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5 Levels Of “No Answer" (when should we use what?) 

blackpenredpen
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Here are 5 levels of “no answers” in math: Undefined, no solution, no real value, doesn’t exist, and indeterminate. When should we use what?
0:00 Teddy Says Hello
0:30 No Real Value
2:39 No Solution
7:45 Does NOT exist
10:43 Undefined
16:12 Indeterminate
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4 июл 2024

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Комментарии : 1,2 тыс.   
@richardcao7390
@richardcao7390 3 года назад
inconsistent
@blackpenredpen
@blackpenredpen 3 года назад
Oh man, you are right! I missed that one. That one is for systems of equations!!
@richardcao7390
@richardcao7390 3 года назад
@@blackpenredpen yep! Doing matrix for preCalc right now and instantly drew the connection to this video haha
@justinchen9071
@justinchen9071 3 года назад
what's that
@ultrio325
@ultrio325 3 года назад
how do you get inconsistent
@nanamacapagal8342
@nanamacapagal8342 3 года назад
@@ultrio325 for example, x+y=2, 2x+2y=3. The system has no solution for x and y, so our system is inconsistent.
@JaydentheMathGuy
@JaydentheMathGuy 3 года назад
Alternative title: How to tell your math teacher "no".
@blackpenredpen
@blackpenredpen 3 года назад
😆 definitely better
@tomatrix7525
@tomatrix7525 3 года назад
Lol
@m9l0m6nmelkior7
@m9l0m6nmelkior7 3 года назад
@Tangent of circle. xD
@sammitramanan6404
@sammitramanan6404 3 года назад
when she tries to teach you differentiation before limits and you pull up a messed up function because you have studied math the right way
@austinlincoln3414
@austinlincoln3414 2 года назад
Lol
@CardThrower-rb6eg
@CardThrower-rb6eg 3 года назад
You forgot the final level "I don't know how to solve this"
@fisch37
@fisch37 3 года назад
Well, that applies in any case where you forgot to study before an exam
@shivamchouhan5077
@shivamchouhan5077 3 года назад
@@fisch37 😂 lol 😂
@RazorM97
@RazorM97 3 года назад
"left as an exercise for the reader"
@AgaresOaks
@AgaresOaks 3 года назад
Pfft, that's not even close to the final level. Above that there's "open question" (no one knows how to solve this) and "independent of a given set of axioms" (proven that no one can solve this, but it should have a solution).
@orlandomoreno6168
@orlandomoreno6168 3 года назад
@@AgaresOaks independence of a system of axioms doesn't mean that
@DialecticRed
@DialecticRed Год назад
“No real value” also happens to be the official mathematical classification for NFTs
@blocks4857
@blocks4857 Год назад
Value is subjective
@cewla3348
@cewla3348 Год назад
@@blocks4857 cool, so it's indeterminate, meaning that they are completely worthless? Cool! I have INFINITE BITCOIN, since, to me, bitcoin is worth $0.
@rieldebonk1044
@rieldebonk1044 Год назад
@@cewla3348 You dont do THAT MAN!
@Bobspineable
@Bobspineable Год назад
@@cewla3348 to someone else it could be worth millions so it doesn’t matter if it worthless to you, you take advantage of what people think and profit off it. That’s how you get something valueless to get value. That’s what our money and jewelry are. Pieces of metal and paper that we perceive to have value.
@patrickliberatoalves2931
@patrickliberatoalves2931 11 месяцев назад
The value of NFT is imaginary
@Adomas_B
@Adomas_B 3 года назад
Me on my math exam: The answer is left as an exercise to the reader
@akshatvats7992
@akshatvats7992 3 года назад
xD
@YourLocalCafe
@YourLocalCafe 3 года назад
@Lakshya Gadhwal learner*
@idrisShiningTimes
@idrisShiningTimes 2 года назад
Gives me Reimann Zeta Function vibes
@navaneethshettyb9312
@navaneethshettyb9312 Год назад
😂😂
@stratonikisporcia8630
@stratonikisporcia8630 Год назад
@@idrisShiningTimes "I know how to solve this, but I'll only tell you if you give me $500,000"
@jxdinglol
@jxdinglol 2 года назад
"No solution" is used frequently in systems of equations. Two parallel lines have no intersecting points and that is the easiest form of all "no solution" problems to understand.
@saperoi
@saperoi 2 года назад
Also as contradiction where x is 6 but x has to simultaneously be 9
@arvin390
@arvin390 Год назад
Yeah, stuff like x = x + 1
@manioqqqq
@manioqqqq Год назад
then, x=∅ and thus y=∅ ect.
@rynabuns
@rynabuns Год назад
how about non-Euclidian geometry?
@ThomasTheThermonuclearBomb
@ThomasTheThermonuclearBomb Год назад
"No solution" being used there is incorrect, it should be "inconsistent system"
@somerandomsheep
@somerandomsheep 3 года назад
when your parents ask if you are lying you can just tell them "it's a complex statement"
@necrolord1920
@necrolord1920 3 года назад
6:51 technically with the definition, the output is always NON NEGATIVE. An absolute value could be 0 :)
@tperm6695
@tperm6695 3 года назад
Yup, when x=0 absolute value of x is still 0 :)
@angelmendez-rivera351
@angelmendez-rivera351 3 года назад
I agree.
@Th3_Animat0r
@Th3_Animat0r Год назад
This guy: (flawlessly explains all the ways an equation can have no answer) My calculator: "NaN"
@saikitonia
@saikitonia 7 месяцев назад
👵
@Mg_887
@Mg_887 7 месяцев назад
NaN stands for "Not A Number" in js and in ts
@SlidellRobotics
@SlidellRobotics 3 года назад
About 15 minutes in, for 2⁰, you could argue/explain the definition (not prove) that 2⁰ = 2¹⁻¹ = 2¹ * 2⁻¹ = 2 * ½ = 1.
