Thank you for the video and lesson. It is interesting how to wire up the oscilloscope to test the Sallen-Key circuit. I will take a look at the Pico Oscilloscope and see if I can do HF circuits with it.
Wonderful ! Thank you. I needed to figure out how to do the rail-to-rail wiring. And it is a Sallen-Key !! Wonderful. But I need component values for 14 Mhz.
Doing Level 3 electrical installations and found this very useful and even gave a more in-depth look at this problem. different yet similar calculations. always a joy to see different methods to work out one question as this gives more understanding of this question. Thanks for this video. still useful 5 years later. that's one of the beauty of maths.
First i wanna say sorry, i can speak a little english.. i have a question.. the question is wt if the branch which included the capacitor was in the middle (the place of the other branch) is it the same? I mean nothing will change or wt?
It doesn't matter what order the branches are in here. So if the middle branch is the capacitor, and the right-hand branch is the resistor-inductor, the method is the same.
Excellent video! I would advise anyone trying to set-up 'bias' on a transistor to get your self a 'transistor-checking' meter!These are not 'horribly' expensive and they will give you the 'pin-out' of the transistor(EBC).The meter will also give you the (gain='hfe') of the transistor, which is important for (Audio-amplifier) circuits'.eg.fuzz-box,guitar,or guitar-amp,etc. The other piece of information the meter will give you,which is probably the most 'important',is that the transistor is 'NPN',or 'PNP',which are 'biased' differently!
So we have 4 different currents flowing in this circuit. The mind blow for me is WHERE do these currents transition from one to another. For example, exactly where does I(T) at 2.07A @(-15.38 degrees) transition to I(R) of 2.0A @ zero degrees? I have no problem with the calculations, but I can't visualize how/where these currents interact and morph in the wire. Any help would be greatly appreciated. Any help would be greatly appreciated.
Conceptually, it is not so much that there is a "point" at which one current / angle morphs into or becomes another, but rather they are all happening at once, superimposed upon one another.
Hi. For example 3, when you substituted the imaginary component of m in for Beta, why did you disregard the negative imaginary component? Surely you could sub in - sqrt(11)/2 and achieve a completely different but valid answer? (great video btw)
Yes - if you right click on the flipflop to open the Component Attribute Editor, there is a box for "SpiceLine" where you can enter a custom entry for the parameter "Vhigh" (output voltage when high): so you can type Vhigh=5 to make the output voltage 5V for example.
Am i first here? That was an excellent tutorial. Thank you. I am trying work out if my condenser design is enough to cool my distilate. Suprised the efficiency of counter flow is 30% better. Thank you. 🙏 ah.. an now i understand why my heat exchanger becomes less efficient as the temperature incresses as more alcohol is lost.
Great video. Since multimeters and clamp style current meters are ubiquitous and can easily measure RMS voltages, currents and resistance, would this be a "practial" approach? Measure the resitance of the coils in the motor, and then measure the voltage applied to the motor. Then, take a clamp style meater to measure the current drawn by the motor. With V and A, we can calculate apparent power (VA). With the amps and resistance of the motor, we can calculate real power. PF can then be computed.
I've been struggling to understand RLC circuits since I took differential equations 3-4 semesters ago. I didn't find any luck with my book, lecture, or other youtube videos. This video made me really understand what's going on. Thank you so much!
That was brilliant! I put the simple question into YT and out this vid popped. I knew nothing a few minutes ago and now I totally get it. Thank you very much. 🙂👍🏴
Hello, I know this is a late comment, but if you see this, could you please tell me how you proceed for a 4th input? 'Cause based on the rule of halves, the D input column cannot be divided by halves, since there is no group of 0 and 1 anymore. How do we proceed then? Thanks in advance, you already helped tremendously!
If you had 4 inputs, there would be 2^4 = 16 possible combinations, and you can still use the half and half rule to generate all combinations. So in this example it would be 8 1's and 8 0's for the first column, followed by groups of 4 for the next column, groups of 2 and then groups of 1.
you explanation are easy to understand. just one question, at the IRL part where V/ZRL. why did Z become 100V at an angle of 0 instead of 100V at an angle of 50? or is it that the 50 is a frequency and it does not affect our angle? thank you.
Amazing video, very clearly explained. Thanks so much (my lecturer was not clear at all, and I was convinced it had to be simpler than he was suggesting.. very glad it turned out to be true!)
It is amazing to find exactly what you are looking for on the internet. Btw great video. Had a small confusion, and it was stuck in mind, calculating the sheer for angular component of bar. I've been having nightmares as I couldn't satisfy my mind with any answer. Finally, watching someone with the simplification process, my mind is ready to accept the obvious. 😅
