Why Sudoku Solvers Overlook This SUPERIOR Strategy - SHC 206

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In Why Sudoku Solvers Overlook This SUPERIOR Strategy - SHC 206 by Smart Hobbies, I will show you how to solve the Classic Sudoku Puzzle No. 389 by Akash Doulani using a superior Sudoku Strategy. I also explain why other Sudoku solvers avoid this strategy. This strategy takes the place of 4-5 other advanced strategies. I show you how to play Sudoku better and how to solve Sudoku faster. I solve this puzzle logically and explain all the expert Sudoku tricks, Sudoku techniques, and Sudoku strategies as I apply them to the Sudoku game. Thank you Akash Doulani for permission to feature your puzzles on my channel.
I used the software program CTC App for this solving video. Puzzle link:
tinyurl.com/4rfw94dh
Check out Akash Doulani’s blog and get his new book here: akashdoulani.blogspot.com/
This video is part of my Sudoku Handmade Classic series on my RU-vid channel, Smart Hobbies. The goal of this series is to share the joy of solving Sudoku puzzles with you.
#learn #sudoku #youareawesome
Strategies demonstrated in this video:
Hidden Single
Naked Single
Full House
Pointing Pair
Naked Pair
Hidden Pair
Naked Triple
Nice Continuous Loop
W-Wing (D-variant)
Timestamps
0:00 Intro
00:21 It’s Solving Time
03:52 Akash Doulani Fun Facts
04:04 Snyder Notation and Hidden Singles
05:24 Naked Pairs
09:19 Superior Strategy
14:38 Why Solvers Do Not Use Superior Strategy
15:53 Solving The Green Cell
18:12 Solving After The Green Cell
📕Get my FREE Solving Guide that will help you solve over 80% of all Sudoku puzzles🧩to include NYT Hard👉👉www.buymeacoffee.com/timberla...
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Subscribe to my channel here: / @smarthobbies
Follow me on Instagram: / timberlakesmarthobbies
Check out Smart Hobbies page on Harold Nolte’s Sudoku Primer website here:
sudokuprimer.com/smart-hobbie...
Contact me here:
Reddit.com: Timberlake52
Discord: Timberlake#1905
Let me know what you think and how you did in the comments below. Thank you so much for watching.
Timberlake
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Опубликовано:

27 июл 2024

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Комментарии : 25

@SmartHobbies 8 месяцев назад

Join the Smartie Party now 🥳to get EXCLUSIVE reward puzzle packs, ad free content, discord access, and so much more👉👉www.buymeacoffee.com/timberlakeB/membership Timestamps 0:00 Intro 00:21 It’s Solving Time 03:52 Akash Doulani Fun Facts 04:04 Snyder Notation and Hidden Singles 05:24 Naked Pairs 09:19 Superior Strategy 14:38 Why Solvers Do Not Use Superior Strategy 15:53 Solving The Green Cell 18:12 Solving After The Green Cell

@JohnRandomness105 7 месяцев назад

I finished the puzzle rather slowly. There were a surprising number of pairs, and several triples. Two pairs led to finned X-wings (3s and 8s), probably superfluous. In the endgame, I colored 58 cells. I found this chain: if R1C1 (containing 45) is 5, we get a 34 pair in row 2 block 3. This forced R2C3 (with 49) to be 9, and this finally cracked the puzzle. The rest was resolving pencilmarks. After my solve, I saw the W-wing delta-variant listed in the tactics. Sorry, still haven't yet mastered that. 5:50 I got that 59 pair in column 2 later, after filling out blocks 9, 1, and 7. 7:00 Placing the 6s gave me a 49 pair in column 3. 10:40 I have the 59 pair in column 2 and the 58 pair in column 9. I wish that I'd recognized that as a skyscraper although it appears to be superfluous -- removing a 5 from R9C1. Instead, I continued filling out the grid until everything was centermarked. I placed three 7s and a 1 in the process. (Those are partially visible in the video's grid here.) This gave me another 58 pair in row 7: R7C1 and R7C7, which gave me several more digits. Next came a 479 triple in row 6, giving me more digits, and a 138 triple in row 4, giving me a 679 counter-triple. 13:50 Dumb question: is there a variant on the "nice continuous loop" called a "nasty continuous loop"? The last interesting tactic of my solve: I colored the four 58 cells. Then I found a chain with those remote pairs: R1C1 is 45. If 5, then R3C9 is 5 and R2C78 is a 34 pair. Otherwise, R1C1 is 4. In either case, R2C3 can't be 4, it has to be 9. This solved the green cell, and also cracked the rest of the puzzle. 14:40 Unfortunately, when I try to observe the big picture, it looks like a scrambled mess. 15:20 I got all of those digits in the wake of the second 58 pair. I'd placed the 7, along with two other 7s and a 1, earlier. 17:10 I never removed the 5 from R3C6, so I never got that W-wing variant. It occurred to me that an "oddagon" is a nasty continuous loop.

