elizathegamer413
@elizathegamer413 3 года назад
@@TheSummerLab1 yeah, RU-vidrs can publish and then private a video but they can comment on it
@worldwarwitt2760
@worldwarwitt2760 3 года назад
Huffman compression!
@joeyhardin5903
@joeyhardin5903 3 года назад
what is the value of that LRLRLRLRLRLRLRLRLRLRLRLRLRLRLRLRLRLR... number?
@RC32Smiths01
@RC32Smiths01 3 года назад
This is what makes science and math simply unforgettable for me. To learn about things like this is magnificent and surreal. Amazing!
@mattmahoney8659
@mattmahoney8659 3 года назад
Just major in Math
@donandremikhaelibarra6421
@donandremikhaelibarra6421 3 года назад
There are aleph null numbers between [0,1]
@l1mbo69
@l1mbo69 3 года назад
@@mattmahoney8659if I was smarter/ had done more math when I was younger I would
@mattmahoney8659
@mattmahoney8659 3 года назад
@@l1mbo69 No time like the present. One of the neat and unique things about Math is that it ages well, no single idea ever becomes obsolete as new ideas emerge unlike with Technology, medicine, and to some extent Physics and Chemistry. That's because Math eventually became based on proof and statements of truth which remain true forever. ( if proven correctly ) That's a long way of saying you can always lean it. There is nothing uniquely special about majoring in it in college anymore. To learn what Math majors know you need 2.5 things. (1) Source material like this video, (2) Practice ( old textbooks, (maybe) brilliant.org, (maybe) myopenmath courses (if that's still around) and (2.5) patience because learning math can be hard at times in a way like a foreign language or a sport can be and requires one to push through its hard parts. In all likelihood, if your like me, you probably dont have the time/energy/resources to teach yourself all the math you wish you knew but never got to learn. But I wanted to put out there that it's not an impossible thing just in case anyone wanted to try. It's a lot easier to try something when you know its possible.
@l1mbo69
@l1mbo69 3 года назад
@@mattmahoney8659 thanks for the to the point structure. But I have tried, and it's not that I am terrible but I am far from good enough to justify majoring in it. I'm not going to be completely leaving it behind, though. I have decided to get a degree in Physics (and I'll try to minor in mathematics). I seem to be much better at it (judging from how I fare in international olympiads) and like it almost as much as maths. I think the issue is that Mathematics, other than logic, also involved a lot of creativity. What is it that clicks in your brain, exactly? To me it seems to be really mysterious. All the progress I have made in maths has only been by practicing similar problems till I know the tricks used. Basically I just become familiar with that particular topic and I don't feel like I am making any progress with my core mathematical intuition. Does that make sense?
@thetntsheep4075
@thetntsheep4075 3 года назад
God: would you like to have length 0 or be uncountably infinite Cantor Set: *yes*
@Adomas_B
@Adomas_B 3 года назад
Teacher: this exam will be straight forward. The exam:
@Ennar
@Ennar 3 года назад
... is straight forward?
@sebastianp4023
@sebastianp4023 3 года назад
... but with the third and every third of every subset removed.
@pinchus2714
@pinchus2714 3 года назад
@@sebastianp4023 you mean every third of the exam is removed. If every third question was removed and there were n questions, what would the last question left be?
@aweeb7029
@aweeb7029 3 года назад
It's "straight forward" upto infinity, so the exam never ends...
@hybmnzz2658
@hybmnzz2658 3 года назад
Why is this lame joke on every popular math video. It's especially cringe when the math presented is not even about a problem but more of a lecture.
@samuelthecamel
@samuelthecamel 3 года назад
Fun fact: LRLRLRLR... = 1/4 so it's not just numbers that have a denominator that is a power of 3
@nerdiconium1365
@nerdiconium1365 3 года назад
Also, 4/9 is n the first middle third, so it’s not in their either. For people looking for a formal explanation, the set contains all number from [0,1] where the ternary (base 3) expansion has no ternary digit 1, except at the last decimal place, if it terminates. PS, sorry if you didn’t get what I said, look it up if you really wanna know.
@piezomofo
@piezomofo 3 года назад
L, after the first iteration is the segment between 0 and 1/3, inclusive. In the second iteration, LL would be the segment between 0 and 1/9, inclusive, and LR would be 2/9 to 1/3, inclusive. 1/4 falls on the segment between LL and LR which would be between 1/9 and 2/9, non-inclusive, and that section is removed in just the second iteration. 1/4 is NOT part of the Cantor set. This video has a couple mistakes, but this is not one of them. All numbers in the cantor set have a denominator that is divisible by 3, with the only two exceptions being 0 and 1. I'm open to hearing an argument that says I'm wrong and the op is right, but I'd need to see a proof. Edit: I think the fault in your logic relies on L and R being equal to 1/2 each. Both L and R are in fact representative of 1/3 each, and a silent C is the missing variable that has been removed from the set in the middle of each L and R. Edit #2: I was wrong. Read below if you want to know why. I'm editing my comment to note that I was wrong, but leaving it up as-is besides this note, in case others may have been mistaken, like me.
