zetamath reacts to Simon solving Funhouse 

I made one logical error early. Because the triangle number for 6 is 21, I assumed the 6 cell 10-lines had to add to 30, completely missing that they were in 2 boxes. That's why I watch Simon: after I crash and burn, I learn why. Fixing that one mistake, I was able to finally solve this puzzle. It was a lot of fun, thank you!

After pencilmarking box 1, I did look at the L going into box 4. I just immediately saw that the top two cells couldn't be 46, so it had to be 3 cells. Then I pencil marked the bottom two horizontal cells as 1379 since the 46 and 28 at the top eliminated those. It was easy for me to see that r3c1 couldn't be 6 which would need a 13 and rule out both pairs for the domino or 4 which couldn't have 24 or 15, and therefore must be 5 with a 23. That of course left 19 at the bottom and helped fill in box 4 and got me to there being a 1234 in box 7 pretty quickly. Then I went over to box 3 and was able to work it out relatively quickly, but not very eloquently, ha. Great puzzle and I love seeing your thoughts on it! Setting these puzzles is such a cool concept to me.

A couple of hours ago, I saw in the recommended videos Zetamath's stream of another puzzle solved by Simon. Not recognizing the puzzle, I decided to find and solve it. It took me a while, especially after thinking I'd broken the puzzle and backtracking. Now that I've finished, it's too late for the live stream, but I'll watch this in lieu of watching Simon's solve. 7:50 Often, perhaps, but not always. I remember that puzzle with the dominoes in row 5 and column 5 that Simon missed. At one point, Zetamath said that this was "not the approachable way". 8:00 That U or horseshoe-shaped ten-line: I didn't finally solve it until right at the end. I did something with it earlier (but still late) to place 5 and 9 in column 9, but that's where I thought I'd broken the puzzle. I went back to that step, redid it, and reached the point where the puzzle seemed broken, but this time decided to ignore that line and plough on placing the digits, hoping against hope for something good. A 1234 group turned out to fit at the end. 27:40 Simon prefers the complex-compound deductions over the immediately obvious. 36:00 Only just now did I remember how I forced 46 on row 1 onto the green line. In block 1, column 1 was a 456 triple. 41:50 That sequence of pairs is nice when going down the columns. It's nasty when looking cross the rows. 47:30 I admit that I went in that direction as well, down the hooked gray line. It might be bizarre that we get several 19 dominoes both on and off the gray lines. 52:00 I wish that I'd noticed that. 1:15:10 *Some* shading I found helpful, specifically shading one group light gray on a ten line to identify which cells are in a group. And I colored some green lines by polarity. Sometimes I color them temporarily.

Cherish these live stream watch parties!! Great to pick your brain and learn insights into how you set beauties constantly. Thank you as always Zetamath!

Interestingly, when it came to the “left eye” ten line, I also first proved 1234 could actually work, then disproved two triples.

Nice stream, thanks! For the record, I took the other way around the puzzle 😀

That was highly enjoyable puzzle, I love the way it sort of "keeps its momentum", i.e. once the solve is under way there's no point at which you "...the Hell I do now?", but there's always stuff to investigate. And I DO love a symmetrical grid, it tickles my brain in all the right spots.

i just started watching this having solved the puzzle previously, and I want to say that I solved the ten line that's mostly in box 3 early. I'm curious too now how Simon will do it. Great puzzle by the way. I very much enjoyed it. Edit: I thought about that 10 line differently again, by the way. I reasoned that the two "halves" of the corresponding GW were either 127 or 389. For the 127 half, you had to start the ten line with 46. No 3-cell or 4-cell option works because 345 is already more than ten. Obviously there's only one option for where to put the 46 pair. The other four cells can't be a pair of 2 cell sums, again for obvious reasons, and can't be 3-1, so it's a 4-cell sum. Which has to be 1234 for the reasons that Simon laid out.

Really enjoyed this puzzle - the first zetamath that I solved quicker than Simon!

This was my first zeta puzzle that I solved on my own. Seems fitting that I would solve it the opposite way you intended. I indeed did solve it counterclockwise with that 10 line eye as the very last deduction. I even thought I broke the puzzle for a good minute or two when I didn't consider a 1234 possibility. I've always enjoyed your puzzles, I just usually need a hint or two on the breakin on your "very hard" puzzles.

I made this puzzle far harder for myself by not completing r1c2/3 after I got r1c1/4 and by putting an incorrect 34 center pencil mark into r9c2. I spent so long thinking the bottom left grey line had to be either three 2 cell sums or two 3 cell sums. Coming into box 7 from box 8 I ended up having to brute force it to find my pencil mark mistake. That would have been easier if I didn't miss finishing the whisper line since the only layout I would have thought was possible when solving that box was the three 2 cell sums. I wouldn't have even known I had missed finishing that whisper line if I hadn't watched Simon's solve. It was a beautifully set puzzle that I made a mess of >_

do you (or other setters you might know) ever intentionally set a puzzle with a 3 in the corner just to make simon happy?