1:45. I think it's electron from second shell experiencing shielding effect from electron from 1st shell. because repulsive force from electron from second shell and nuclear force from nucleus will be in same direction thus the net force should come after adding the forces whereas repulsive force or shielding effect from electron from 1st shell will be in opposite direction to nuclear charge experienced by 2nd shell electron. thus it net force will come after subtraction. It's not possible for net force to come from subtraction when both forces are in same direction. I said it after listening and seeing the diagram, and in diagram the forces was being experienced by 1st shell electron in opposite direction. Pls Correct me if I am wrong.
@dimpypandey7483 Isn't the electron in the first shell exerting the repulsive force of 7N on the second electron? I think if that's the case then the effective nuclear charge will be 3N. Since the repulsion is in opposite direction than that of Nuclear force. Correct me if I'm wrong tho
1:10 sorry to say sir But i think there is mistake in diagram representation The net force will be studied on outermost shell (valence shell) electron not on inner shell electron !! The inner shell electrons repel valence shell electron and they(inner shell elec.) Try to Cut off the attraction between nucleus and the valence shell elec. And then the net positive charge experienced by an electron (valence shell elec.) is known as effective nuclear charge Z*=(Z-S)
U said effective nuclear charge decreases down group but lithium and sodium effective nuclear charge value -1(for li---3-2=1and for Na--- 11-10=1) then it will remains constant???then how it will decrease down the group
bhai sahab, Na mai inner electrons leta waqt k shell aur l shell dono ko consider kare aur abb cl mai sirf k shell kya logic hai inka ,,,,,,,, aur iss logic se toh na aur cl ke alawa jitna bhi elements hai biccha mai unka kya ayyega 1 se 2 ke beecha mai...............
