The correct option is E because the force exerted to the right by A and to the left by B must be equal in magnitude, but like there is acceleration, the force directed to the right in B must be greater

We need to right the two equations gotten from drawing the free-body diagrams, which gives us option E

First, we need to get the acceleration for both cases, then we must divide them to get the relationship between them, which is 9/5g

R is the only force that shows an example for the third law because it is equal in magnitude and opposite in direction.

The correct option is D because the interaction pairs must be equal in magnitude

The correct option is D because the only force is the one applied to the first block, which is 16N. Like forces must be equal in magnitude, the second block has that force but in the opposite direction.

The correct option is C because the cart is affected by mg, Fn, and Fn form the load. The loans is only affected by mg and Fn

The correct option is D because for it to be a pair of forces, they must act on different objects.

The correct option is C because the forces must be of equal magnitude and opposite direction, Newton’s third law.

The correct option is D because figure II shows the correct direction of the normal and centripetal force and figure IV shows the friction and the gravitational force.

In this problem, the force to the right must be greater from person A. The forces to the left from person B and to the right from A must be equal. And like it is accelerating to the right, the force from person B must be grater than all towards that direction.

In this problem, with the block Ma we have the equation a=T/Ma, which can be substituted in the equation gotten from block Mb. When rewriting this, we get that the correct answer is D

This problem gives us the equation Fn - Mg = m(-a), by rewriting it we get that Fn = M(g-a)

Because of Newton’s third law, they must be equal in magnitude.

When substituting T for 0.6g*M2, we get that the tension is equal to 0.4gM2

When cancelling g, we get that M2/M1 is 3/2 which is equal to 1.5

The top string will break because it’s tension is grater because it supports mg plus the force the person is making.

Because T is only one side of the rope, it means that W is grater than T.

Because the centripetal acceleration always goes to the center, in this case it means it goes due South. The tangential acceleration hours due West because the car is slowing down. This means that when adding the vectors, the final will have a direction of South due west.

The correct option is D because when adding both components of the acceleration we get that the result is 1.5 m/s^2

To get the car’s acceleration, we must use the Pythagorean theorem with the centripetal and tangential accelerations.

Thank you, sir you’re the only one who’s been able to explain it so clearly to me

The answer is option D because when we draw the vectors for the accelerations that are already given we get one directed towards south of west

The answer is D because the problem already gives us one of the components to get the total acceleration, So to get the other one we would just need to use the first formula for the centripetal acceleration, and finally we combine them.

The answer is C because we would need to use the two different speeds to get the components to the tangential acceleration which is equal to the net acceleration we need to get.

Thanks, very much

String C has to be the strongest because it needs to pull Tb (which is the sum of Ta + Ff) plus the force of friction.

In this example we can remember how if we have two objects we need two separate free body diagrams

This video helped me remember that because acceleration is a vector it has components.

The correct answer is option D because we used the acceleration components (the centripetal acceleration and the tangential acceleration) to get the total acceleration.

In order to get the car’s acceleration we need to take in consideration the centripetal acceleration and the tangential acceleration. Once we got those two we had use the pithagorean theorem to obtain the answer, which is option C

Drawing both the radial and tangential accelerations, we can assume that the resultant acceleration is pointing downwards to the left, which is option D

As in the last example, we combine the vectors of both accelerations and get D as an answer.

Here, we have to take both the car’s centripetal acceleration and the one it gets from slowing down. After combining those 2 vectors, we get an answer which is closest to option C.

the correct answer is 20 m/s2 .

The answer is C becaus it is the string that pulls the most mass, therefore it is the strongest one.

The answer is B because when we make equations for gather x axis for each of the blocks

The answer is C because we get the tension of the system by getting the acceleration using the equations for x of the system

the strongest string must be C because its pulling the most amount of masses

using our free-body diagrams we can form our equations and combine them and get the acceleration and later use that to find the tensions that give us the answers in option B)

using both object's equations the tensions cancel and the masses add up so you find the acceleration therefore you are able to get the tension which is answer C)

Option C, the C string must be the strongest because it is pulling the most weight

After combining the 3 equations in x and combining them to solve for the tensions in terms of the force, we get option B as the answer

Using the x equations for the forces on both blocks and combining them, we can see the acceleration of the system, after which we can solve for the tension.

The correct option is B because it is the only one that states Newton’s third law regarding the correct interaction pair forces (R) of equal magnitude and opposite direction

There is no friction, so the force applied on the truck is the net force and is calculated with mass*acceleration. That is 8 000 N, so the interaction pair (F t/c) must be equal.

The force applied on Y by X is the same as the one applied on X by Y because they are opposite pairs. F x/y can be calculated by F = ma, so both of them are 16 N.

The correct option is E) because both T's are of the same magnitude and opposite in direction and they're smaller than the applied force

In the system the acceleration is only one. We derive our equations and use the elimination method were the T is cancelled and you are left with (M-m)g=(M+m)a, so when you solve for a you get answer E)

In the first case when we make our free-body diagram and our equation we get that the acceleration is 1/3 of g. In the second case doing the free-body diagram and equations we get that the acceleration is 3/5 of g. When we divide our second acceleration by the first we get option D)