@Shreyas_Jaiswal
@Shreyas_Jaiswal 3 года назад
Yes this is how it is defined. My teacher has also taught me this process.
@user-ot4rp8yn8r
@user-ot4rp8yn8r 3 года назад
I always wonder why 2^0 is a definition
@angelmendez-rivera351
@angelmendez-rivera351 3 года назад
This is not how 2^0 is defined, though. Yes, it is true that 2^0 = 2^[1 + (-1)] = 2^1·2^(-1) = 2·2^(-1) = 1, but this is how one motivates the definition for 2^(-1), not for 2^0. You cannot define 2^(-1) reasonably without first defining 2^0. The actual definition of 2^0 is the product of the 0-tuple which, if having elements, would only consist of the number 2. However, the 0-tuple has no elements and is unique, and since its product is 1, 2^0 = 1. In fact, x^0 = 1. This is just a consequence of how exponentiation is defined. There is nothing else to demonstrate.
@vns1956
@vns1956 2 года назад
I was taught like this: say you have a^n * a^m, the result is going to be a^(n+m). now, lets plug in 0 for one of the exponents: a^n * a^0 = a^(n+0) = a^n see, you multiplied by something and the value didn't change at all, so the "something" must be 1, when "a" is a value other than 0.
@tbg-brawlstars
@tbg-brawlstars 2 года назад
Right!!!!
@kevinleugan6037
@kevinleugan6037 3 года назад
Honestly thought this was going to be a lesson on how to stand up for yourself and reject requests you don't want to handle.
@austinlincoln3414
@austinlincoln3414 2 года назад
Lol
@danielgammo
@danielgammo 2 года назад
too bad its math class
@jay-5061
@jay-5061 2 года назад
Nani
@za1231in
@za1231in 2 года назад
luckily you stumbled onto something much more useful
@xenosmoke8915
@xenosmoke8915 2 года назад
It is that lesson, just for tutors not students 🤣
@mathopediamathexplorer3010
@mathopediamathexplorer3010 3 года назад
I love that doll its like Mr . Bean's doll ...
@SpiderMan-in9rl
@SpiderMan-in9rl 3 года назад
Yeah.. so cute Edit - That doll gives me Nostalgia
@user-wy8ki2ef1m
@user-wy8ki2ef1m 3 года назад
Teddy! His name is Teddy!
@SpiderMan-in9rl
@SpiderMan-in9rl 3 года назад
@@user-wy8ki2ef1m Yup.. now i remember
@artandcraftwithmrudhula9206
@artandcraftwithmrudhula9206 2 года назад
🤣🤣🤣
@chessandmathguy
@chessandmathguy 3 года назад
3:56 how about the most basic of situations with no solution... Solve x+1=x+2 lol
@nanamacapagal8342
@nanamacapagal8342 3 года назад
Thank goodness you stuck a +1 there at the start. If you said x=x+1 then -it still does work in computer science as an incrementor- it's not a condition anymore like your normal equation Edit: got absolutely thrashed in the replies, sorry
@mathsman5219
@mathsman5219 3 года назад
X=0 / 0
@paolo6219
@paolo6219 3 года назад
X+5=x
@_judge_me_not
@_judge_me_not 3 года назад
x=∞
@aasid2446
@aasid2446 3 года назад
0 = 1
@israelkoiku2076
@israelkoiku2076 3 года назад
You forgot to include "No Nontrivial Solution" since every homogeneous system of equations has at least the trivial solution x=0, e.g., in a system of homogeneous linear equations
@captainpolar2343
@captainpolar2343 Год назад
nerd alert
@coolskeletondude5902
@coolskeletondude5902 Год назад
@@captainpolar2343 bro you're watching a math video,dont you think people would be talking about math what a baby
@hcmishra6371
@hcmishra6371 Год назад
@@captainpolar2343 said the fool to the person commenting about math in a math video
@dogmania2892
@dogmania2892 Год назад
@@captainpolar2343 mf we are watching math vid stfu
@brightblackhole2442
@brightblackhole2442 Год назад
@@captainpolar2343 did you expect the MATH video to be like "no real value! repeat after me, no real value! that means there's no answer because you don't know anything past natural numbers yet"
@hongkongmapping
@hongkongmapping 3 года назад
just realised the indeterminate family is on your shirt lmao
@aloysiuskurnia7643
@aloysiuskurnia7643 2 года назад
"Undefined" also works when you are using a function with an argument outside the domain of its function. Say you have "f(x) = x for x > 0". You can say that f(-4) is undefined.
@Uni-Coder
@Uni-Coder 3 года назад
The sixth level of 'no answer' is when you are trying to answer the question "is there a sixth level of 'no answer'."
@kazedcat
@kazedcat 2 года назад
There is a sixth level "undecidable" this is when your axioms are not enough to prove if a statement is true or false.
@3Jeroen3
@3Jeroen3 2 года назад
Ah, yes example of this is the arithmoquine function in Gödels proof
@SG2048-meta
@SG2048-meta 7 месяцев назад
@IonRuby what, Gödel did make proofs
@piadas804
@piadas804 6 месяцев назад
0⁰ is 1; it's literally defined.
@johnpaulhumphrey2981
@johnpaulhumphrey2981 Год назад
19:30 I think 0/0 is inderterminate bc per the long division you used earlier: what, when multiplied by zero is equal to zero? Basically everything. So it is not like 1/0 where we cannot supply a value, it is kinda the opposite, we have too many values.
@JayTemple
@JayTemple 2 года назад
The early explanation of complex numbers reminds me of a Top Ten list I did when I was teaching: Top Ten Lies Math Teachers Tell. It began with, "you can't substract a larger number from a smaller one," and, "you can't divide a smaller number by a larger one," and continued with things like, "You can't take the square root of a negative number." Near the top I had, "20 liters of one substance plus 10 liters of another will always yield 30 liters of the mixture," and the #1 lie was ... "You need to know this."
