I've seen some places when calculating the mean of the squared differences, they divide them by 1 less than the amount. So for your example, it would be... 9+4+1+4+16 / 4 = 8.5 = 2.9 Why would they do that?
Thank u bro im trying to get in geometry for 8th grade and my stupid book doesnt teach me shit about this. Finally get tk be in a class w my friends cuz of u
3:17 you said the last door the host left for you. But what if he left you a goat? Its still equal. Your only focused on probability of winning and not probability of losing. The host that opened 98 doors didnt leave you the car, he left you a choice. And the choice is still 50/50 If he left you the car then switching is good. But who knows if he left you a car or left you a goat When he opened 98 doors Your 1% chance goes up to 50%. Not 1% to 99%
Assume you stay with your first pick. If your first pick is Goat A, you get Goat A. If your first pick is Goat B, you get Goat B. If your first pick is the car, you get the car. You only win 1 out of 3 games if you stay with your first pick. It's just basic math/logic kids understand.
Dude, look at the image that has 3 doors and a car behind a door. Doesn't matter which door the car is behind. This is a graphic that illustrates the 1/3 probability of where the car is. It is also the 1/3 probability of ALL that can occur. Either the car is behind Doors A, B or C, each image represents 1/3 of the time what can happen. So together these 3 images represent all the possible scenarios that exist before you make the pick. Now for some reason, these cult members suddenly decide they don't know what each image actually means. It actually means 1/3 of the time, the car can appear behind a door. But here's the important part; it also means 1/3 of the time, the car will not be behind BOTH the other TWO doors. Not 2/3 of the time the car won't be behind the other two doors; it is 1/3 of the time. These guys see 1/3 of something and 2/3 must be ANYTHING else. What does all this mean? It means each car door has the value of 1/3. Each goat door has a value of 1/6. Once you see this, you'll understand where they've made the mistake. It's quite simple, isn't it? Bottom line - Monty Hall Paradox is a 50/50 GUESS to stay or switch for the car. You're welcome.
Assume you stay with your first pick. If your first pick is Goat A, you get Goat A. If your first pick is Goat B, you get Goat B. If your first pick is the car, you get the car. You only win 1 out of 3 games if you stay with your first pick. Switching means the opposite. It's just basic math/logic kids understand. Sadly, it's far too hard for idiots.
@@TristanSimondsen "You and 2 friends have a chance to win a car. One of your friends drops out of the contest. What’s the probability of you winning the car? Should you always say your friend has the higher probability because 2 is better than 1?!?" lmfao at your stupidity. Your stupid friend, that drops out, had a winning chance. The door that the host remove, never has a winning chance. Let's say that a few second later, your friend decide to return to the game. He has a 1/3 winning chance, right? Let's say that a few second later after Monty Hall open a goat door, he close that door. Does that door has a 1/3 winning chance?
explained it better than my professor ever could. goes to show how low the bar is for college professors, they're basically making their students teach themselves the entire course then acting like they contributed to student comprehension
Hello I’m watching this video a few years after it’s been posted. I have an observation regarding the units you provided for the example: $21, $50, $62, $85, and $90. When I went through the calculation the standard deviation comes out to 25.04. How did you reach 28.01?
is there a program that i can plug numbers in and it figure out the answer for me. is there a calculator function for calculating the law of large numbers?
Not a fan of explanation videos but this one does a fantastic job. Love the idea of having these random questions in the middle of it. Helps you grasp the material a lot better
Wait, the Gambler's Fallacy and the Law of Large Numbers contradict one another. You can't say that according to the Law of Large Numbers that the results of tested outcomes will inevitably approach the theoretical probabilities the more trials take place, but then say that you're not more likely to achieve outcomes that have shown up less likely when there's been a significant portion of trials resulting in only one or a few outcomes. You can't say that things are guaranteed to balance out overtime, but then also say that they won't. In reality, it is a matter of independent and dependent variables. While the independent states that each individual event will have the same odds no matter what (ex. flipping a coin is always 50/50), the dependent states that the odds of particular outcomes in a sequence of numerous trials can be predicted through the results of previous events (ex. flipping heads 10 times in a row isn't 50%, but 0.1%).
