Another explaination can be that all periodic waveforms can be considered as a sum of different sinusoidal frequecies( Fourier series). When we multiply voltage and current for power only the components with same frequency will produce power. Hence if a power loss is to be calculated across diode, the voltage across diode is a dc, but for current it is ac ( with multiple frequencies) but only the dc or avg term will result in power loss. Similarly for mosfet both the quantities are ac, so rms is used represent the whole ac quantity quantity
Yes thats what they teach in college about the diode forward drop, but in real world the forward voltage drop across a diode is NOT constant, it increases with the current flowing through it. Simply pickup any datasheet of a diode and check for Vf vs I characteristics
Please, what will multimeter in DC and AC mode measured when hooked up to AC supply. Came at right while am thinking about the difference between RMS and AVR value.
Since you are calculating the areas under the signals, if the signal is always positive the value rms and avg are the same. If the signal goes negative it subtracts from the avg and it sums for the rms. That is why rms is useful for power measurements (power is always positive). In the particular case of sinusoidal signals you can easily calculate rms from peak value just dividing by sqrt(2)... (btw in this case the avg is zero). For DC avg and rms are the same.n
Dear Dr, I don't understand the move to RMS values at this point ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-J6PaYV5o36U.html. Could you give me some tips ?