@pablopereyra7126
@pablopereyra7126 2 года назад
I understand most of these, but I can't seem to spot is the lie in "20 liters of a substance plus 10 of another will always yield 30 liters" Could you explain that?
@JayTemple
@JayTemple 2 года назад
@@pablopereyra7126 Depending on how the substances interact, they might actually yield 30 liters, they might only yield 25 liters, or they could explode.
@mal2ksc
@mal2ksc Год назад
@@JayTemple Also, if you're adding the contents of a 10 liter gas cylinder to a 20 liter gas cylinder, you still have a 20 liter tank, just at increased pressure.
@NoActuallyGo-KCUF-Yourself
@NoActuallyGo-KCUF-Yourself Год назад
Many dissolution processes change the volume due to changing intermolecular forces between the particles. Salt + water is the simplest example. 1.000 L of a 2-molar saline solution mixed with 1.000 L of pure water will not yield a 2.000 L mixture.
@ThomasTheThermonuclearBomb
@ThomasTheThermonuclearBomb Год назад
@@pablopereyra7126 Basically, chemistry makes things weird
@izjemmr
@izjemmr 2 года назад
In my experience, "indeterminate" is applied whenever it refers to a test, as is "inconclusive". Limit tests, like those in the video, and some primality tests are good examples, but I most often see the term used when it has to do with convergence tests for infinite series. For example, the divergence test or nth-term test proves that an infinite series does not converge to any value if the terms in the series do not approach 0, but does not definitively prove the inverse. There are series that do not converge even though the value of their terms approach 0, so in those cases the nth-term test is indeterminate. In any case, it all just means the test cannot prove an answer and more work must be done.
@NoActuallyGo-KCUF-Yourself
@NoActuallyGo-KCUF-Yourself Год назад
That's an okay synonym for inconclusive, but I think inconclusive is a better choice of word for that scenario. To me, inconclusive means that this particular process did not yield a conclusion, but perhaps some other process will. Indeterminate is more like, no, it cannot be determined.
@indigopari
@indigopari 7 месяцев назад
⁠@@NoActuallyGo-KCUF-Yourself I agree, I don't feel like indeterminate fits so well with tests; I usually end up using indeterminate for like expressions that mean you have to go back and try solving another way, like if you end up with 0/0 or 0*infinity or something like that. i guess it depends on the context though, whether that means that a meaningful answer does not exist or it just means that you have to try evaluating with a different method. i guess for a really simple example, if you're evaluating f(x)=(x^2-25)/(x-5) at f(5), and you get 0/0, then that would be indeterminate, and you need to go back and try cancelling or smth, though again, i guess it depends on what you're doing whether x+5=10 would even be a meaningful answer in that context. but i've ended up using indeterminate mostly in like calculus/continuous contexts where if you end up with 0/0 or anything like that that just means you need to go try l'hôpital's or smth
@pancito3108
@pancito3108 Год назад
6:25 √(x²) = |x| This would result in |x| = 25 So x = ±5 And ±5 has -5, so there you have your solution
@peteradler6005
@peteradler6005 Год назад
Sqrt ( x) >=0 by def
@pancito3108
@pancito3108 Год назад
@@peteradler6005 I never said otherwise
@ostepolsegudensprofet
@ostepolsegudensprofet 7 месяцев назад
​@@peteradler6005 okay but why though. (-5)^2=25 so why not (25)^1/2 = -5
@WingMyWay
@WingMyWay 6 месяцев назад
​@@peteradler6005 Its okay to veer off "but its defined" and use math to solve problems instead of jerk off about made up rigor
@xinpingdonohoe3978
@xinpingdonohoe3978 5 месяцев назад
Although I guess he purposefully restricted the domain to take only a single branch of the multivalued function √, and made sure to choose the bit where √(x>0)>0
@johnpaulhumphrey2981
@johnpaulhumphrey2981 Год назад
I was going to close this because it was just another tab, but I loved your pacing, and stuck around. I liked your style and level of explanation. Subscribed
@markovermeer1394
@markovermeer1394 2 года назад
In computing science, we also have "I won't tell you" (no permission or not requested), typically a NULL value.
@gdclemo
@gdclemo 2 года назад
there is also 𝈜 (upside-down T if Unicode doesn't work) which means that this program never halts.
@technoultimategaming2999
@technoultimategaming2999 2 года назад
But null can be an answer. For example set A can be empty, and if someone asks you how many elements are in set A and you say it's empty. That is still a solution
@markovermeer1394
@markovermeer1394 2 года назад
@@technoultimategaming2999 That would not be represented as NULL: an empty set would typically be returned as empty array. Your situation is option 2 of the alternatives in this presentation.
@dojelnotmyrealname4018
@dojelnotmyrealname4018 7 месяцев назад
Null usually means "does not exist" which is "no solution" tho.
@chyawanprash
@chyawanprash 3 года назад
I disagreed a lot with the √(x) = - 5 but then I came to understand this really well actually. When ever we want both roots, we actually mention ± which means that √x can only be other the positive or negative value. And as far as mathematics is concerned, √x is *_defined_* to give the positive value. Wow, this makes so much sense now!
@math_the_why_behind
@math_the_why_behind 3 года назад
Right! The sqrt(x) could also be 0 though :)
@dioniziomorais8138
@dioniziomorais8138 3 года назад
Correct, but 'twas just examples.