@samuelthecamel
@samuelthecamel 3 года назад
@@piezomofo I'm sorry to call you out, but when you said that 1/4 falls in between 1/9 and 2/9 it actually falls in between 2/9 and 3/9. 1/9 = 0.11111... 2/9 = 0.22222... 1/4 = 0.25 3/9 = 0.33333... Also if you are curious about how I found that 1/4 is in the set, it has to do with this infinite sum: 1/3 - 1/9 + 1/27 - 1/81 ... = 1/4
@piezomofo
@piezomofo 3 года назад
@@samuelthecamel no, by all means, you're right to call me out. I wasn't doing the math and was quick to throw out a reply. You're right about 1/4 being between 2/9 and 3/9, and I was wrong saying it was removed at that point. Also, I understand what you're saying about the infinite sum, but I can't wrap my head around it. I'm not saying you're wrong, in fact, it's highly likely that you're much smarter than me. I just have to imagine, though, that at some point 1/4 must be excluded because it's denominator isn't divisible by 3. I'm probably going to drive myself nuts trying to figure this out now. What you say makes sense, but it's also contrary to this idea that the only way to end up a number in the Cantor set is to be between 0 and 1 with a denominator that's divisible by 3. Either way, my mind has been sufficiently blown. I'll let you know if I make any progress, and thank you for correcting me. Now I've got a challenge.
@piezomofo
@piezomofo 3 года назад
@@samuelthecamel wow, I just read a paper from faculty.math.illinois.edu/~reznick/496-1-16-19.pdf It explained the same thing you said and went a little further, obviously easier to go further in a paper than in a RU-vid comment. The paper also says that in an informal survey (sample size 12) 9 out of 12 did not know or did not remember the fact that 1/4 is in fact in the Cantor set. That made me feel a little better about being wrong, myself. I would imagine that it stands to reason that 3/4 is also part of the set, since the set is symmetrical. I wonder what other numbers might fall within the set that are not so obvious. Anyway, thanks again for your original fun fact, and for setting me straight. I wouldn't have otherwise done the further research and may not have learned about this interesting non-intuitive point.
@NoorquackerInd
@NoorquackerInd 3 года назад
I can't believe binge watching 3Blue1Brown got me so ahead that I was completely ok with everything in this video
@juliekrizkova546
@juliekrizkova546 Год назад
Same here. Im in high school watching math and physics videos on yt (3b1B, Mathloger, Numberphile, Veritasium...) just for fun and I understood everything in this video. So maybe I actually learned some math or it wasnt so complicated, but I cant tell :D
@karunathakur1920
@karunathakur1920 8 месяцев назад
​@@juliekrizkova546 same bro
@helloitsme7553
@helloitsme7553 3 года назад
I like that this shows that a set can be uncountable and still have length 0, cause I've always wondered whether that was possible
@EpicMathTime
@EpicMathTime 3 года назад
Yep, it is the most prominent example of such a creature. In fact, coming up with such a creature without building up from the Cantor set, or its idea, is rather difficult..
@JoeyFaller
@JoeyFaller 3 года назад
@@EpicMathTime have you made any vids on this topic?
@livedandletdie
@livedandletdie 3 года назад
I prefer the inverse Cantor set. It has length 1, is still uncountable, and as it's length is 0+1/3+2/9+4/27... and as (1/3+2/9+4/27+..) = 1 Despite missing every number in the Cantor set, a few numbers that aren't in the inverse cantor set include 1/4 and 3/4.
@minecrafting_il
@minecrafting_il 2 года назад
@@livedandletdie i know im 10 months late, but as another comment in this comment section said, 1/4 and 3/4 are actually in the cantor set, so that is probably why the inverse cantor set does not have them
@superraegun2649
@superraegun2649 Год назад
​@@livedandletdie 1/4 = LRLRLRLRLRLRLRLRLRLR... and 3/4 = RLRLRLRLRLRLRLRLRLRLRLRLRLRL... in the cantor set.
@cobalt3142
@cobalt3142 3 года назад
Fun fact: at 7:13 you mention that you could think of the elements of the Cantor set as binary numbers, with 0's in place of the L's and 1's in place of the R's. However, if you instead replace the R's with 2's, you actually get the element of the Cantor set written in base 3. That's another way to think of how to construct the Cantor set: you take all the numbers from 0-1 written in base 3, and at each step you remove all numbers with a 1 in that digit after the decimal point.
@sunimod1895
@sunimod1895 3 года назад
12:03 I feel successfully intermissed.
@alteskonto1145
@alteskonto1145 3 года назад
Wow the intermission part really worked well
@morkovija
@morkovija 3 года назад
"No one shall expel us from the Paradise that Cantor has created" - David Hilbert 1925
@segmentsAndCurves
@segmentsAndCurves 3 года назад
Cantor is really a game changer.
