Another useful way you can view question 3 is by simply multiplying the molecular weight by two(136.09 x 2 = 272.18) so that you can see how much grams would be in a 2L solution to that is 1M, and then divide the given numbe(83.7) by your new 1M gram total(the 272.18) to get the same answer but in less steps and thinking.
Your way of teaching is very good but you have to enhance your video-making techniques. Most of the things are skipped when you change your camera direction, moreover, your hand also covers the whole content on the paper, this is creating difficulty in understanding the lecture.
Hi ma'am, very helpful thank you. Does this kind of dilution (ie. starting from a stock) count as serial dilution? Or is serial dilution only when you keep decreasing the concentration by a set factor. Thanks in advance.
I am so glad to study in Glasgow Uni and waiting to meet you in person, I would like to know what is written in the board in the back side about Phd, this is what I am planning to do next step, Thanks a lot for your lovely explanation
I really need to thank you for this tutorial, a total of about 6 years in school and counting. I lost confidence in myself until I came across your video today. Thank you so much.
Dear Madam, this is my Email : moukwele_njemba@yahoo.com. I will like to contact you directly by Email. Best regards, From Cameroon Moukwele WhatsApp : +237699932619