@math_the_why_behind
@math_the_why_behind 3 года назад
@@dioniziomorais8138 Right, they were just examples. I just mentioned it because he said it was defined to be positive, but it could also be zero, and zero isn't positive :) But yes for that specific example the answer is defined to be the positive one :)
@dioniziomorais8138
@dioniziomorais8138 3 года назад
@Math: The Why Behind ok, I don't have a great understanding in math, I'm not even an native english speaker lol
@beatoriche7301
@beatoriche7301 3 года назад
Well, the real answer is that, for positive real values other than 0, the equation x^2 = a actually has two solutions; we want sqrt(x) to be a function, which means it has to yield a single output value, and so the square root function is defined to be the positive solution to that equation. It's similar in the complex numbers - for every nonzero complex number a, the equation z^2 = a has two distinct solutions. However, in this case, there is no such obvious criterion to latch onto; the square root function is inherently a multi-valued function, which has all sorts of implications for things like power series expansions. There are ways to restrict the output range of the square root multifunction so as to make it a proper function; for example, one common convention is to define the square root of a number to always have positive real part and to be located on the positive imaginary axis for negative numbers. A similar thing occurs when you measure the angle (often called the argument, or arg for short) a nonzero complex number makes with the real axis; obviously, adding any number of full turns will still yield a valid angle to describe that complex number. Here, the usual convention is to restrict the angle to lie in the interval (-π, π]. These types of situations are quite common in complex analysis, and these functions with their naturally but still, in essence, arbitrarily restricted output ranges are known as the principal branches of those functions. However, restricting multifunctions to their principal branches comes with a whole bunch of problems - for instance, general theorems such as arg(z_1*z_2) = arg(z_1) + arg(z_2), the famous multiplication rule for complex numbers, do not hold anymore when the argument is replaced with its principal value. The principal branch of the argument is also not continuous, making it not terribly useful for more advanced analytical purposes. The bottom line, these situations require great care, and conventions are tricky; 5 is the value of the real square root function at 25, but the complex square root - a multifunction - evaluated at 25 has two values, namely 5 and -5 (and so -5 is indeed a square root of 25). By contrast, 5 is the principal square root of 25, which means that, in a sense, the equation sqrt(z) = -5 is indeed not solvable if the square root symbol is referring to the principal root.
@countcrocodile1115
@countcrocodile1115 2 года назад
Not only he explains well, but you can also see how happy he is in his face alone, keep it up man. great video
@manioqqqq
@manioqqqq Год назад
What about his statement that √25≠-5? √25=±5
@alexh.4514
@alexh.4514 9 месяцев назад
Plenty of math teachers on YT say the same things as Bprp, but his absolute joy is what makes him such an effective teacher.
@damianbla4469
@damianbla4469 3 года назад
02:35 The case of "No real value" happens also when we calculate the roots of quadratic equation with discriminant (so-called "delta") is negative.
@blackcat5771
@blackcat5771 3 года назад
so cute
@shrankai7285
@shrankai7285 2 года назад
Wouldn’t that be no real solution, as we are solving an equation?
@dojelnotmyrealname4018
@dojelnotmyrealname4018 7 месяцев назад
The solution exists, it's just not a real value. @@shrankai7285
@user-vn7ce5ig1z
@user-vn7ce5ig1z 3 года назад
A simple example for No Solution is "x + 1 = x + 2" It almost looks trivially solvable but obviously isn't, regardless of the system.
@radupopescu9977
@radupopescu9977 2 года назад
No solution in real and complex numbers!!! BUT, in ordinals numbers, there is another issue.
@thelaststraw1467
@thelaststraw1467 11 месяцев назад
if you REALLY wanted to couldnt you sub in infinity? of course its not a number tho...
@bloomingon6141
@bloomingon6141 7 месяцев назад
@@thelaststraw1467infinity has no value
@thelaststraw1467
@thelaststraw1467 7 месяцев назад
@@bloomingon6141so? how does that imply its not a solution coz it def is
@abigailc8829
@abigailc8829 7 месяцев назад
​@@thelaststraw1467 Because if it's not a number of some sort, it can't be a solution. I can't go and say the answer is "triangle" or "purple" or "ham sandwich" because that isn't how math works. An earlier commenter mentioned ordinal numbers, which is essentially what you're getting at, but infinity isn't an ordinal number - ordinal numbers are essentially used to represent infinity, from my (very limited) understanding of them. You could put in the ordinal solution ω (omega), but that isn't the same thing as infinity because ω + 1 sort of equals ω (except also not really? Ordinal numbers are...weird).
@math_the_why_behind
@math_the_why_behind 3 года назад
Excited to watch this video!
@SlipperyTeeth
@SlipperyTeeth 3 года назад
I think indeterminate is also used to refer to certain cases of convergence tests for integrals.
@scathiebaby
@scathiebaby 2 года назад
0⁰ : Could be 1 or 0, but exponent is stronger, so the 1 wins, therefore 0⁰ = 1
@TheMrFrukt
@TheMrFrukt 3 года назад
Very nice explanation! As always :D
@timothyconnally2167
@timothyconnally2167 2 года назад
As a software developer, I’ve had design discussions about the meaning of “null”. In a database, this is when no value is stored. You’ve supplied a useful set of mathematical meanings. Other non mathematical meanings include “not applicable”, “unknown”, “not yet determined”, “invalid”, “declined to enter”, etc. At first this seems too pedantic, but really it can make a database function better to augment a nullable field with a null reason list to express why a value is missing. Unfortunately databases are not designed to do this easily. Null tends to be the design equivalent of a blank stare.
@chx1618
@chx1618 Год назад
FWIW the inventor of null called it his "billion-dollar mistake".
@justsomeguy5628
@justsomeguy5628 7 месяцев назад
In programming languages like c#, for example, even "null" and "Null" are two different things, and while they are kinda applied datum types and to field types, respectively, but even then, they don't behave the same. One of the most important things about floating point in computation is that it allows NaN to be, ironically enough, a number.
@colly6022
@colly6022 7 месяцев назад
i would say null itself just represents an empty set, and the semantics of what that means are more related to the software's behaviour or programmer's intention rather than being a property of the null field itself. the inverse to this would be "maybe" monads, where they do contain data, but the semantics of how they're used implies there shouldn't be (in some capacity). e.x.: haskell's Maybe, rust's Option, C++'s std::optional, etc..