@victorscarpes
@victorscarpes 3 года назад
The best way to think about the length is that every C_n has 2/3 the length of C_n-1. If you start with 1 and multiply by 2/3 on every step, C_n will have length (2/3)^n. Since the cantor set is the limit of C_n as n approaches infinity, the length is the limit of (2/3)^n as n approaches infinity, wich is also know as zero.
@lynnrathbun
@lynnrathbun 3 года назад
BUT you are NOT removing 1/3 every time because you leave the end points. The "1/3" that you remove is smaller than each of the "1/3" segments that you remove.
@victorscarpes
@victorscarpes 3 года назад
@@lynnrathbun those end points have a Lebesgue measure of zero, they make no difference to the length. Just like the intervals (0, 1), (0, 1], [0, 1) and [0, 1] all have the same length of 1 unit. It's not 1- or 1+ or anything infinitesimaly close to 1, it's exactly 1. The length of an individual point is zero.
@stdsfromspace4560
@stdsfromspace4560 3 года назад
@@victorscarpes thats why a point is called dimensionless
@victorscarpes
@victorscarpes 3 года назад
@@stdsfromspace4560 Yes, exactly!
@simohayha6031
@simohayha6031 3 года назад
Or that's the cantor set only can contain points and a point is 1 dimensional essentially, thus having no length. So zero obviously comes to mind.
@hkm239
@hkm239 3 года назад
Oh yes, time to get confused
@kuchenzwiebel7147
@kuchenzwiebel7147 3 года назад
This testing if a number is in the cantor set reminds me of the "The terrible sound you never want to hear when working on turbine engines" meme.
@WofWca
@WofWca 3 года назад
I don't get why.
@benweieneth1103
@benweieneth1103 3 года назад
3:17 Fun fact: The set of all fractions with denominators that are whole powers of three (i.e. the endpoints of the Cantor set) is a countable set. This means that *almost all* the points left behind are not endpoints.
@KokeBeast23
@KokeBeast23 2 года назад
Would the other numbers be non-computable numbers?
@benweieneth1103
@benweieneth1103 2 года назад
@Jorge Hernandez, all non-computable numbers are not endpoints, but there are computable non-endpoints as well. As explained in the video, every infinite sequence of L and R describes a point in the set. All endpoints will have some initial sequence and then either infinite L's or infinite R's. Any sequence with a different end behavior, such as LRLRLR... will be a non-endpoint, and plenty of those are constructable.
@zTheBigFishz
@zTheBigFishz Год назад
This is the weird part. The set seems to be just a collection of rational numbers which is countable regardless of any other caveats. So the set is countable as you are constructing it until it hits the point at infinity then it goes uncountable?
@benweieneth1103
@benweieneth1103 Год назад
If you're constructing it by the remove-the-middle method, all the intermediate sets are uncountable. (Any segment of non-vanishing length contains an uncountable number of points.)
@zTheBigFishz
@zTheBigFishz Год назад
@@benweieneth1103 Yea, a few minutes ago I made a comment above to that effect. At each step you get a list of end points, and some open intervals.
@PapaFlammy69
@PapaFlammy69 3 года назад
im jens herro
@maxwellsequation4887
@maxwellsequation4887 3 года назад
Hi Jens herro
@Andrew90046zero
@Andrew90046zero 3 года назад
One takeaway from this is that "infinity" doesn't necessarily mean "all". Merely, infinity is an indicator that there is some sort of unending procedure that can be used to generate numbers, and this procedure can be used unendingly. If you remove an infinite number of numbers between 0 and 1, there will still be infinitely many numbers left over. And correct me if I'm wrong here, but the distance between negative infinity and positive infinity is the same as the distance from zero to infinity.
@killmeister2271
@killmeister2271 3 года назад
i dont think you're wrong depending on what you consider a distance, but honestly it's hard to tell because infinity is such a big number that it's hardly even a number at all. the distance between 0 and 1 is 1, and the distance between negative infinity and infinity is 2*infinity, and the distance between 0 and infinity is infinity/2. the problem of course is identifying whether any of these numbers are different at all after some point. of course, it would be incorrect to state that 1=infinity or infinity/2=infinity. it's like saying 0=1, or 1/2=1, even though 0/2=0, and 1=1. fractals are amazing
@inverse_of_zero
@inverse_of_zero 3 года назад
Mate, the end part on the fractional dimension was absolutely gold. I learnt the "box counting dimension" at university but it really glossed over my head when I was an undergrad. Your analogy is so simple to understand, that I'll probably use it to explain it to my students. Thank you :)
@alansmithee419
@alansmithee419 3 года назад
9:00 What baffles me is you could do the same thing with infinitely long decimal integers and discover that there are uncountably many of them. Despite the fact that there are countably many decimal integers total.
