I wish you luck on taking your exam, I will be taking me shortly as well. Whoever made this practice test did a horrible job, I would look at other means of practice tests to better prepare for the exam
I've been studying on and off for like a year now, and finally made my test reservation for tomorrow. Here's to hoping I pass before the 601 is retired! 😅 Edit: I passed!! Time to pick my next cert...
Awesome video! Appreciate your use of the binary 1s and 0s to get the subnet mask or CIDR, it made that part of subnetting really easy for me. Didn't think of it that way. Thank you Vincent!
@@bread_yt93 Flag questions you do not know and do them later, do PBQs last. I gave an answer to every question, even if I did not know what the correct answer is. I also did all the practice exams on ExamCompass and watched all of Professor Messer’s videos + Cyberkraft’s example PBQs.
Here's a mnemonic I came up with for the 802.11 wireless network standards for anyone else that might be struggling with this: 2.4 GHz networks: b, g, n, ax (Bears Go Near AXes) 5 GHz networks: a, n, ac, ax (Angry Nerds ACquire AXes) this won't help with the speeds but just knowing which ones support 2.4GHz and which ones support 5GHz should help with a couple of questions. Good luck to anyone taking the exam in the future! And thanks for posting this video Vincent, I found it really helpful to hear your thought process.
It's particularly annoying to me that you decided to leave your camera on and in the corner for what we need the whole screen for. We really didn't need to see you reading and smiling during the PBQs. Still helpful. Thanks for posting.
Question 30: Class C doesn't imply classful, it just means the subnet is starting at /24 or binary 11111111.11111111.11111111.00000000 the "." are placed for visual purposes only. So in order to make at least 6 network you would have to subnet to /24+3 or /27 since 2^3=8 additional network. So you final binary will be 11100000 = 224 and full subnet mask 255.255.255.224
Question 13: Hexidecimal Math 8 4 2 1 note that max is 15 = F lets try 11 = B; since we used 8, 2, & 1 = 1011. The numbers goes from 0-9 then A-F because you can not represent 10 using two digit 1 & 0
I'm switching from the psychology field to IT after some traumatic experiences I went through. I don't know where to begin. I'm hoping to learn stuff from your videos. If you have any tips.. I'd appreciate the help. I have taken the Google IT Support Specialist Technician cert but I had a friend tell me it's not enough to help me get a job. :c which was sad for me. I'd love to talk to anyone about this.
The part of question 3 of PBQ 3 that you got wrong is annoying, they need to explain which spot they want the subnetmask and gateway address instead of just putting 2 blank lines with the same choices for both.
he spent so long on the binary to hexadecimal portion, i feel so bad for that homies need to know that you group binary numbers by 4s (which the question already did), convert each 4 into 1 hex, then concatentate them to get the hex. you can get really good at this once you practice your binary to hex table
18:32 that is not what an ARP poisoning attack is. ARP is unsecured and broadcast based. Unsolicited (Gratuitous ARP) messages can be sent and cached for things like the default gateway. Please take this opportunity to make an update video
time segment 15:28 your explanation of buffer overflows needs a LOT of help. You said that you don't know and then offered an answer that is pretty off base. This creates an opportunity to add a "click here" dialog for an update video.
I watched Prof Messer and did some practice questions and passed with that alone. People always reccomend to read material but I havent needed to for any college classes or Certification yet. Maybe I will need to for Sec+ who knows.
Out of 25, 11 correct - 14 incorrect. I am preparing for s+ and I am feeling like just hit by a truck. Man, these questions were hard and tricky. I agree the questions were not clear and bit enough explained but still tough to answer.
I've just finished 3 courses on my 4th, basic computer cert, computer and network technology, administration of server and network equipment and now I am doing a support course with helpdesk basics, and then I will do one digital communication course and another network administration course and after that I will see if I do more or jump into work. i've been waging blue collar on the factory floor and warehouse since I flunked out of HS so 7 years now and I hope this can be my way to escape to white collar work. Also helps I used to build and sell computers and always been using them all the way from dads old windows XP desktop to now so i'd like to think I have a shot at changing up my life with this.