@beatoriche7301
@beatoriche7301 3 года назад
Technically, the square root of a complex number is a multi-valued function; whilst the real square root of 25 is 5 by definition (as the square root of a real number, if it exists, is defined to be the positive number whose square yields that number), 25 has two complex square roots, namely 5 and -5. In fact, any nonzero complex number has two distinct square roots. Also, 1/0 can obviously be defined to be whatever you like - be it 17, -3, or even a newly invented number such as ∞. In that case, 17*0 would be 1 by definition; the trouble, however, is that this is not consistent with the algebraic structure of a field, as the distributive law would yield 1 = 17(0+0) = 17*0 + 17*0 = 1 + 1 = 2. It would also mean that the multiplicative inverse of a number is not uniquely determined and all sorts of other stuff - if you're willing to make that trade-off, though, you are free to do so, as mathematicians can literally do whatever they want. Similarly, 0^0 can be defined to be 0, 1, or whatever you want, and in fact, there are contexts where 0^0 is defined to be 1 by convention; this is often done, for instance, to avoid cumbersome situations in general formulae such as the binomial theorem. The trouble is that 0^0 cannot be defined in the real or complex numbers while remaining consistent with familiar properties of limits, such as multiplicativity. This is a crucial point; as long as you're not touching limits, you're fine doing whatever you want with 0^0. In fact, you're even fine with limits as long as you formulate all your theorems about limits while excluding all 0^0 type situations. Of course, that's a lot of work, which makes it an unusual convention. It is critical to realize that definitions can mean whatever we want them to mean; the point of definitions is to capture the essence of a certain object, aid learners in understanding a given subject, and make theorems and proofs as brief as possible. You may, for instance, define 1 to be a prime number, but if you're doing number theory afterwards, it would make your theorems longer because, as 1 has very different structural properties from what we generally consider to be the primes, you would have to keep considering it as a special case and potentially exclude it. Of course, this is all just a bunch of sounds coming out of our mouths that we decide means something, and in general, you should always be able to say "wale" instead of "prime number," "eyeshadow" instead of "cardinality," and "lightbulb" instead of "angle." All of it is arbitrary, after all. This thought is brought to its logical conclusion in predicate logic, which, simply put, is a purely syntactical type of language that starts out with only very few basic symbols. One nice way to picture translating your statement into predicate logic is that you feed it to a computer, whom you have previously given a few abbreviations (e. g. A ∧ B is a shorthand for ¬(¬A ∨¬B), A → B is a shorthand for ¬(A ∧¬B), etc., where, if you haven't seen these symbols before, ∧ means "and," ∨ means "or," ¬ means "not," and → means "implies" - normally, you'd use a different type of arrow for that last one, but the typographical limitations of my device don't allow for that), and that the computer basically "unravels" all of it by substituting in what you wrote these things should stand for and makes a rather long mess out of it. Of course, no mathematician actually thinks in those terms; however, the good thing is that all of it is unambiguous and can be deciphered and even checked based on axioms and inference rules that you are to first declare as valid or invalid.
@edgar4887
@edgar4887 3 года назад
Moivre’s theorem
@user-hb6ro7ic2t
@user-hb6ro7ic2t 3 года назад
That's incredibly interesting, I never thought of mathematics as so... constructed. For me, this raises a broader question of truth within mathematics if definitions can bend around exceptions, which they essentially have to if they are to include all situations (ie 0^0). Is there any direction you could point me for more education in this area? It would be much appreciated.
@beatoriche7301
@beatoriche7301 3 года назад
@@user-hb6ro7ic2t The whole area of math philosophy deals exactly with these types of questions; a whole range of mathematicians and philosophers has given all sorts of different answers as to whether or not mathematical statements are objective and/or correspond to the real world in some way, when (if in any case at all) we can reasonably call a statement "true," and so on and so forth. Personally, I align very strongly with the ideas expressed by the English mathematician G. H. Hardy (who summarized his thoughts on the role of mathematics in society in his work _A Mathematician's Apology_) and, more recently, in Paul Lockhart's similarly named essay _A Mathematician's Lament._ If anything, I would personally call myself a mathematical hedonist (that's not like an accepted term or anything, though); I believe mathematics is a purely artistic endeavor limited in scope only by our collective imaginations and that mathematics is valuable insofar as it provides pleasure and entertainment. Basically, it's all a fiction going on in our heads, and we should do it as long as it's fun.
@Strategic.
@Strategic. 3 года назад
that was decently interesting to read
@popularmisconception1
@popularmisconception1 3 года назад
compare: sqrt(25) = x 25 = x^2 there's a slight difference between asking how much sqrt(25) is and asking what numbers multiply themselves to 25. that's why powering your equation to two is not an equivalent transformation. yes it is a matter of definition, but there is a practical reason why thing are defined the way they are. otherwise you could say a length of a hypotenuse is a negative number. so no, square root is not a multivalued function, because functions are not multivalued. but equations can have multiple solution. any time you need a multivalued function, perhaps you should rephrase your problem as an equation.
@reciprocal4286
@reciprocal4286 2 года назад
I am fan of your videos... And your smile when you trying to explain something interesting.. thanks.. for sharing knowledge..
@sunmichoi6888
@sunmichoi6888 3 года назад
Thank you so much for the awesome explanation
@blackpenredpen
@blackpenredpen 3 года назад
Thanks
@tago3860
@tago3860 2 года назад
@@blackpenredpen welcom
@Nebula_ya
@Nebula_ya 3 года назад
Where would an equation like "x + 1 = x" fit?
@blackpenredpen
@blackpenredpen 3 года назад
No solution.
@thebloxxer22
@thebloxxer22 3 года назад
In programming, increments. In reality, see above
@wavingbuddy5704
@wavingbuddy5704 3 года назад
Thinking abstractly: x could be infinity (that obviously isn't a soln) but if you think about it infinity + 1 = infinity
@rhaq426
@rhaq426 3 года назад
@@wavingbuddy5704 huuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuh
@wavingbuddy5704
@wavingbuddy5704 3 года назад
@@rhaq426 infinity doesn't increase in size when you add to it, it's infinity after all. it's not really a mathematically rigorous way of putting it as x+1 = x really doesn't have any solutions I was just being annoying tbh XD
@Pacvalham
@Pacvalham 3 года назад
I think 0^0 should be 1 because the exponent (0) says that you do not multiply the base (0), so you are not multiplying by 0.
