Thank you for these videos, my question is how do you know that you need to calculate the torque to make the motor turn at a constant speed, and what makes this condition be the maximum speed?
Brilliance. You have made this concept crystal clear to me. The reveation that the segment of 48:30 to 50:26 has given me, has sincerely made my day. Thank you for ending my confusion spiral. God bless you.
Firstly, thank you very much for the videos, I didn't give enough attention to these topics in time and now I realize that I need to study more and your videos are very helpful. One point I am confused is that at 18:26 you said that as theta_y goes to zero, normal vector will point towards y. However, this also implies that y component goes to zero. As we have F_y = F.cos(theta_y), actually theta has to go ninety degrees so that we will eventually have no F_y component. Am I thinking wrong?
Over the years, I've studied numerous video compilations devoted to GD&T but always gravitate back to the TheBom_PE series. Anyone interested in learning GD&T from scratch should watch this video series in order and read Chapter 20 on GD&T in Shigley's Mechanical Engineering Design. I cannot think of a more thorough and comprehensive starting point.
Over the years, I've studied numerous video compilations devoted to GD&T but always gravitate back to the TheBom_PE series. Anyone interested in learning GD&T from scratch should watch this video series in order and read Chapter 20 on GD&T in Shigley's Mechanical Engineering Design. I cannot think of a more thorough and comprehensive starting point.
Over the years, I've studied numerous video compilations devoted to GD&T but always gravitate back to the TheBom_PE series. Anyone interested in learning GD&T from scratch should watch this video series in order and read Chapter 20 on GD&T in Shigley's Mechanical Engineering Design. I cannot think of a more thorough and comprehensive starting point.
Over the years, I've studied numerous video compilations devoted to GD&T but always gravitate back to the TheBom_PE series. Anyone interested in learning GD&T from scratch should watch this video series in order and read Chapter 20 on GD&T in Shigley's Mechanical Engineering Design. I cannot think of a more thorough and comprehensive starting point.
Over the years, I've studied numerous video compilations devoted to GD&T but always gravitate back to the TheBom_PE series. Anyone interested in learning GD&T from scratch should watch this video series in order and read Chapter 20 on GD&T in Shigley's Mechanical Engineering Design. I cannot think of a more thorough and comprehensive starting point.
Hello, I am a graduate mechanical engineer and I work with SolidWorks. At the moment I am learning finite elements and I am enthusiastic about her lessons. You are the best teacher.
I'm confused by the units of Kb at timestamp 28:38 being MN/m. Isn't the answer 5,546,445,738,000 N/m or 5546 GN/m? Edit: Nvm, I realized 78mm^s is not 0.078m^2.I'll leave this here in the event anyone else comes along and makes the same mistake.
Hello Prof. [ At 8:29 we said current is leaving node 1 into node 2; and so, we defined it as positive got it. Then at 11:01 we said there is current leaving node 2 into node 1]. We defined both to be positive: leaving their respective node. I originally thought this made sense because we are just letting the math work itself out. For every node, if we don't know, just say it's leaving the node. Got it. But then [at 37:40 we said current is leaving node 1 into node 2. Got it. But at node 2 we said if current is *entering because we just said for our node 1 equation it is leaving. That also makes sense]. So, between these two problems, why did we approach it differently? What if for problem 2 we did what did we problem 1 and just kept it positive instead of intentionally defining it negative like we did in question 1? Would the math just work itself out, or would there be a bigger problem? Thank you.
Due to some mental health struggles, (I'm doing so much better now) I'm taking my Machine Design II class into the summer as an incomplete. Its been a time trying to learn everything off of the textbook, and when I get confused random websites and scattered youtube videos. I was struggling HARD with this section for a few days before finding your video. I cannot say enough how grateful I am that this exists. I learn a lot better watching videos, and this is exactly what I need to stay on track to graduate on time. Thank you so much!!!
Can you please explain why we modelled the normal force to be acting at two points? I believe a more accurate representation would be a distributed load across the triangle's base, with a larger normal force towards the right end of the triangle. Love your videos as you explain concepts very well, thank you.
Hello professor, I am curious if you have any insight here. I just finished the halfway point of my MechE degree though a local community college. The only class I did not take there was Circuits I. I will be taking this in the Fall of 2024 at my 4 year. I am watching this playlist over the summer to prepare - thanks for posting! However, here is the actual question: at my actual 4 year, MechE's take their own level 3000 Circuit class - which is different from what the EE's take. I could have taken a general Circuit I class, that both MechE & EE take together, and transfer out. I'm curious if you know what, if any, the difference is between a level 3000 Circuits class is taught through the MechE department vs. a standard circuits I class. I assume they are more or less the same - but clearly there has to be some kind of difference. If you don't know, don't stress it. Thank you for making this great playlist.
I think he made an error on the last discussion of self locking screw, if your required torque to lower the load is positive, it should mean that is a self locking situation (it is not going to be moved by the load weight and the force of gravity), but if the required torque needed to lower the load is zero or negative it means that the load being moved by its own weight is greater that the resistance offered by the friction of the screw, and if the motor is not kept energized and in an electrically "locked" situation the load by itself will make the screw turn and lower itself, I really appreciate these lectures being online and available to everyone, great they share the knowledge.
It’s like music to my ears. Absolutely interesting to listen and maturing of explaining techniques and communication is another level. Fantastic 🧠 Was a FnDT engineer for 4 years… feels stupid being a robot without a deep understanding after listening to you .. Bless this lecturer. 🙏🙏🙏
Nice Videos ! Was hoping CIT ! Thinking of doing a Physics Deg. there. Wondering what I will be missing f/ ME & EE as a Physics Major. I like Machinery & Circuitry. Did EM Drafting for 13 yrs. All 4 yrs in HS I took Drafting + 2 yr Deg. AP. I hate to do Physics and never use the skill again.
Thanks for the support. My guess is that you are not expecting to ever practice engineering in the US. Engineers practicing in the US need to be skilled with both unit systems.
Watching second time. Big respect to you professor. Not only on your knowledge but of course your teaching style and explaining every detail to ones whichis not a nerd or genious like you.
Strange to grasp that both omegas are zero, but both alphas exist when t=0. We should take in consideration following: alpha = d(omega)/dt which means that we need infinitesimal amount of time, in order to define alpha. However, there is no change of omega in time because t=0, but regardlessly alpha exists anyway. So, where alpha is coming from? If we say that rod remains in horizontal position at t=0 and the rope is taut, then such a set up should be treated as a static problem (at this instant). In other words, (massive) rod and RIGID (massless) rope should be modeled as a rigid static form, supported at the point E. Any infinitesimally small passage of time, would cause appearance of both omega and alpha.
Hi TheBom_PE, Hi want to build a platform for keeping 2000 Liters x 2 water tanks. Platform is approx 5 x 10 feet. Pillars will be in brick mortar and I want I beams on it to support load. What sizes of i beam and how many in numbers to use?
I'm looking for information on derivation among the parameters relations of geometry for SAE V-belts Pulley/sheaves. The standard Table is showing the different parameter value but what are relationship among those parameters to find out those value? Can anyone help me to determine the derivation of the geometric relationship by providing a source of information? Thanks.