@jinjunliu2401
@jinjunliu2401 3 года назад
The problem then is that you'd get a real number which actually isn't an integer (or fraction if you will) thus not in that set, so you haven't reached a contradiction with this new number you made
@kaiblack4489
@kaiblack4489 Месяц назад
The reason this doesn't work with the integers is that every integer has a finite length. The set of integers contains elements that are arbitrarily large, but every individual element is finite in length. If you try to apply the diagonalization method with the integers, you will end up with a number of infinite length, so it won't be a valid integer.
@alansmithee419
@alansmithee419 Месяц назад
@@kaiblack4489 Yeah I don't know what I was thinking to be honest. Me 3 years ago not as smart as me now I guess (hopefully at least). What I described appears to be akin to 10-adic numbers, which is a representation of reals, not just integers.
@karan_jain
@karan_jain 3 года назад
It is easy to find a number written in the LRLR form. Just replace all the L's with 0's and all the R's with 2's, and you will get the number in base-3. For example, 1/3 = LRRRRRRRRRRRRRRR = 0.0222222222222222 (base-3) = 0.33333333333 (base-10) You could also go the other way around to find the LRLR form from the number. For example, 1/4 = 0.25 (base-10) = 0.02020202020202020202... (base-3) = LRLRLRLRLRLRLRLRLRLR... in the cantor set.
@tomerwolberg37
@tomerwolberg37 3 года назад
Why use base 3 instead of base 2? Actually you have to use base 2 instead of 3 otherwise you can't represent numbers like 4/9 which in base 3 is 0.11 or 0.102222222 both of which contains '1', but since you can't represent 1 in your method you can't represent 4/9. If you changed to base 2 it would solve that problem (i.e. L=0,R=1 like he did in the video).
@karan_jain
@karan_jain 3 года назад
@@tomerwolberg37 But that's exactly what makes it convenient. Any number which has a '1' in its base-3 representation will never be in the cantor set (4/9 for example is not in the set). It is also possible that it is an endpoint in the set (e.g. 1/3 is 0.1 in base-3, but the convenient part is that it can be written as 0.02222... which makes it a part of the set as an endpoint).
@tomerwolberg37
@tomerwolberg37 3 года назад
@@karan_jain oh, I thought you were trying to show it's the same size as the real numbers. Now I see what you mean, clever.
@erictko85
@erictko85 3 года назад
karan jan thanks for your example, yet i am a bit lost and because you clearly have a grasp of deep mathematics maybe you could help. what is this all about? Why was Cantor showing this "set"? I ask because i can somewhat follow along witht this video, but I dont know what its all about. Why are we talking about this set? What is its significance? I know its EXTREMELY significant, yet as I am ignorant i cant figure out why. Maybe you would have interest answering?
@philosophyandhappiness2001
@philosophyandhappiness2001 3 года назад
Bro, youre a hell of a teacher. I listen to your videos while driving (being a father and husband really limits the time frame i have to focus on myself, so i do what i can) and despite that, im able to grasp everything youre talking about clearly. I wish i had a teacher that was as good as you are, back when i was in school, maybe i would have pursued higher education.
@mwill110
@mwill110 3 года назад
This is great stuff. Hope you get much bigger in the Mathematics RU-vid sphere. This is good for showing one of the absurdities of infinite sets and real numbers. Personally, I like to refer to things like this to complain about the naming convention of "real numbers" and "imaginary numbers". The reals are completely nuts!
@sturmifan
@sturmifan 3 года назад
you are only the second one that explained the "I can always find a number thats not on your list" in an understandable way, thanks!
@c.bishop1062
@c.bishop1062 3 года назад
Thanks for being an awesome channel
@brendanmccann5695
@brendanmccann5695 3 года назад
Lovely!! Thanks, Zach.
@spicemasterii6775
@spicemasterii6775 3 года назад
Awesome explanation! Thanks. I have watched both vsauce and numberphile. I personally like your channel better. Keep up the good work!
@user-oj3gb8nh2q
@user-oj3gb8nh2q 3 года назад
I read about this in Chaos: a new science. Nice!
@jimnewton4534
@jimnewton4534 3 года назад
One curious thing about the Cantor set, is that, yes, it contains all the endpoints of the C0, C1, C2, ... sequence, but it does not ONLY contain those endpoints. This is clear, because there are countably many such endpoints---they can be enumerated. The Cantor set contains uncountably many points which are not endpoints of any such interval.
@meccamiles7816
@meccamiles7816 10 месяцев назад
This is a wonderful video. Well-done.
@hjdbr1094
@hjdbr1094 3 года назад
if a set has dimension n
@bjsk6109
@bjsk6109 3 года назад
I doubt 0 has more L’s than my life
@brianh870
@brianh870 3 года назад
I had never heard of fractional dimensions before. Mind expanded. Thanks!
