Chad -- I don't often comment but what you've done here deserves praise. To offer this (for free, I might add) is a work of utmost selflessness. I freakin' admire you for it, man! Keep it up
I have to say that, I literally passed my previous orgo. chem. because of your videos. I learned nothing from my professor. I'm studying through your channel this semester too. Appreciate your efforts. You're the best!
You're amazing! You explain all these concepts so well! I'm passing organic chemistry 2 because of you : ) I was really apprehensive about taking it in the summer but everything is going really good so far ; )
hey chad, Since you describes the nitrogen of the amide as being electron donating so long as it is the atom directly bonded to the benzene ring, could we use the same logic for the oxygen of an ester? If the oxygen of an ester were directly bonded to the benzene ring, it would be an electron donating group, activating, and therefore an ortho/para director, am I right on this? Thank you
which among the following is the most deactivating group aromatic substitution reaction (Please rank the alternatives from strongest to weakest)? A. -NR3 B. -SO3H C. -NO2 D. -CN.
Do electron withdrawing groups destabilize the benzenes in EAS as a result of withdrawing the electron density (and therefore making the conj base of a phenol, for instance, more stable and therefore worse as a nucleophile)? Or is it because the electron withdrawing effects destabilize the carbocation intermediate?
Both!!! Very nice reasoning on both parts. Electron withdrawing groups lower the energy of electrons making 😊nucleophiles more stable and less reactive. But the sigma complex, i.e. the carbocation intermediate in EAS reactions, which is already electron-deficient, is destabilized by these electron-withdrawing groups. Essentially, exactly what you said!
