A lead shot is projected from ground level with a velocity u at an angle θ to the horizontal.Given t 

A lead shot is projected from ground level with a velocity u at an angle θ to the horizontal. Given the time t for the lead shot to reach its maximum height t = usinθ/g, where g is the acceleration of free fall due to gravity, show that the greatest height reached by the body hmax = (u^2 〖sin〗^2 θ)/2g.