@liangcao4914
@liangcao4914 3 года назад
"The size of the Cantor set gets doubled when its side length is tripled." Could you please elaborate on how do you define double here? If you use cardinality, it is always that of R; if you use Lebesgue measure, it is always 0.
@robinbernardinis
@robinbernardinis 3 года назад
Having seen the video by 3blue1brown he references, I think that the size he is talking about is defined as the limit as `l` approaches 0 of the amount of line segments that contain at least one element of the set when you partition the number line in segments of length `l`
@pbj4184
@pbj4184 3 года назад
I think he is using cardinality. You said both their cardinalities were R. Can you bijectively map the elements of the L Cantor set and the 3L Cantor set?
@amaarquadri
@amaarquadri 3 года назад
@@pbj4184 I think you can. Just like how you can map the reals between 0 and 1 to the reals between 0 and 2 (by multiplying by 2), you can do the same with the cantor set. As a concrete mapping, take the number written in base 3, and multiply it by 3 (i.e. shift the decimal place). Now it covers numbers from 0 to 3 instead of 0 to 1, and all numbers are still made of 0s and 2s.
@pbj4184
@pbj4184 3 года назад
@@amaarquadri You are correct. I wonder what he meant then 🤔
@nachiketagrawal5154
@nachiketagrawal5154 3 года назад
If you extend the original interval from 0..1 to 0.. 3 then you basically tripled side length. But you'd only take the section 0.. 1 and 2.. 3 so you just doubled the cantor set
@raskr8137
@raskr8137 3 года назад
I just was researching fractional dimensions this morning, and this video comes out no more than 6 hours later. What a coincidence
@the_hanged_clown
@the_hanged_clown 3 года назад
not likely. abc corp is just really good at tracking your behavior.
@nashleydias1597
@nashleydias1597 3 года назад
The algorithm is doing a good job
@princeardalan
@princeardalan 3 года назад
You've made a very good video. Congrats!
@udaykumarpolu7749
@udaykumarpolu7749 3 года назад
Please.. Continue your efforts to increase curiosity in every student about science and math...I thank RU-vid for recommending your channel😍
@MikeRosoftJH
@MikeRosoftJH 3 года назад
The Cantor set (or Cantor discontinuum) is the set of all numbers in an interval whose base-3 representation does not contain the digit 1. Then, how about the set of all numbers whose base-3 representation contains finitely many digits 1? It can be seen that this set is a union of countably many scaled down copies of the Cantor set; and so it has measure 0. (Basically: every gap in the set is filled by another copy of the Cantor set.) It's also a dense set (and, of course, uncountably infinite like Cantor set itself). I don't know if this set has a name, or what are its other topological properties.
@9erik1
@9erik1 3 года назад
this and your last video were awesome dude -- really accessible introduction to Hausdorff's definition of dimensionality, and answered some of my musings about the Cantor set that I haven't had time to investigate. thanks!
@Jack_Callcott_AU
@Jack_Callcott_AU 2 года назад
Great video. I'd like to see another one that explores this topic even more At about 9:58 you said that the Cantor set has the same cardinality as the real numbers, but I think this statement may involve the assumption of the continuum hypothesis. You showed that the Cantor set is uncountable so it has greater cardinality than the countable rational numbers. I think the continuum hypothesis states that there are no orders of infinity between the cardinality of the integers and the real numbers, but CH has been shown to be independent of the other axioms of set theory.
@dipanpal2743
@dipanpal2743 Год назад
This video should get love as much as the size of cantor set...❤
@PhilipSmolen
@PhilipSmolen 3 года назад
I remember seeing this is college. Fun times!
@mattchandler2387
@mattchandler2387 3 года назад
That's a really good way to think about dimensions!
@justmathemagics5137
@justmathemagics5137 2 года назад
Very simple explanation.. thanks a lot sir
@fritzheini9867
@fritzheini9867 3 года назад
very neat introduction to the properties of the Cantor set. wish it had existed when I was learning analysis for the first time.
@ushasiupadhyay7958
@ushasiupadhyay7958 3 года назад
This is soooo amazing 😍
@soulintent4129
@soulintent4129 2 года назад
Really amazing video
@gigaprofisi
@gigaprofisi 2 года назад
12:00 That's really nice man, I appreciate it
@Doctormario4600
@Doctormario4600 2 года назад
Your videos are so underrated.
@biratuba
@biratuba 3 года назад
11:50, never been mad before for having RU-vid premium
@aienbalosaienbalos4186
@aienbalosaienbalos4186 3 года назад
I didn't get an ad either, no premium. Hope that makes you feel better :)
@aaronhow1932
@aaronhow1932 2 года назад
It is almost like Infinity raised to the infinity and that pattern itself also expands infinitely! Dang. This truly gives me a whole new perspective of numbers! :)
@christmassnow3465
@christmassnow3465 3 года назад
A genially simple way to bring our thinking to a higher level.
