In this channel we teach Mathematics, Physics and Chemistry for Secondary (College) Students. We give special tutorials for those preparing for exams like IGCSE, SAT, WAEC, UTME, and other related examinations. We will be treating past questions for these exams so students can have solid background on how to answer questions when they sit for the real exam(s).
I found the video ponderous and long-winded. Just immediately factor to (sqrt(x)-6)(sqrt(x)+1)=0, therefore surely x=36, and the second factor yields nothing.
Just substitute t=sqrt(x) and solve like a normal quadratic, from t^2-5t-6=0, u get t=-6 or 1, take t=1 as square roots can't be negative, thus t=1 & hence x=1
