In person, direct explanations of chemistry principles. This covers general college chemistry, AP chemistry, IB chemistry and high school chemistry. This is my 12th year teaching high school chemistry, 3rd year as a chemistry adjunct professor at a state university, and I previously taught laboratory chemistry at a Pac-12 university for 6 years. Prior to teaching I was an organic chemist at an environmental laboratory. Watch and understand chemistry!
Please anybody here working on theoretical quantum mechanics that can help me with information and benevolent enough to help me with research and guidance. Will be grateful
Hi Chimasunday, I hope someone responds that can be helpful. I am sorry I cannot be of much help. That is outside of my wheelhouse. I am proud of your great efforts!
Yes, cyclohexane and benzene are different. The number of hydrogens are inferred by the types of bonds that are drawn. I do have videos on benzene rings if you are interested. Thank you!
I love how you actually seem to enjoy teaching. Very hard to find that nowadays. Thanks for everything and all the videos😊I’m sure you’re a wonderful teacher!
I just wanted to come back once again and thank you for all of your videos. I had mentioned in one of your other videos about me failing Chem 2 in the Spring and having to re-take it this Summer. I spent my summer break watching your lectures and really trying to understand the concepts AND YOU HELPED ME GET AN A! Now I'm in Orgo so I will continue to be your biggest fan! You're amazing, thank you!
Vanessa! Look at you, Miss I got an A after failing. You are AMAZING! I am so proud of your grit and hard work. Remember what you did this summer; you can do anything . I am so grateful I could be a small part of your journey. Thank you for watching. Way to go girl!!!!!!
For stability it favors the octet rule. Thank you. www.google.com/search?q=in+nature+does+xeo4+have+an+expanded+octet&rlz=1C1GCEA_enUS1071US1071&oq=in+nature+does+xeo4+have+an+expanded+octet&gs_lcrp=EgZjaHJvbWUyBggAEEUYOdIBCTExNTgyajBqN6gCALACAA&sourceid=chrome&ie=UTF-8
If pentagonal carbon atom arrangement in the skeletal structure is possible, then a square of c's structure is also possible☺️ I doubted my answer at first😆tnx for the video ofr clarifying it😅
Nice According to the Maxwellian speed distribution, As the Temperature increases the Number of molecules with speeds within a small interval near the most probable speed: Select one: a. increases b. be constant c. decreases What is the correct answer, Doctor
Hi Chungachisenga, Here is a video on using partial pressures to determine the equilibrium constant. I hope this helps. Thanks! ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-L38q-4tQxOc.htmlsi=7RgDIdodPKWLq7nP
Hi Diksha, I am so glad it was helpful. Thank you for commenting. I appreciate your compliment too, thank you. God bless you and sending love to you in India!
Hi Dinakhaled, Here is a great explanation from Google. Thank you for your question:) www.google.com/search?q=why+does+xenon+form+compounds+if+it+has+a+full+octet&rlz=1C1GCEA_enUS1005US1005&oq=why+does+xenon+form+compounds+if+it+has+a+full+octet&gs_lcrp=EgZjaHJvbWUyBggAEEUYOTIHCAEQIRigATIHCAIQIRirAjIHCAMQIRirAtIBCTE0OTgyajBqN6gCALACAA&sourceid=chrome&ie=UTF-8
Is that posible to record absorbance data greater than 1 during OD reading in spectrophotometer? because lambert beer law describes that absorbance greater than 1 can not give you straight line.
The absorbance is read on the spectrophotometer. It comes from the wavelength of the light absorbed which the machine reads as transmittance, and then is calculated to absorbance. Maybe I misunderstood your question. You may want to ask your question to your professor so they can clarify. Thanks!
You are seriously the best teacher I have ever seen when it comes to this subject. Honestly the best !!! Thank you for already answering my questions like if you were reading my mind. I absolutely understand now and make sense rate reactions. You seem just not a great teacher but a wonderful person as well. I wish you were in California. Blessings to you and your family.
Hi e.m.ye.m.y, THANK YOU for your kind comment! I wish you were my student:) I am so pleased the videos have been helpful. God bless you in beautiful California.
What is the mobility of the K and Cl ions inside the bridge? Can the bridge be so slow to create a charge imbalance , at least in the initial transient when the external circuit is closed on the load? What I am curious about is if there can be a temporary violation of Kirchhoff's current law due to accumulation and rarefaction of charge at the bridge extremities. (Left side releases K ions near the left end, right side releases ions near the right end, but no net current can be measured by a clamp ammeter in the middle of the bridge. Only when the charge imbalance passes a certain threshold the electric field causes a drift current in the mid section - has this ever been observed?)
Hi Copernicofelinis, excellent question. Honestly, I do not know. At the general chemistry level we assume it is instantaneous and a non-issue. In real life, I do not have an answer. I suggest you ask your professor for their thoughts as well. Thank you for the great question!
@@OldSchoolChemistry considering how many years have passed since I last talked to my chem prof, it is safe to assume I would need a seance to ask him the question. And since he was a stubborn atheist, he would probably not answer even if he could. I would do the experiment myself, but nowadays it's easier to buy a semiautomatic rifle than a chemistry set... I think I would need three to five cells to give a strong enough (near short circuit) current to be read by a clamp ammeter on the middle salt bridge. And it would probably need to be a current probe attached to an oscilloscope because the transient could be just a few tens of microseconds... It would be epic seeing KCl breaking KCL, tho. Anyway, thanks for taking the time to reply, and kudos for your tutorials: they are a joy to watch. I love your enthusiasm.
Hi Hashemlafi, we do not include water because it is in the liquid phase. We only include aqueous and gas phases in the equilibrium expression. Thank you for your question!
@@OldSchoolChemistry Thanks for your help ma'am 😊 I forgot that we don't include them in the equilibrium expression. Either way, my question didn't make any sense because the formula has to be balanced in the first place. So when I asked whether it should be divided by [H2O], that was just wrong because it has to be two molecules of H20 in the reactants.