@zipfelchefchen6816
@zipfelchefchen6816 3 года назад
great video, thank you very much
@MarkusAldawn
@MarkusAldawn 2 года назад
I've just invented the non-inclusive cantor set, where instead of including the endpoints you exclude them. The full list of non-inclusive cantor numbers is as follows:
@minecrafting_il
@minecrafting_il Год назад
One year late: 1/4
@gggg-fx5wj
@gggg-fx5wj 3 года назад
There is an error in the video about how to conclude the infinite size of the cantor set. The mapping of the endpoints to strings of ones and zeroes makes it a countable set which is much smaller than the set between 0 and 1. However the numbers between the endpoints remain uncountable and is therefore much larger.
@elliott614
@elliott614 3 года назад
Sounds like somebody's taking Intro to the Theory of Computation this semester lol (such as CS520 if you go to UW-Madison)
@tamirerez2547
@tamirerez2547 2 года назад
the intermition. great idea!! 👍❤️😃
@musicsubicandcebu1774
@musicsubicandcebu1774 3 года назад
We spend 1/3 of our lives sleeping, and the other 2/3 in the dark.
@AndrewMarcell
@AndrewMarcell 3 года назад
I’m a math teacher who spent way too long in college and graduate school. Congratulations, you finally got me to care about the Cantor set!! 🎉
@priyansusingh1272
@priyansusingh1272 3 года назад
Amazing dude👍🏻👍🏻👍🏻
@pingnick
@pingnick 3 года назад
Wow definitely many teachers should play this before a given class but it brings too many things together I guess hahaha yeah wow excellent illustration of fractal dimension calculation in particular! Thank you!!
@sachatostevin6435
@sachatostevin6435 3 года назад
Hi Zach, Another great video by you! This may be just semantics, but I'm a little bit unsure of the use of the term "fractional dimension" here. Sure, the dimension number is not an integer, but (ln(2))/(ln(3)) doesn't seem rational either... would it not be more appropriate to refer to it as "irrational dimension"? I think doing so would make it distinct from some of those other fractal-like examples that have "fractional dimension" that are rational numbers. Or have I just taken it way out of context?
@aaronhow1932
@aaronhow1932 2 года назад
Very fascinating! :)
@universallabs
@universallabs Год назад
Very nice video, I have a question as to what would the relationship be with a cantor set and an aleph number?
@TechnocratiK
@TechnocratiK 11 месяцев назад
It's worth noting that the LRLRL... example you gave corresponds to 1/4, which is in the Cantor set. So, adding to the weirdness, although all the endpoints of the intervals have denominators that are powers of 3, in the limit, the Cantor set contains rationals whose denominators are not power of 3.
@rfMarinheiro
@rfMarinheiro 3 года назад
I think your argument for uncountability is missing something. If we assumed that only the endpoints are part of the set then it would definitely be possible to enumerate them: - On the i-th iteration (with i > 0) you are adding 2^i new endpoints, which you can easily enumerate from smallest to largest. - This means that before the i-th iteration you would have 2^i points already in the set. Then you could assign labels [2^i + 0, 2^i + 1, ..., 2^i + 2^i - 1 = 2^(i+1) - 1] to the new points. It is easy to show that this would be a bijection between the endpoints and the naturals, which would mean that the set would be countable. The reason why the cantor set is uncountable is because some points that are not endpoints are also part of the set. The actual proof uses a similar idea. First you look at the expansion of the number in base 3. Just like numbers can be written in base 10 like 0.1 or 0.9562, you can think of numbers in base 3 being written as 0.0. 0.1, 0.2, 1 and so forth. A number is only ever removed if a 1 appears in the numbers after the decimal point. 0.1 in base 3, the equivalent of 2/3 in base 10, gets removed in the first iteration and you can see that in the notation. This means that the cantor set is essentially the union of all numbers with only 0s and 2s after the "decimal point". Then you can use the same argument of having infinite lists of numbers.
@Ennar
@Ennar 3 года назад
Zach's argument is simply that there is a bijection between elements of Cantor set and binary sequences and 2^(aleph_0) is uncountable.
@rfMarinheiro
@rfMarinheiro 3 года назад
​@@Ennar I agree that there's a bijection between the Cantor set and binary sequences of infinite size, but that's not what he showed in the video. What he showed was an injective mapping from a subset of the Cantor set (the boundaries) into the set of binary sequences of infinite size. That particular subset of the Cantor set is actually countable (see sketch of proof just above). You can't make any conclusions regarding the countability of that set from this argument alone.
@Ennar
@Ennar 3 года назад
@@rfMarinheiro, take a look at 7:02. Zach says: "The Cantor set is every single combination of infinite L's and R's you could possibly have," which clearly includes points that are not endpoints. He just explained what a sequence of L's and R's represents on the example of endpoints, since they are easy to visualize and never claimed that endpoints are uncountable.