@angelmendez-rivera351
@angelmendez-rivera351 3 года назад
Exactly
@Inspirator_AG112
@Inspirator_AG112 Год назад
*[**14:22**]:* Misconception here. The equation b⁰ collapses to an empty product when considering repeated multiplication, which is 1 by definition. This is also applicable to 0⁰ = 1.
@peteradler6005
@peteradler6005 Год назад
Misconception here. If you assume 0^0=1 then b^0=empty product. So your argument is circular.
@wildfire_
@wildfire_ 7 месяцев назад
0^0 is undefined because for the x^0 rule, the logic is as follows: when multiplying powers of the same value, you add the power values together, ie. x^a * x^b = x^(a+b) Thus x^0 can be written as x^1 * x^-1. x^1 is just x and x^-1 equals 1/x. x * 1/x = x/x = 1 That means that in the term 0^0, your trying to solve 0/0, which is conflicting because x/0 is undefined, but x/x = 1
@bruhifysbackup
@bruhifysbackup Месяц назад
so you're saying 0^2 is undefined?
@shashwat4920
@shashwat4920 3 года назад
Wow this guy is still loving the comments. Salute to you 🙋‍♂️
@shivaudaiyar2556
@shivaudaiyar2556 3 года назад
Thanks for such a great content with love from India
@HN-vu8pp
@HN-vu8pp 3 года назад
Didn’t you learn all this at age of two?
@RishaadKhan
@RishaadKhan 3 года назад
@@HN-vu8pp this is so unfunny its funny
@yashkrishnatery9082
@yashkrishnatery9082 3 года назад
@@HN-vu8pp well, we did but revision is necessary. 😂😂
@thephoenix8728
@thephoenix8728 3 года назад
@@HN-vu8pp its complicated bro the teaching pattern here is kinda terrible like we learn differentiation a year before limits so....
@apia46
@apia46 Год назад
"it has no real value" hey look thats me
@avyakthaachar2.718
@avyakthaachar2.718 Год назад
Awesome video. Very helpful ❤👍
@b4ttlemast0r
@b4ttlemast0r 2 года назад
you can prove 2^0=1 and the undefinedness of 0^0 if you define exponentiation as x^1=x; x^(n+1) = x^n * x; x^(n-1) = x^n / x; this means that 2^0= 2^1 / 2= 2 / 2 = 1, and for any x it means that x^0 = x / x, which is equal to 1 for nonzero x, but undefined for 0^0 because division by 0 is undefined edit: by this definition, inf^0 is also equivalent to inf / inf
@damianbla4469
@damianbla4469 3 года назад
05:40 First of all, the general reason why this equation has no solution is this: The left hand side of the equation is positive and the right hand side of the equation is negative. So easy ;)
@damianbla4469
@damianbla4469 3 года назад
I additionally tell that this rule does not always work. For example for the equation: x^2 = -5 the LHS is positive and the RHS is negative but there are the solutions (two solutions - both are complex: x=5i, x=-5i).
@radupopescu9977
@radupopescu9977 2 года назад
@@damianbla4469 You are right, so it has 2 real solution, and 2 complex one's. I didn't think of the complex one's. Sqrt(25) = -5 and Sqrt(25) = 5. In fact any square root of positive something has 2 values, except for 0.
@Galactic-MathWizard
@Galactic-MathWizard 9 дней назад
Uhm... Shouldn't the complex roots be x= √5i and x= -√5i, since (5i)²= -25≠ -5?
@flopsnail4750
@flopsnail4750 Год назад
6:08 The square root operation outputs both positive and negative values. Therefore it has not one answer, but two. 5 and -5, making 25 indeed the correct answer.
@carultch
@carultch Год назад
That's a common misconception. There are both positive and negative solutions to x^2 = 25, but only one of them is uniquely qualified for the job of *the* square root. By convention, sqrt(x) refers only to the positive square root, or principal square root.
@MattMorgasmo
@MattMorgasmo Год назад
I love your videos. Both educational and charmingly presented! Btw.: When you said "hello" at the very beginning you sounded 100% German.
@manaarikicarpentier6038
@manaarikicarpentier6038 3 года назад
At 6:00 ish: For sqrt(x) = -5 x = 25.exp[i(2pi +k*4pi)] Would work (with k as a whole number) I think.
@angelmendez-rivera351
@angelmendez-rivera351 3 года назад
It would not. If the square root function is defined as a function of complex numbers whose output it also complex-valued, then -5 is not in the image of C under Sqrt. This is to say, Sqrt : C -> {z in C : z = 0 or Re(z) > 0 or Re(z) = 0 and Im(z) > 0} is a surjection. However, -1 multiplied by Sqrt(25) is equal to -5, and it does solve the equation x^2 = 25, even though it is not true that Sqrt(25) = -5.
@radupopescu9977
@radupopescu9977 2 года назад
@@angelmendez-rivera351 Sqrt(25) = -5. is true! Because Sqrt(any number except 0)=+/-(other number). Sqrt(25) = -5 and Sqrt(25) = 5. In practice we neglect negative value. There are also complex values. Remember nth root of a number, except 0, has n values.
@angelmendez-rivera351
@angelmendez-rivera351 2 года назад
@@radupopescu9977 No, you are wrong. That is not how roots work.
@angelmendez-rivera351
@angelmendez-rivera351 2 года назад
@@radupopescu9977 sqrt(25) is not defined as the individual solutions to x^2 = 25. That is just not what the symbol sqrt means. You are wrong.
@radupopescu9977
@radupopescu9977 2 года назад
@@angelmendez-rivera351 So all my math professors were idiots... Nice...
