The compound which would combine wiTH oxygen would have oxygen with ON -2 so, the metal combining with it would have ON +2, hence. Here 2 would become the n factor, and according to the formula equivalent weight of the metal would be given by molar mass/2 and similarly the equivalent weight of oxygen comes out to be 16/2 = 8. So, in other words the mass of the metal combining with 8gm oxygen would itself be the equivalent weight of the metal.
CAN SOME ONE TELL IS THIS CORRECT SO FOR THIS QUES 16:19 so we know that eq wt=mol.wt/n-factor(v.f) so for oxygen nF IS 2 IF MASS IS 16 g...here it is given 32 so take nf=4 Then eq wt of metal is 68/4=17g/eq
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I hope aapka JEE'24 acha gaya ho (Nahi gaya then don't worry, 2024 saal hi barbaad hai...I hope aap aage acha karo. All the best and thank you for leaving so many comments which motivates other aspirants!)
Bhai oxygen element ka atomic number 8 hota h aur atomic mass 16 hi hota h aur molecular oxygen (O2) ka molecular mass 32g hota h. I think you got confused between atomic mass and number
Molar mass of 1 mole oxygen is 16g. So, mass of o2 is 32g. 16g of O reacts with 24g of Mg. So, 8g of O reacts with 12g of Mg. Mass of element which reacts with 8g of O is called equivalent weight of element. Hence, equivalent weight of Mg is 12g/eq.