@EpicMathTime
@EpicMathTime 3 года назад
@@rfMarinheiro Any point in the Cantor set can be identified with these {L,R} sequences, not just the endpoints. The endpoints in particular are identified with {L,R} sequences that are eventually constant. So, the described {L,R} sequences puts the Cantor set in bijection with binary sequences. It puts the endpoints in particular in bijection with finite binary sequences.
@vojtechstrnad1
@vojtechstrnad1 3 года назад
I came looking for this. Thanks for the explanation, I was confused because I understood that only the endpoints make it to the Cantor set, which would make it countably infinite.
@user-op9gv3mp6p
@user-op9gv3mp6p 3 года назад
YOU ARE THE BEST !
@wesleysays
@wesleysays Год назад
That’s beautiful
@PainfullHands93
@PainfullHands93 2 года назад
But this set has to be countable if we agree on the structure of the numbers, and we can easily show that every number in this set has to, at some point in the LR representation, become stable and exclusively have L's, or exclusively R's from that point on, that position would also denote the C_n on which it was added to the set. This also means that if you attempt to create a representation as shown in the counterexample of flipping the L/R at the specific position, you would never reach a point in which the tail stabilises at exclusively L's or exclusively R's, thus the created counterexample is not in the set (by definition we would never reach the C_n in which it would be created, because at some point it would flip positions from L to R or back.
@yashrawat9409
@yashrawat9409 3 года назад
Me at 2 Am: Casually studying about how Cantor Set has log_3(2) dimension
@RobbyBobbyBoy
@RobbyBobbyBoy 3 года назад
Coming to the realization that each split of the cantor set becomes its own cantor set without him having to tell me was a fun thing
@tobias5740
@tobias5740 3 года назад
Where do you have the zoom into the cantor set animation from? I can't find anything even close to it! It's mesmerizing
@VivekYadav-ds8oz
@VivekYadav-ds8oz 11 месяцев назад
The length being zero isn't surprising at all if you realise how length is defined. It doesn't have much to do with the amount of points in the set. Those remain infinite throughout. It's just the sum of all the max - min of largest subsets that are continuous in nature, at each step. At first step, all points in the range [0,1] are included. So the largest subset that is continuous is [0,1] itself. 1-0 = 1. At second step, the largest subsets that are continuous are [0,1/3], [2/3,1]. 1/3 - 0 + 1 - 2/3 == 2/3. So it's no surprise that in the limiting case, when all the points become discrete and are no longer continuous, the largest length is the length of a single point itself. Which is x - x == 0.
@killmeister2271
@killmeister2271 3 года назад
i think you can use the LR explanation for finite numbers. personally i think rounding the number down is how this can work. for example, if i have 001, that's LLR which is any number between 2/9 and 1/3 so if you were to round down it can just be 2/9. EDIT: i am currently trying to make an encoder and decoder to turn strings into numbers and that number back into the string data. i have completed the encoder, but the decoder is a bit difficult. this, however, is possible.
@douglaswilliams8336
@douglaswilliams8336 3 года назад
I am absolutely scared shitless when it comes to arithmetic. I've never been good at it so never tried. As a college student with degrees I can honestly say I have calculators going back some years. Being one of the 1st in my area to carry a mobile, I did so because they had a built in calculator. So why do I love these types of video?? They more convoluted the better. I'm just starting to get it.
@mygills3050
@mygills3050 2 года назад
when a is an integer, a=3^n, and m
@victorjimenez7213
@victorjimenez7213 3 года назад
Bro this would have been nice to see last year in my Dyamics and Chaos theory class. That w/o a doubt the hardest math course in my life.
@austinsides5779
@austinsides5779 3 года назад
Hey Zach, can you do a video about Nuclear Engineering, or it's careers?
@plazmotech5969
@plazmotech5969 3 года назад
ok before watching the video heres my initial thought: any number between two rational numbers gets removed eventually... given any number we should be able to come up with two rational numbers whos denominator is a power of three and gets removed eventually. so all numbers get removed? (besides endpoints)
@benlindquist3302
@benlindquist3302 3 года назад
I had seen the 3Blue1Brown video on fractals but this explained the dimension thing way better
@JamesWylde
@JamesWylde 2 года назад
Finally! Someone that can include their mid roll ad spam at a break point that makes some sense
@nomattr
@nomattr 3 года назад
You can arrange every element of Cantor set to each of the elements of the set of numbers eliminated by only the first iteration. That means that what was removed from Cantor set is power to infinity larger than the Cantor set itself. How can we tell that the Cantor set size is the same as set of Rational numbers when we only considered a subset of Rational numbers?
@loganharrisoncrabtree4644
@loganharrisoncrabtree4644 3 года назад
What is the background music in the beginning of the video
@ahasdasetodu6304
@ahasdasetodu6304 2 месяца назад
That makes me wonder whether a function that maps elements in cantor set to 1 and those that are not to 0 would be riemann integrable since the set of points of discontinuity have length 0 and if so what such integral would equal
@Lovuschka
@Lovuschka 2 года назад
9:10 This however works only because you have a length of the number that is equally long or longer as the entries in the list of numbers you have. So in fact, you can never find any new number that way, as you would need an infinite amount of time to create one, i.e. your attempt to create a new number would never end, and as such no new number at all would be made.
