The diode videos in this channel tend to focus more on the half and full wave rectifier circuits. If you have a suggestion for a video topic please do share.
Thank you for spotting this typo. In the example presented at 16:48 in the video, R_L = 1kOhm. Then I_L = V_L/R_L = 5.1mA. The value of R_L = 1kOhm was accidentally omitted in the video.
Thank you for the question. In the example presented at 16:48 in the video, I have solved it using Vin= 12V, V_z = 5.1V and R_L = 1 kOhm. V_L = V_z so we get I_L = 5.1mA. Your calculation is assuming V_L = Vin = 12V, which is not correct. Hope this clarifies the confusion.
iL varying is essentially the same as RL varying. In this video, we have considered the 3 fundamental parameters varying individually. It is possible for two parameters to be varying together. In such a case, we will have 4 possible operating points. In your specific case (min iL, min vi) (min iL, max vi) (max iL, min vi) and (max iL, max vi). One of these operating points will give maximum R1 value. Hope this hint helps.
@@electriccircuits7164 thank you for your clarification , i want to make sure that i understand the problem , i think to get the maximum Rs this means that it will get maximum voltage across it , so the voltage across RL should be minimum , so RL itself would be minimum so the current IL would be maximum , and from the equation Iin = Iz + IL if IL is maximum so Iz is minimum and since Iz = (Vin - VL)/R1 - IL -> Vin must be minimum to achieve minimum Iz (which in case of ideal zener diode minimum Iz = 0) , is my intuition correct ?
Yes your thinking seems correct to me. You can confirm your intuition by solving for the 4 operating points and confirming that you get max Rs value corresponding to the operating points you identified.
