Welcome to learn channel - our Engineering Tutorial Video Channel. Topics covered: Automation, Electric engineering, Robotics, Hydraulics, Pneumatics, Electric motors, Closed-loop controls and soon will come more. Our videos are animations from topics what we teach as profesors. Comments are welcome!
Please note: 1. Can I upload videos from learnchannel to any other network? No - please note the RU-vid-copyrights. We remove all illegal uploads (especially from Facebook) by contacting the respective network. 2. What about sharing our videos? Yes please! We encourage you to share our videos and put them in your Playlist.
Our official website: learnchannel-TV.com Facebook: facebook.com/Learnchannel-TVcom-1744238709207184/ Contact: info@learnchannel-TV.com
How to calculate how many tons of pressure a hydraulic unit can produce? I want to use it in a cylinder of a plastic hydraulic injection molding machine. The cylinder is 25cm x 70cm
Pressure gauge motor cylinder with piston crank case connection hose tank water tank drain inlet filter compressor pressure coil electric ampere generator oil red inlet valve diaphragm crank shaft piston output valve lubricant main rotor sliding vane grooves in fan protected teacher ji
Saludos LEARNCHANNE excelente su explicación ,muy bien analizado desde el punto de vista teórico/practico , quería realizarle una pregunta: Tengo una bomba de agua de 2 hp/1,5 kwatts /60 HZ ,Motor de induccion con capacitor permanente, aunque por lo general segun tengo entendido la bobina de arranque da mayor resistencia que la bobina de trabajo, en este caso ambas bobinas de arranque y trabajo indican la misma resistencia (1.8 ohmios), esta bomba la encontré con su capacitor quemado,chamuzcado y se borraron toda la información técnica del capacitor. Buscando información en el comercio de esta bomba, me indica según la placa técnica que debería de ser 90 microfaradios (esta bomba tiene doble impele), pero hay otra bomba de la misma debería de un solo impele (usa un capacitor de 60 microfaradios). Me refiero a una bomba Pearl. Me podría asesorar con respecto al valor real de las dos bobinas y cuál sería la capacidad real. LAS BOBINA ESTAN AISLADAS CON RESPECTO A LA CARCASA/ NO USA SWITCH CENTRIFUGO, Funciono al colocarle un capacitor de 60 microfaradios, pero a veces se queda en un estado de indecisión o patina y no arranca a veces. Que me sugiere hacer? Gracias
Greetings from South Africa . I really enjoyed this video except at 3:10 ,where you said divers use diaphragm compressors to fill their cylinders. No no no no no no no! We use multi-stage high pressure compressors - 200 - 300 bar / 3000 - 4500 psi in our air tanks. That's a bit much to demand of a diaphragm pump. they are happier at 125 psi - 9 bar. Om shanti.😇🙏
I really liked it, the evolution of animation is perfect for progressing from the basics to being able to see how it is translated into reality in a complex engine. Great job
I hope that i understood it correctly: The bridge uses the ratio between the upper and the lower resistors (R1<>R2 and R3<>R4). In the formular is somewhere "R1/R2" and "R3/R4". If you increase both resistors at the same time, the ratio between them won't change much. That's also why the strain gauge 3 and 4 are "swapped" at the full bridge. The resistors that'll change have to be kind of unsymmetrical or "crossed".
@@Dampfhammer96 thank you for your answer. I think I understand the importance of having gauges on both sides. However, in my experience, I can't have gauges on the 2 sides, can I at least make a half bridge by having 2 gauges on the same side or is that not possible? If so, is the formula right: Vin/Vout = (K/4)*(ε1-ε2)?
@@learnchannel-TVAh. Ok, so wouldn't this be more a demonstration that due to only DC in this circuit, the components won't have an Inductive Reactance (2pifL), and therefore you won't see a change in Inductance regardless of what material is used in the core? In other words, it's not really that Iron doesn't change inductance, it's that there is not any inductance to demonstrate since there is no frequency change?
@@marcfruchtman9473 the inductance L is affected by an iron core. The inductive reactance XL depence on the frequency. In this vid veverything is correct.
ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-1Y_pQCUdUcw.html Hola Bienvenido. En este vídeo expliqué cómo funciona el motor CC tradicional (con escobillas de carbón). Con subtítulos en español.