2 to the x = 12, many don’t know where to start

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5 окт 2024

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Комментарии : 95

@shanoxyshanoxy1230 3 месяца назад

You have no idea how much you help me with math. Im fourteen and learning math everyday because of you. Thank you 😊

@chrisdissanayake6979 3 месяца назад

How sweet and humble you are to appreciate Mr John’s hard work! (I needed to add more to this message) You are only 14 years old! I am 73 and I should be old enough to be your grandmother. I may share some wisdom gained over the years. Humbleness is a worthwhile wholesome quality to have. I think all babies are born with humility, but they tend to lose it as they grow up, because they get influenced by the corrupted society around them. So, please try not to lose your humbleness as you go through life. Life is much more than learning Mathematics. However, when you focus your mind on Mathematics, it helps your mind to keep away from trouble! 😇 I think, overall, this math channel gives us opportunities to observe how we all behave when we can’t do a math problem correctly. Some people’s ego gets hurt and they blame others! So, we get a chance to notice those shortcomings in the real world, learn how to remain humble with compassion and become better humans!

@Kualinar 3 месяца назад

If those videos ONLY help you, he have achieved his goal.

@shanoxyshanoxy1230 3 месяца назад

@@chrisdissanayake6979 Thank you❤️

@shanoxyshanoxy1230 3 месяца назад

@@Kualinar yes he has☺️

@chrisdissanayake6979 3 месяца назад

@@shanoxyshanoxy1230🙏🏽♥️

@lamper2 3 месяца назад

This lesson was a LOT more complex than the problem looked.

@robertdeland3390 3 месяца назад

3.5849625 X = log(12) / log(2) used calculator for the logs. Did this before watching the video. Logarithms are a frequent "go to" if unknown is in the exponent.

@thomasharding1838 3 месяца назад

Good Class! Thanks, I had forgotten this since 1963.

@robertstuart6645 3 месяца назад

The property of logarithms one needs to know for solving these problems is the log of a number to an exponent is the same as the exponent times the log of the number. This is a good practice problem for this property.

@freedomhawk772 3 месяца назад

Great class!

@forrestgreen9369 3 месяца назад

X = log(12)/log(2) = 3.58496...

@haroldlake1005 2 месяца назад

Better approach

@raya.pawley3563 3 месяца назад

Thank you

@stephenwells1559 2 месяца назад

But how does a person manually calculate the log function of a calculator? Trial and error?

@defan2105 2 месяца назад

So what I'm hearing is, if you don't have the proper calculator, there is little hope for this old man to figure this out? How did they do it before calculators?

@russelllomando8460 3 месяца назад

got it kinda solved mentally logic gave me 3.6 good explanation thanks for the fun

@walterwen2975 2 месяца назад

2 to the x = 12, many don’t know where to start: 2³ = 8, 2ˣ = 12; x = ? Straight forward solution: log(2ˣ) = log12, x = log₂12 = log₂[(2²)(3)] = log₂(2²) + log₂3 = 2 + 1.585 = 3.585 Answer check: 2ˣ = 2³·⁵⁸⁵ = 12; Confirmed The calculation was achieved on a smartphone with a standard calculator app Final answer: x = log₂12 = 3.585

@tomtke7351 3 месяца назад

THIS IS A GREAT VIDEO TO PLAY MULTIPLE TIMES TO ASSURE YOU GET EVERYTHING PRESENTED... A L S O you MUST hardcore memorize about logs, exponents and bases.... This is possibly NEW notation.... so spend 10 minutes and commit it to memory. Repeat this lesson tomorrow.... Then search out other RU-vids on logarithms. 2^2 + 2^3 = 12 I.E. 4 + 8 = 12✔️ 2^2+2^3 = 2^2(1+2) = 2^2(3) So 2^x = 2^2(3) Xlog2= log(2^2(3)) X= log((2^2)(3))/log(2) = ((2log2)+log(3)/(log2) = (2(0.301)+(0.477))/(0.301) = (2 + (0.477/0.301)) = (2+ 1.585) = 3.585 Alternate Xlog2=log12 X= log12/log2 = 3.585

@johnnyragadoo2414 3 месяца назад

I never remember how to do this, but it’s easy to derive on the fly. Another way to express the value 2 is 10^log(2). 12 is then 10^log(2)^x, or 10^(log(2)*x). In other words, the base ten log of 12 is log(2)*x. The base 2 log is log(12)/log(2), which gives you the answer.

@kpdywo848 2 месяца назад

1) 2^x=12 ==> xln2 = ln12 ==> x= ln12/ln2. 2) 2^(ln12/ln2)=12. 8 seconds to calculate, not 1150 seconds (19 mn 10)

@shemiahwalker 3 месяца назад

6 maybe unsure, thank you I learned something new.

