zetamath sudoku stream

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00:00 Pre-stream
04:18 Greetings
Puzzles done this stream:
08:36 "Coral Creek" by Jay Dyer
Logic Masters Germany: logic-masters.de/Raetselporta...
SudokuPad (conv.): tinyurl.com/d9d45vsc
Divide the grid into ominoes (regions of orthogonally connected cells), so that no two ominoes of the same size share an edge. Each cell contains a number equal to its omino's size.
Shade some cells so that all shaded cells are orthogonally connected, all unshaded cells are orthogonally connected, and no 2x2 is fully shaded or unshaded.
An arrow in a cell indicates that the omino pointed to by the arrow contains N shaded cells, where N is the number in the arrow's cell. An arrow may be in the same omino as the cell it points to.
1:47:08 "Ouroboros" by zetamath
Logic Masters Germany: logic-masters.de/Raetselporta...
SudokuPad: tinyurl.com/4pauc7n4
Normal sudoku rules apply.
In the grid below, you are to shade squares to form a single closed loop that is 1 cell wide. The loop may not touch itself even diagonally.
Within each cage in the grid, the shaded squares and the unshaded squares sum to the same number. As usual, digits do not repeat within cages.
The circled cells contain the number of cells that are part of the loop among the 9 including the cell itself, as well as the orthogonally and diagonally adjacent cells.
2:31:37 "Those Three Residues" by SSG
Logic Masters Germany: logic-masters.de/Raetselporta...
SudokuPad: tinyurl.com/yvwecu5m
SudokuPad: tinyurl.com/yafhaefp
Normal sudoku rules apply.
Modular Lines: Along the line, any run of three digits must all have different remainders under division by 3.
Killer: Digits in a cage may not repeat and must sum to the given total.

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Опубликовано:

5 июл 2024

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Комментарии : 3

@SSGranor 11 месяцев назад

So, first of all, thanks for featuring Those Three Residues. It's definitely one that hasn't gotten so much attention; and, I think it's kind of neat. So, the way I think about the opening is a sort of SET idea. In fact, this puzzle came from thinking about what kind of geometry one could come up with where SET would be very forcing on modular (or entropic) coloring. The way I think about it is actually an unbalanced SET. Compare r1369 to c24578. All seven purple digits are in the first group and all other digits on the line are in the second, together with, after cancellations, exactly 10 cells that aren't on the line. From the unbalanced SET, we know that the second group will be exactly first group plus one set of 1 to 9; so, it will need to include 10 purples - the seven you found from the SET you did plus r457c7. As for your broader comments on SET, I can definitely see how it's not been a totally positive thing. I do tend to think, though, that, used well and in moderation, it has a place in the construction of good puzzles. FWIW, Archers on the Quad - the arrow/quadruple puzzle of mine you mentioned at the end - was also built on a SET idea. In that case, SET isn't needed to solve it; but, I definitely would never have though to construct a puzzle that way, if _I_ didn't understand the SET implications.

@SSGranor 11 месяцев назад

Meant to also mention that I sort of agree that the killer stuff towards the end came out a little tougher than I'd hoped. It's the trade-off that comes of wanting the cages to not provide much help until you can work out what the geometry is doing. That's why they're all pretty middly (and, incidentally, why it was a much more natural thing to do this with modular, rather than entropic, lines). The intent was for the solver to need to understand the modular consequences of the cages in order to be able to come around to understanding the actual values of digits. I do think that's what happens here - and that that, in itself, is pretty interesting - but, that's also how you end up needing to do a bit of secondary coloring to find the relationship between the digits in the 12 and 20 cages. (I'd have to look more carefully to see if you cheated at all on the secondary coloring; but, at least the relationships involving the digits in those two cages were correct and actually pretty straightforward to prove if you're looking for them.)

@zetamathdoespuzzles 11 месяцев назад

Even if the resolution was a little messy, it was well worth it for the very cool discovery!