@aligator7181
@aligator7181 2 года назад
Do yourself a favor and don't try to make sense of it. The entire lecture is total nonsense, nothing can ever be proven. This guy is just goes on and on without any proof or any solid examples...pure gibberish
@rmbennet
@rmbennet 2 года назад
I got a dominos ad right after staring at the screen while zooming into the cantor set and now I really want pizza.
@likelike12345
@likelike12345 2 года назад
Is this true that the Cantor set includes only multiples of powers one-third? I my understanding is that the Cantor set includes mostly irrational numbers and many rational numbers that are not multiples of integer powers of one-third. The usual example is one-fourth, which never gets removed. If it actually included only multiples of powers of one-third, there is no way it could be uncountably infinite because it would be a subset of the rationals, which are countably infinite. You'd would be able just count the rationals and skip the ones that are removed.
@ferminenriquezamorapineda2832
@ferminenriquezamorapineda2832 3 года назад
The most intriguing for me is that probably infinity just exists in math but not in the real world, assuming that the space-time is discrete rather than continuous, and maybe that could be the reason of the tiny errors in many mathematical models of physical systems
@djowsvideos
@djowsvideos 3 года назад
Very cool and interesting video
@choco_jack7016
@choco_jack7016 2 года назад
it's all the numbers inbetween 0 and 1, including 0 and 1, that, in ternary, don't have a 1 in them, or end with 1. ex: 1/3 is 0.1, 2/9 is 0.02, 0 is 0, and 1 is 1.
@anujyiitk
@anujyiitk 2 года назад
Amazing explanation...............
@jacksonhunt6410
@jacksonhunt6410 3 года назад
This is insane. Fractional dimensions? I’ve never even heard about that before!
@wyboo2019
@wyboo2019 Год назад
relevant search term: Hausdorff Dimension two years late but oh well
@jacksonhunt6410
@jacksonhunt6410 11 месяцев назад
@@wyboo2019 I’ll look that up. Thanks
@levno
@levno 3 года назад
Actually you can do the binary flipping thing with Integers as well. You could just add one to every digit and if you have a 9 you wrap it around to 0.
@Hyrum_Graff
@Hyrum_Graff 3 года назад
Yeah, that's usually how that's used. It's called "Cantor Diagonalization", and from the name, I would guess that Cantor used it to prove that the set of all real numbers is larger than the set of all integers.
@lam6786
@lam6786 3 года назад
This looks like one of those cube fractals
@rossholst5315
@rossholst5315 9 месяцев назад
My question is what makes any starting point for counting unique? Meaning how can we be sure that the location selected is really the value of 1? Could we not always move the starting point for counting over any arbitrary amount? Also could you not make a subsequent arrangement where we only take the endpoints, divide the length into 10 divisions , only taking each end point. And repeat that process again with just dividing the distance between two points into 10 units. Just keeping the end points each segment. And eventually if we kept doing this we would start with 2 points with a length of 0, and we would build up to the infinite number of points between 0 and 1 giving our line a length of 1?
@DaRza17
@DaRza17 2 года назад
Why did the youtube algorithm gods hide this channel from me for so long? Amazing content my dude!
@GhostyOcean
@GhostyOcean 3 года назад
Just some notation before I state my question. when a number ends with _3, that means base 3. Would the number 0.02222…_3 be in the Cantor set? What confuses me is 0.0222…_3 = 0.1_3 for the same reason 0.999… = 1. Even though its ternary value on the left never contains a 1, its value on the right does have a 1 in its expansion. So is it in the set or not?
@Ennar
@Ennar 3 года назад
It is, it is simply 1/3. The defining statement should be "there exists a ternary representation with no digit 1" and not "every ternary representation contains no digit 1". You can think of 0.1 as 0.1000000000..., which tells you: choose middle segment and then keep choosing left. The thing is that interval (1/3,2/3) is not closed, so a sequence in it can converge to a point outside of it.
@waynedarronwalls6468
@waynedarronwalls6468 2 года назад
This strikes me as being vaguely similar to the Zeno paradox...in a different context though of course...imagine Zeno trying to get his head around the idea of uncountable infinities...never mind not being able to make the final step, he would not even be able to make the first lol
@abulhasankapraywala
@abulhasankapraywala 2 года назад
that intermission music didn't make me stop wondering about infinity
@philosophyandhappiness2001
@philosophyandhappiness2001 3 года назад
I was just discussing how there are different sizes of infinity and actually used integers and fractions as my example, stating there are more fractions than whole numbers, going into detail about the infinite number of fractions in between 0-1, and then i see this video the next day😂😂 hell yeah
@kangalio
@kangalio 3 года назад
Great intermission lmao
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