@Poult100 3 месяца назад

That stretched my 64 Yr old brain! Thanks for the exercise 👍

@KUS-2024 2 месяца назад

log(2^X)=log(12) X×log(2)=log(4)+log(3) X=(log(4)+log(3))/log(2) X=log(4)/log(2)+log(3)/log(2) X=2+log(3)/log(2)

@eugengrzondziel1706 Месяц назад

Italians loves slow food, US citizen loves slow explanations.

@LarsV62 3 месяца назад

My calculator came up with a similar solution, too, using natural logarithms. That answer is ln(3) / ln(2) +2. It also gave a solution called "root of the equation" with the solution using not base 10 log, but base 2 (aiming from value x?) That answer was x = log2(3) + 2

@freedomhawk772 3 месяца назад

Fantastic! That's what I got.

@prollysine 3 месяца назад

2^(ln12/ln2)=12 , -> x=ln12/ln2 ,

@abdelwahabazeddine7035 2 месяца назад

Summing the 2 equations term to term, it follows : 2^2 +2^3=12 2^2*(1+2)=12 2^2*3=12 2^2*2^(log2(3))=12 2^(1+log2(3))=12 x=1+log2(3) x=1+log(3)/log(2)

@prollysine 2 месяца назад

@@abdelwahabazeddine7035 checking your calculation , 2^(1+log(3)/log(2))=6 ??? , and not 12 ? not clear...

@abdelwahabazeddine7035 2 месяца назад

@prollysine Exact. The error is obvious ( line 5) !!! 2^(2+log(3)/log(2))=12 x=2+log(3)/log(2) Writing math equation in text mode is not easy. Log2(3) means log(3) in base 2.

@prollysine 2 месяца назад

@@abdelwahabazeddine7035 First you wrote: x=1+log(3)/log(2) and now you write x=2+log(3)/log(2), the latter is correct, so x=2+log(3) /log(2) is the good result, have a nice day

@abdelwahabazeddine7035 2 месяца назад

@@prollysine Of course the latter is the correct answer !!! The direct method : x=log(12)/log(2) x=log(4*3)/log(2) x=(log(4)+log(3))/log(2) x=(log(2^2)+log(3))/log(2) x=(2*log(2)+log(3))/log(2) x=2+log(3)/log(2) Six lines instead of five in previous method.

@vespa2860 3 месяца назад

I would love to see a video explaining your rounding technique😉 Kinda like the brutal butchering, but......

@BMF6889 3 месяца назад

I used logic to solve this problem meaning that we are actually solving for the sq root of 12 so the exponent needs to be the sq root of 12 which is 3.46410161513775. Plug that into the x value and you get 12. This seems to work only when dealing with base 2 so the log solution is the better way to go.

@Kualinar 3 месяца назад

2^(✓12)= 11.035665... That's smaller than 12. 2^(ln12/ln2) = 12. 2^(log12/log2) = 12. ln12/ln2 = 3.2849625... log12/log2 = 3.2849625... The only way to get the correct answer is to use logarithm, not a square root.

@BN-hy1nd 2 месяца назад

OR 2^x = 2^3.584. Both sides have a common base i.e 2 so x = 3.584

@stphinkle 3 месяца назад

This is the answer: 3.5849625007211561814537389439478

@louf7178 3 месяца назад

LOL

@gavindeane3670 3 месяца назад

That is an approximation of the answer.

@CliffordMorris-ls9lc 2 месяца назад

I taught this to primary kids I.e, 11 year olds . You just start with base 2 and make a table of answers Eg Base Exponent Answer 2 0 1 2 1 2 2 2 4 2 3 8 2 4 16 2 5 32 Obviously expanded further. You then compare the exponents to the answers . The log is the index or Exponent to that base. So log 16 in base 2 is 4 . Just look at the table. A kid can see this.

@BrandurDavidsen-wd2lp 2 месяца назад

2^x = 12 x log 2 = log 12 x = log 12/ log 2 x = 3,5849

@johnholme783 2 месяца назад

Log 6 with base 2. Eg: Log₂ 6 = x

@freedomhawk772 3 месяца назад

x = 2 + ln(3) / ln(2) OR ln(12)/ln(2)

@freedomhawk772 3 месяца назад

The natural logarithm of 12 divided by the natural logarithm of 2 equals 2 plus the natural logarithm of 3 divided by the natural logarithm of 2.

@brucewellman 3 месяца назад

this is a question about ASU vs meteric when is 32'=to 9 meters?? gravity acieration or is the meteric number wrong and should be 9.81meters per sec per sec

@CliffordMorris-ls9lc 2 месяца назад

A log is the inverse of an exponential,

@rgrinnell 3 месяца назад

2 to 3.5

@Darisiabgal7573 3 месяца назад

3.58496 Log-e 12/Log-e 2

@angelamaro6689 Месяц назад

X = log (12) en base 2.

@taharwackers6373 2 месяца назад

X=log12 à la base 2

@angelico1 2 месяца назад

Is just the definition of log2(12).