For anyone who was stuck on the binary and decimal part here are a few things I like to keep in mind that may help. My understanding portion Hexadecimal = Hex(6), decimal (10), six over ten, so keep in mind there are 16 digits we have to pay attention to. From 0 - 9, we can count it normally, the only difference is in 10 we convert to A and keep going to 15. For example 0,1, 2, 3, 4, 5, 6, 7, 8, 9 ---> (Alphabet now) 10(A), 11(B), 12(C), 13(D), 14 (E), 15(F), we don't go up to 16 because we started at zero. From this we now understand two things, the numbering system in hexadecimals (1) and it being 16(2). Hence, we use this understanding of it having a base 16, to our advantage in decimals. Meaning if we want to convert a decimal to hexadecimal we need to divide it by 16. Binary = Binary (0 or 1), keep in mind for decimals they use the power of 2, because it's base 2. This is all the information we need to start our conversions. Solving portion Binary part: 1100 0100 Since we're using base 2, we'll use the powers of 2 to solve this (respectfully for each part). 2^0 = 1 2^1 = 2 2^2 = 4 2^3 = 8 (This is all we need to solve this problem here, and keep in mind if there are more numbers you keep on going: for example if it was 111100, you'd go up to 2^5) 0's mean off, so we don't need to add those parts in, only the parts that have a one to it. Because of this, we get 4 + 8 = 12. So lets organize all of this together. Binary : 1100 0100 (Go from right - left, not left to right) 1100 = 4 + 8 = 12 0100 = 4 Now to convert it to hexadecimal we keep in mind what we learned earlier, 12 = C, so we put C. 4 isn't that high so we keep it 4 (only converting pass 9). Giving us: C4 Decimal part This part requires less work and if you've ever programmed you'd notice it's quite similar to the % operator (remainder). Since we understand that hexadecimal is base 16, we divide whatever the decimal is by 16, here in this case it was 196. 196/16 = 12.25 16 * 12 = 192, meaning we're left with a remainder of 4. So out of this, we have two important numbers the 12 which we got from dividing, and the 4. We convert the 12 to hexadecimal which is C and leave the 4 alone getting C4 lets do another problem, lets say it was 230. 230/16 = 14.375 16 * 14 = 224, we need six more to get to 230, meaning the remainder is 6. We have two important numbers the 14 and the 6 giving us: E6
Thank you so much for this when I took my A+ I think the only way I passed the core one and core two on the first try is because I nailed the PBQs because I don't think I did so hot on the multiple choice questions and when I failed the Net+ the first time it is was because despite feeling like I did great on the multiple choice I did not do so good on the PBQs. I got the Sec+ coming up and this will help a lot.
What I like is how you've left yourself vulnerable to making mistakes. Practically everything you got wrong, I got wrong too and was forced back to the training materials to fill in the holes in the knowledge. Thank you for allowing yourself to be not only this helpful, but also this open. My upcoming Network+ exam now seems more like a storm wave rather than a tsunami at this point.
For binary to decimal, don't separate the bytes. binary is base 2 meaning instead of ones, tens, hundreds place, you use 1,2,4,8,16,32, etc so a 00000001 = 1 in decimal, 00000010 = 2 and so on, each step to the left is doubled. So you plug in your binary chart and add the decimal value of all the ones together. Here's how you'd get convert that binary number to decimal: 1 | 1 | 0 | 0 |0 |1 |0 | 0 128 | 64 |32 |16 |8 |4 |2 | 1 -> 128 + 64+4 = 196 Now to convert decimal to binary, you divide the number by 16. What you get from that is your first digit. Then if the remainder is divisible by 16 repeat for the next digit. If the remainder is not divisible by 16 then the remainder is your last digit. (hard to explain but example below should make it easier) hexadecimal digits: 123456789ABCDEFG 196 / 16 = 12 r 4 -> 12= C so first digit is Converting hex to decimal ( this part will help you understand hex better even though the question isn't asking for it): Hexadecimal is base 16 so 1 - 16 in decimal = 1=G in hex, the difference between hex and binary is that each digit means 1-16 instead of multiples of 2, and each digit is the power of 16 (except the right most digit which you just translate to decimal) then, each power of 16 is added to go from hex to decimal. In other words, C4 = 12 x 16 + 4 = 196
From my experience with the Network+ exams at least through pearsonVue the PBQs are a lot harder than this. I have to troubleshoot the system and Certmaster is not good with teaching you how to do that at all. Its great for understanding how things work but can't find anywhere to practice troubleshooting a network. Do you have any recommendations on where I can do that?