@rockinroggenrola7277
@rockinroggenrola7277 3 года назад
In many contexts, 0^0 is actually defined as 1 since it obeys more algebraic rules than if we were to define it as 0.
@MrRogordo
@MrRogordo 3 года назад
Not in Calculus, and that is what he teaches
@brunolevilevi5054
@brunolevilevi5054 3 года назад
@@MrRogordo isnt it especially in calculus that it's defined to be 1? Like if you just take the taylor series of e^x = x^n/n! , if you want to know whats f(0) dont you have to assume that 0^0 is 1? Maybe assume isnt the right word, but 0^0 being equal to 1 makes more sense than like 1^(infinity) being equal to 1 or being equal to infinity
@fgvcosmic6752
@fgvcosmic6752 3 года назад
However, 0^0=1 implies 0÷0=1 Undefined is the only answer that "works"
@vincenzodanello4085
@vincenzodanello4085 3 года назад
@@fgvcosmic6752 why would it imply that? 0^0 means that you multiply 0, 0 times, so basically you don't do any operation. And "doing nothing" in a multiplication = 1. It's the same as 0!. When you do 0!, you don't do any operation since you don't multiply anything at all. Hence why 0! = 1. Same reasoning for the 0^0
@MementoMoriGrizzly
@MementoMoriGrizzly 3 года назад
@@vincenzodanello4085 0! = 1 because there's only 1 way to arrange 0 objects.
@TheWifeHaver436
@TheWifeHaver436 7 месяцев назад
0^0 = 1 Because You can always put a "1 •" before something and it doesnt change For example with 2 1 • 2^2 = 1 • 2 • 2 =4 1 • 2^1 = 1 • 2 = 0 1 • 2^1 = 1 As you can see its always a "• 2" less So with 0 its this 1 • 0^2 = 1 • 0 • 0 = 0 1 • 0^1 = 1 • 0 = 0 1 • 0^0 = 1
@randomname9291
@randomname9291 Год назад
I like how I’m the video you say that 0 to the power of zero is undefined while your shirt shows it as indeterminate
@iwersonsch5131
@iwersonsch5131 3 года назад
x^-a = 1/x^a by definition (for positive a, negative a, and even a=0) => x^0 = 1/x^0 => 0^0 = 1/0^0 => 0^0 is its own multiplicative inverse => 0^0 = 1, as there is no other real number that is its own multiplicative inverse.
@iwersonsch5131
@iwersonsch5131 3 года назад
For nonnegative integer exponents, there is also another rule for powers: x^a = product_1:a(x). The empty product is 1 by definition, regardless of whether the factor it doesn't contain is zero.
@joaquingallardo1728
@joaquingallardo1728 3 года назад
-1 is also its own multiplicative inverse
@iwersonsch5131
@iwersonsch5131 3 года назад
@@joaquingallardo1728 oh right whoops. whatever there's gonna be a reason to exclude it
@angelmendez-rivera351
@angelmendez-rivera351 3 года назад
@Alejo Sanchez The answer to your comment is given by Iwer Sonsch's reply, right above yours.
@angelmendez-rivera351
@angelmendez-rivera351 3 года назад
@@iwersonsch5131 Actually, fixing your argument is quite easy. 0^0 satisfies the equation x = 1/x AND it satisfies the equation x^2 = x. The solutions to the first equation are x = -1 or x = 1. The solutions to the second equation are x = 0 or x = 1. Only x = 1 satisfies both. Therefore, 0^0 = 1.
@ff15damage86
@ff15damage86 3 года назад
Everybody gangsta until complex number can't do anything anymore
@alexh.4514
@alexh.4514 9 месяцев назад
Nah just throw in + i
@justsomeguy5628
@justsomeguy5628 7 месяцев назад
Hey, it's better than when they result in periodic solutions.
@albertlau867
@albertlau867 3 года назад
undefined is often for function, when the input is not in the domain. define f(x) = 3x+1 if x is odd; x÷2 if x is even. we can see that the domain of f is integer. f(27)=82 f(82)=41 f(0.5) is undefined.
@Nameless-qe9hu
@Nameless-qe9hu Год назад
1/2 is an even number, and therefore defined
@gammasennin3304
@gammasennin3304 Год назад
I would like to start this by saying that I absolutely love your channel and videos, you have inspired me to learn and enjoy math for years and so thank you! I do have a bit of confusion with the “no solution” part though, specifically the “sqrt(x) = -5” part as if you rework the equation as “sqrt(x) = i² • x” then square both sides you end up with “x = i⁴ •5²” if you take the fourth root of this you end up with the expression “quartic root(x) = Z = 0 + i•sqrt(5)” which resembles a complex number. I am absolutely no expert on this matter by any means so there is a very high probability that I made a few mistakes along the way, this may not even be a valid solution but I thought about it as soon as I saw the equation so if you could be so kind as to clarify this, it would mean the world to me as learning a new thing, especially from someone as talented and kind as yourself, is a graceful opportunity for me.
@joschistep3442
@joschistep3442 Год назад
Nice idea, but you end up with the same "fake-solution". After you squared them to x = i⁴ *5², you don't have to bother taking the root, just calculate it. You'll end up with i² *i² * 25 = -1 * -1 *25= 25. As said in the video, sqrt(25) ≠ -5, therefore it's a fake-solution.
@winter_c
@winter_c 3 года назад
6:55 you should say non-negative for abs x ccan equal 0
@matthewhunter2443
@matthewhunter2443 3 года назад
5:50 sqrt(25)= + or - 5, meaning that 5 and -5 are solutions
@semicolumnn
@semicolumnn 2 года назад
sqrt is always positive, x²=25 is what you are looking for
@Leo-gb1mo
@Leo-gb1mo 2 года назад
I am surprised lots of students don't know this lol...
@semicolumnn
@semicolumnn 2 года назад
@turbo Yes. The solutions to x²-25=0 is both 5 and -5. A function can only have one value. sqrt() only returns the positive root.
