You helped me immensely with my tests last semester, and you're still coming in to help this semester. Appreciate how you review content learned prior to ensure clarity. Your playlist blesses me
So, even if the second compound (2-bromoprophane) doesn't contain an element of symmetry (because the H and the Br doesn't reflect to each other), I can consider the three hydrogens of the -CH3 homotopic? Have I understand well? Thank you very much for this video!!!
ugh in first year OCHEM they dont care about ringed sp3 not being able to rotate. I was doing them like how you did but apparently its wrong for first year ochem
at 7:57 why did you group the wedged and dashed hydrogen together, whereas on the previous sample you separated and had 7 signals, but here 3. If you had done the same as in last example, you'd have 5 signals, no?
So if you check back at the previous example we have Br and H on carbon 1, so there is a Br on the wedge side and an H on the dash side which means the upper and lower surfaces of the molecule have different environments. In this example we have Br wedge and Br dash so the upper and lower face are equivalent. Make sense?