@Kualinar 3 месяца назад

Easy. X= log 12 ÷ log 2 ≈ 3.585 (3.5849625....) You can also use ln(12) ÷ ln 2 ≈ 3.585 Liking and posting a comment also help getting a video proposed to more peoples.

@AngelPuti 2 месяца назад

xlog2=log12 x=log12/log2 x=log6

@AngelPuti 2 месяца назад

Log 12/ log2= log12 base2

@jorgepinonesjauch8023 2 месяца назад

😊😊😊😊 casi 20 minutos para darte vueltas, como un verdadero mojón en el agua, pensé que iba ver algo extraordinario 😢

@Joe-pb3lx 3 месяца назад

@charles401 3 месяца назад

If "we're gonna type this into our calculator ", why wouldn't we just type into our calculator log12/log2?

@kpdywo848 2 месяца назад

The last time I did this in the lab where I worked, I was fired, so I learned logarithms. What a waste of time

@guitartommo2794 2 месяца назад

When you see equations with x as a power think logs.

@heribertoborrome 2 месяца назад

X=log 12/log 2

@jimwhalen5675 2 месяца назад

To involved lets similfy the explanation.KISS principle

@elessarstrider5210 3 месяца назад

Next, do fractional tetration.

@louf7178 3 месяца назад

I'm surprised it wasn't a linear power (3.5).

@劉明桂 2 месяца назад

@christianlohmann8577 3 месяца назад

Still remembered: ln(12)/ln(2)

@stevewthespider 3 месяца назад

x is aprox 3.58

@chrisdissanayake6979 3 месяца назад

I am sorry I didn’t have a calculator. I tried to do x log 2 = 12 So, it should be Log 2 12 = x

@richardl6751 3 месяца назад

Your computer or smart phone probably has a calculator.

@chrisdissanayake6979 3 месяца назад

@@richardl6751 Thank you 🙏🏽 But, I did it wrong.

@barrychoi606 3 месяца назад

x log 2 = log 12😊

@chrisdissanayake6979 3 месяца назад

@@barrychoi606 Thank You 🙏🏽

@sk3ffingtonai 3 месяца назад

If I didn't want to understand logarithms, I'd watch this video.

@haroldkaufman74 3 месяца назад

2 to the 4th

@MSHStructuralDesignLtd 3 месяца назад

Its actually closer to 3.585.

@alaeddinemustapha8496 2 месяца назад

X=log12 ÷log2

@parzifalus Месяц назад

Generally enjoy the videos. But want to first see the problem solved manually. Then can add some follow up for those who want to use a calculator. Not useful if only a calculator solution is demonstrated.

@thaerthaer1120 2 месяца назад

Its more than easy 12/ln2

@johnwu2010 2 месяца назад

Too long for explanation. Waste time.

@williamjames305 3 месяца назад

X=3.5

@寧靜致遠-h1r 2 месяца назад

X=log12/log2～=3.584962500721156

@YMH-me2ps Месяц назад

X=5

@YMH-me2ps Месяц назад

Bécasse 2°2+2°3=2°5=12

@roskapostit2609 2 месяца назад

log(12) / log(2) = 3,5849625007211561814537389439

@Ca_milo_G 3 месяца назад

no idea here....42 yrs old

@chrissullivan40 3 месяца назад

So basically just use a calculator. :)

@theophilejulien9288 Месяц назад

You running your mouth senselessly, while you could move faster for a comprehensive understanding

@lwh7301 3 месяца назад

Useless. If you are going to rely on your calculator, why bother with the manual stuff?

@louf7178 3 месяца назад

It is the method to solve exponential equations, which could then reference logarithmic tables or a calculator to get a decimal number.

@redblack8414 3 месяца назад

So that you understand what you are doing.

@soshakobyan3123 2 месяца назад

Is this a joke?

@mushtaqkaukab2698 2 месяца назад

Your teaching method is very poor

@CliffordMorris-ls9lc 2 месяца назад

This guy rabbits on and on . Introducing logs to the base e Euler’snumber then dividing by log base 2 with no explanation. The whole thing is a garbled mess. Sorry but he is crap at teaching and anyone who claims to have learnt anything aleady knew more advanced stuff.. What level he is teaching to is not defined. As a maths teacher I am at a loss to know how any of his children learnt from such a convoluted and mixed up message. Teaching is about simplifying not mixing up ideas . You start with the notion of a log as the inverse of an exponential. Establish this with examples then relate it to the problem. You do not try to tell people about other things like logs to base e. His other point was to establish why he was dividing by log base 2 with examples. Instead he just waffles on congratulating himself as if the object is proving how clever he is solving a very basic problem. Sorry but I despair!

@Bloozguy 3 месяца назад

I guesstimated using the calculator and found it to be ALMOST 2^3.58499 which my calculator gave me the answer of 12.0002287347, so I figured it was close enough. ... I'm not weighing atoms here. (^_^)