@SmartHobbies 7 месяцев назад

Oddagon being nasty is a good way of putting it.

@Ramakrishnagm 7 месяцев назад

Wow. Nice tric or strategy., After solved my way I saw your vedio. Getting 49 in r3c6 is intended tricky solve path or Nice Continues Loop. The next magic is W wing with 49s, without showing conjugate 4s explained nicely. (Conjugate 4s in row 1). And once we get 49 in r3c6 XY wing 459 (45,59 in box 1, and 49 in box2) 35 pairs in box 2, 4 in r1c1 the puzzle get solved. But intention is W wing. Very good explanation, and we'll constructing grids to get this loops. .... I tried , got four 7s, two 2s and filled no's in all cells. 1) Swordfish 1s., in Row 4, 5, 6. and col 1,4, 8. Elm 1 from r9c1 made *1 in r9c3* After eliminating some no's and got *45 in r8c5, and 345 in r1c5* 2) ( Two in One ) W wing 45, 45s in r1c1 and r8c5. Targeting cell r1c5 (345). -Conjugate 5s (59 pairs) in col 2, eliminated 4 from r1c5 345 to 35. - Conjugate 4s (49 pairs) in col 3, eliminated 5 from r1c5 35 to 3. Now 45 in r1c4. 3) X chain 5s.... Start r1c4 (45) r1c2 (45) r3c2 (59) r3c9 (58) End, all strong links., Eliminate 5 from r3c6 (459= 49). -Or XY chain start r1c4 45 end r3c9 58. Involving boxes 2, 1, 7, 9, 3. Eliminating the same. 4) XY wing 459., 45, 49, 59. r1c4 45, r3c6 49, r3c2 59. Eliminates 5 from r1c1 45 to 4. Puzzle solved. Thanks for giving very good puzzle.

@SmartHobbies 7 месяцев назад

Wow. It looks like you went the more traditional route with the multiple advanced strategies. Nice job spotting the X-Chain. I thought that one was quite tricky, along with the W-Wing.

@Ramakrishnagm 7 месяцев назад

@@SmartHobbies I want to go with traditional way, because I want learn more strategies, still not completed learning. If I satisfy to learn then I will go for shortcuts, or tricks and solving without strategy. Here it is logical trick, no strategy., After getting some no's, and filled possible candidates in rest of all cells,..., *If r3c2 (59)* is 5 or 9, then 5 eliminated from *r3c9 (58)* ** See the logic...r3c2 (59) - If it is -5- then, 5 eliminated in *r9c9 (58)* - If it is -9- then, r2c3 (49) is 4, r2c8 (34) is 3, r2c7 (345) is 5, then 5 eliminated from *r9c9 (58)* Now we get 8 in r8c9, puzzle solved. The detail... 8 in r3c9(58), 5 in r9c9 (58), 8 in r7c7(58), 59 pairs in box 7, 4 in r8c3 (49), 9 in r2c3 (49), 5 in r3c2 (59), now 5 eliminated from r1c1 (45), 4 spotted. 4 is the key of the puzzle, Single 4 in r1c1 crack the whole puzzle. Thanks for Mr.AKASH DOULANI.

@milkom2021 7 месяцев назад

Truly a remarkable job finding that AIC, Timberlake! 👏🏻 Not having been so observant I had to take a more tortuous route by using Empty Rectangles to eliminate couple of 5s from row 9 and then removing 5 from r3c6 with an X-Chain which gave me a Y-Wing that in the end resolved the green cell. Whew! 😅

@SmartHobbies 7 месяцев назад

Way to go Milos. There were many other ways and strategies to get there. Glad you found some that got you to the green cell. Thank you so much for watching.

@UKcuber 6 месяцев назад

10:25 at this point I looked at where the 5 can be in box 9. It's either in row 9 column 9 or failing that there is one in row 3 column 9 forcing 5 into row 8 column 2 which forces the other box 9 5 to be in row 7 column 7. We therefore have a 58 pair in box 9 and also 17 pointing pair in the only two places left.

@SmartHobbies 6 месяцев назад

Nice job spotting this. Thank you for sharing. I like to hear how other people approached and solved these puzzles.

