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Young Laplace Equation 

Martin Blunt
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An introduction to the Young-Laplace equation. One of a series of videos using lightboard technology developed at Imperial College London. I would like to thank Ollie Inglis, Hywel Jones and Lekan Ladipo from the Digital Media Centre in the Faculty of Engineering at Imperial College London for their help producing this and the other lightboard videos.

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26 сен 2024

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Комментарии : 23   
@anubhavarora3282
@anubhavarora3282 Год назад
Sir your way of explaining is truly fabulous. I am grateful to you for providing such a quality content
@JohnParra-u2o
@JohnParra-u2o 9 месяцев назад
Finally I understand the basis behind the 2σ/r. Thank you for sharing your knowledge, Professor.
@adampax
@adampax Месяц назад
Masterful work to explain mean curvature intuitively in less than 15 minutes!
@IndiraYessenaliyeva
@IndiraYessenaliyeva Год назад
Crystal clear, thank u 🙏
@Fawad.ANizamani
@Fawad.ANizamani Год назад
OH MY GOD you are back
@pizzalove4693
@pizzalove4693 5 месяцев назад
Very nice explanation Thank you for such quality content
@DANGJOS
@DANGJOS 3 месяца назад
You make it look easy, thanks!
@agamjain9138
@agamjain9138 4 месяца назад
Thank you sir❤
@manikmehta2090
@manikmehta2090 5 месяцев назад
❤️❤️thanks sirr
@笠峰倪
@笠峰倪 3 дня назад
Your explanation is clearer and more understandable than the one in Landau's Fluid Dynamics. Thank you.😁
@BoffyBlunt
@BoffyBlunt 3 дня назад
Many thanks - rare praise indeed!
@zq88
@zq88 4 месяца назад
Hello, Professor. Thanks for your video! Can you explain how to determine the curvature sign? My understanding is that if the curvature center is in the denser phase, then it is positive. Is that right?
@BoffyBlunt
@BoffyBlunt 4 месяца назад
I think you have this the wrong way round. We define the capillary pressure as the difference in pressure between the less dense phase and the denser phase, then positive curvature is when the less dense phase bulges out into the less dense phase (think gas and water).
@zq88
@zq88 3 месяца назад
​@@BoffyBlunt Thank you sir! I think I've got it.😃
@coldchickennoodles5575
@coldchickennoodles5575 5 месяцев назад
I still don't understand the equation, can someone explain pls
@BoffyBlunt
@BoffyBlunt 5 месяцев назад
What specifically would you like help with? I can try to clarify points that you are confused with.
@coldchickennoodles5575
@coldchickennoodles5575 5 месяцев назад
@@BoffyBlunt Thank you so much for answering. I just find the 'dv' part in the first equation you presented slightly confusing and the V=4/3(pi)r^3
@BoffyBlunt
@BoffyBlunt 5 месяцев назад
@@coldchickennoodles5575 The dV comes from work - the work done from basic physics is PdV where P is pressure and dV is the change in volume. The equation V - 4/3(pi)r^3 is the equation for the volume of a sphere in terms of its radius r.
@User-Tal1951
@User-Tal1951 Год назад
Hi I need to ask something. How to reach you? Thanks
@BoffyBlunt
@BoffyBlunt Год назад
You can email me at m.blunt@imperial.ac.uk
@noodles8439
@noodles8439 3 месяца назад
I understand everything except that the professor can write backwards.
@stanleynio
@stanleynio Месяц назад
Fr
@TheJugx
@TheJugx Месяц назад
Mirrored...
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