共通因数でくくる方法もあるけど、右辺を左辺に移項させて、両辺に(x-1)をかけると、x^6-1＝0となり、x＝1以外の複素数解になりますね。 ここで複素平面上に半径1の円を書いて、ル·モアブルの定理より、中心角がπ/6の正6角形を書けば、自ずと分かりますね。

The sum of the digits in the numerator is 1*7+0+8*8+1=72. 72 is divisible by 9 without a remainder. Divide the numerator by 9 and get a number equal to the number in the denominator. As a result, we get the square root of 9*1, and we get 3. Magic? No - mathematics.

1^x + 2^x = 4^x x = ?

stupid at all.

15×15

My answer is: 8/3 or 2.6`....

It is not correct. Where is check?

Мне тоже кажется что решения у этого уравнения нет

How did you find such a slow method?! The method described by many of the comments is much quicker.

I think you'd get more positive feedback if you offered this as an alternative solution and do quadratic in method 1.

Your method and solution are so intresting!! Wish you the best 🙂

What is a real life situation that this is useful knowledge?

Shouldn’t there be a total of six roots. You only have 2 real plus 2 complex.

Шикарно! Дякую! Клас!

that is impossible solve..

sq root of 96/ sq root of 30

X = 1 is also possible

Good solution ❤

This solution made not for school level. University's level. Task is easy if you know about immanent i^2=-1 else have not solution

Very nice🎉

X=4

Очень интересное решение, спасибо

1

using method 2 - and do not go to base 3 - but base 81. Faster - less steps. sqr( 3^x * sqr(9^x * sqr( 81^x ))) = 81 3^x * sqr(9^x * sqr( 81^x )) = 81^2 9^x * 9^x * sqr( 81^x ) = 81^4 81^x * sqr( 81^x ) = 81^4 81^2x * 81^x = 81^8 81^3x = 81^8 3x = 8 x = 8/3= 2 2/3

Fantastic explanation

благодарю!!!!!!!!

Simple way is to keep squaring up n equating powers of 3 instead of such complicated route of fractions.

Заморочка! Не ломайте голову!

Вот так сейчас пудрят мозги нашим школьникам. Пора вернуть советское образование, где коротко и ясно.

I directly put -1 and got the correct result without any calculation

X=-4

X=5

X=-1

WHY NOT ASK CHATGPT TO USE DIRECT COMPUTATION AND ALGEBRAIC METHOD. NONE AS DIFFICULT AS ABOVE METHOD.

La décomposition en nombre premier de 1680 c'est 16*3*5*7, comme c'est le produit de 4 entiers successifs, entre 5 et 7, il y a 6 si on divise 1680 par 5*6*7 qui vaut 210 on obtient 8 donc 1680 = 5*6*7*8

-1 (real value).

Làm sai từ chổ o mà chia cho -1

Kya bakwass hai yo seedha asnwer ara iska binomial se

Ужас... Тот случай, когда из мухи делают слона.

等比数列の和という概念にたどり着けてない。。

Do have maht adulation besayd school?

good way to make money

it's homework for basic level students, sorry 😢

Professor, não seria mais fácil descobrir o valor do logaritmo X ao cubo = Y calculando a equação de 2° grau utilizando a fórmula de Bhaskara?

I could do this, if necessary, as I was taught long multiplication in primary school !

Can you solve this? I saw it uploaded on 4chan but it got deleted before getting solved solve: y = -9/8 - 7/8x -4 x + 9 y = -22

2^(1/3)😅😅😅