@akashdoulani3230 7 месяцев назад

Hi Timberlake. It was a very informative video. Hadn't heard of this technique. It's really nice to learn about such techniques. Thanks for featuring this on your channel

@SmartHobbies 7 месяцев назад

You are welcome, Akash. Wonderful puzzle. I knew it would be challenging. I love seeing the strategies that the viewers are finding.

@paulakeay4317 7 месяцев назад

Nice explanation of the w-wing, thanks

@SmartHobbies 7 месяцев назад

So glad you liked it Paula. Thank you so much for your kind words and for watching.

@jonbrowne 7 месяцев назад

Very hard solve Timberlake! Probably one of the toughest you have posted! Thanks all the same!

@JohnRandomness105 7 месяцев назад

Yeah, definitely not easy. For me, it wasn't nearly as difficult as last week's puzzle by Wisteria. I managed to avoid or evade the W-wing delta-variant the video features. (I haven't watched it yet.)

@SmartHobbies 7 месяцев назад

It was the toughest I’ve seen by Akash. He does a great job of putting the strategies in the puzzle to make them stand out and appreciate finding them.

@jonbrowne 7 месяцев назад

@@JohnRandomness105 well done John!

@brucewayne2091 7 месяцев назад

Strange, I simply sliced & diced my way thru & found a remarkable amount of cells where only 1 candidate could go in. Once you started strong/weak links, I could understand why competitive solvers would go with simpler solving methods.

@SmartHobbies 7 месяцев назад

Nice insight Bruce. Going for continuous loops requires a change of mindset. Otherwise, you will be applying multiple advanced strategies. Do you think most solvers would rather do all the smaller advanced strategies?

@brucewayne2091 7 месяцев назад

@@SmartHobbies TL: I've watched quite a few 'how to solve' as you could imagine. I don't think anyone does a great job of strong/weak so yes, I think most solvers would rather have a small reliable set of strategies that apply to the majority

@AnonimityAssured 7 месяцев назад

A lovely puzzle, but well beyond my purely logical capacities. I had to throw colours at it numerous times, and a Skyscraper helped a bit, but even then I needed a couple of ad hoc virtual chains to crack it. I'm so out of my depth with your channel that if it weren't for the SGP puzzles, I think I'd jump ship. Afterthought: Here's a variation that is more compatible with my limited abilities, although it's certainly no walk in the park. Its beauty lies in the fact that it is more ordered than the original: 018 000 040 200 700 009 300 600 000 045 006 000 000 020 000 000 100 650 000 007 004 600 008 003 090 000 120 018000040200700009300600000045006000000020000000100650000007004600008003090000120 HoDoKu grading: 1502 Hard. Andrew Stuart grading: Tough Grade 197.

@SmartHobbies 7 месяцев назад

Thank you for your insights, Julian. This is probably the toughest Akash puzzle I’ve seen and I knew there were lots of strategies to throw at it. I’ll have to check out your variation. 1502 Hodoku rating is no walk in the park.

@Ramakrishnagm 7 месяцев назад

JULIAN ❤ 🙏., I tried 018 000 040 - 23. Beginning and the middle it ok., but the final 😮tough. I got no's...44 no's. 018 002 746 200 700 009 370 600 205 145 076 002 700 020 401 000 100 657 000 207 064 600 408 073 497 060 128 Than filled no's in all cells. Five more strategies found, got 53 no's still got stuck. So I decided to go with tricky solve with easy 44 no's(top). 1) X chain of 9s with strong link., Start -r3c4 (49), r1c4 (359), r1c1(59), r6c1 (89) End. Elm cl r6c6 (349=34) Now we get 34 pairs in box 5. It makes 289 trio in box 4, and *r5c3 (369= 36)* 2) r1c1 (59) is 5 or 9 then r8c3 2 eliminated and 1 spotted. The logic... - If it is 5 then, 6 in r2c2, 3 in r5c2, it forces next 3 in r7c3, now col 3 got only one place 1 for r8c3. - If it is 9 than, 4 in r3c3, 6 in r2c3, 5 in r2c2, 2 in r8c2, so in r8c3 eliminated 2 and spotted 1. If two way r8c3 is 2 eliminated and 1 spotted. Puzzle solved. Detail.... 1 in r8c3, 3 in r7c3, 6 in r5c3, 4 in r2c3, 9 in r3c3, now r1c1(59) 9 eliminated and 5 spotted. 5 is the key for whole puzzle. Thanks for the puzzle.❤.