@eydum3948
@eydum3948 6 месяцев назад
Im only 1min and 8 sec in and those whitebord skills are slick
@BryndanMeyerholtTheRealDeal
For the no real value, I usually use a+bi
@asbil3642
@asbil3642 3 года назад
I study maths with arabic and french but i don t know why that man make maths easy with that innocent smile .😘
@Strategic.
@Strategic. 3 года назад
French sucks
@xenosmoke8915
@xenosmoke8915 2 года назад
Imagine walking into this class without knowing he’s holding a mic.
@alexh.4514
@alexh.4514 9 месяцев назад
I seriously thought it was just a cute prop XD
@antoa.2942
@antoa.2942 2 года назад
18:57 everybody happy made me lought
@jellomochas
@jellomochas Год назад
0^x is undefined for negative x (equivalent to 1/(0^-x) = 1/0). 0^0 is indeterminate, and when the exponent zero is a discrete value and not a limit, it is convenient to define all x^0 := 1, including 0^0 (this is used in expressions of polynomials as summations, for example).
@DrAnnesleyPeiris
@DrAnnesleyPeiris 3 года назад
So, for computations 0^0 is undefined. For limits, 0^0 is indeterminate .
@Mothuzad
@Mothuzad 3 года назад
"DNE" is a negation of a quantifier in logic, whereas "undefined" refers to any operation which is given an argument outside its domain. This is consistent with what he says in the video, but more general.
@angelmendez-rivera351
@angelmendez-rivera351 3 года назад
Eh... yes, but really, no. "Undefined" is not actually a word mathematicians have ever really used in their publications. "Undefined" is a buzzword that was basically invented by mathematics teachers and that only really has meaning inside the classroom, not in mathematics in general. What it means is that the answer to the problem in question cannot be given in the specific setting being worked on, for one reason or another. "Undefined" has no meaning outside of the classroom, and as I said, you will never see a mathematician talk about this in a publication, because it not actually a mathematical idea, it is just a tool for teaching.
@Mothuzad
@Mothuzad 3 года назад
@@angelmendez-rivera351 "Undefined" is a common term in academics within the realm of computer science, especially dealing with language specifications. That's just a fun fact, not directly relevant to your reply. In mathematics, the concept of "undefined" still exists for professional mathematicians, I'm sure, but everyone at that level of expertise already knows not to use operands outside the domains of the functions they're using. It's like a competent adult already knowing to look both ways before crossing the street. It's too juvenile to be worth mentioning. But of course, the classroom is where they teach that lesson in the first place.
@gdarthurxs7062
@gdarthurxs7062 3 года назад
Awesome like usual
@teslainvestah5003
@teslainvestah5003 2 года назад
I define w as a number whose square root is -5. I define w as a number whose absolute value is -1. I define w as the limit of sin(x) as x approaches infinity. w is my new favorite number, and it's better than anyone else's favorite number.
@ferln4
@ferln4 2 года назад
how to make mathematicians mald in 4 sentences
@carultch
@carultch Год назад
Lambert, is that you?
@inertiasquared6667
@inertiasquared6667 2 года назад
for 6:00 if you let x=25i^4 (25 * 1) then sqrt(x) = 5i^2 = -5, wouldn't this count as a complex solution? I know its kind of playing a technicality but I can't find any way to contradict it
@guanglaikangyi6054
@guanglaikangyi6054 Год назад
The contradiction, I think, is that it would follow that sqrt(25) = -5, which is not true.
@inertiasquared6667
@inertiasquared6667 Год назад
@@guanglaikangyi6054 Yes if we're working with real numbers. But in complex space you can avoid the contradiction by letting x = 25 * 1, sub 1 for i^4, then when you square root, you get 5 * i^2 which is 5 * -1 i.e. -5. The assertion does in fact have a complex solution.
@tzonic8655
@tzonic8655 4 года назад
No real value: *exists* Complex numbers: let me introduce myself
@eolapade
@eolapade Год назад
In those cases 1, 2, and 3, I think it makes sense to say that a solution of the equation f(x) = 0 does not exist in the real numbers or that the limit of a function as x approaches some number does not exist as a real number or that the value of a function evaluated x does not exist in the real numbers (perhaps because the function is not defined at x). For cases 4 and 5, the fact that a function is not defined at x does not mean that the function cannot be defined at x. An example is the reciprocal function a/x for some fixed real number a. There are some applications where you can define a/0 to be 0. While there may be some ambiguity in defining a/x at 0, we should not interpret "undefined" and "indeterminate" as "cannot be defined" and cannot be determined, respectively.
@abdulahshahzad1732
@abdulahshahzad1732 Год назад
When you were talking about the non existent you gave the example of an equation including -5. Now square root of 25 is 5 but it is also -5, solution of square root of 25 is +-5. So square root of 25 gives the true result -5 and an extra result +5 so solution exists
@WindowsXP_YT
@WindowsXP_YT 3 года назад
√-x = i√x, where x is bigger than 0 and i is the square root of -1.
@sailingteam1minecraft124
@sailingteam1minecraft124 3 года назад
12:07 Absolutely hilarious. Good video anyway 24:18
@radiationpony8449
@radiationpony8449 2 года назад
Complex solution for sqrt(x)=-5: Sqrt(25[(i^2)^2]) ==> 5(i^2) ==> -5
@robloxplayer0003
@robloxplayer0003 2 года назад
When you thought it was going to be a meme video converting real life to math equations but it's actually a helpful video of math terms.
@huhneat1076
@huhneat1076 2 года назад
The main difference between "undefined" and "does not exist" is that anything that "does not exist" still has a definition. The lim(x→∞) sinx is defined, it's [insert definition of limit] for sinx when x approaches infinity, but when you attempt to compute it, it happens that no value can be the answer.
@omp199
@omp199 2 года назад
I don't think that is the distinction. 6 / 0 is "defined" in the same sense that the above limit is "defined". It is defined as the unique number x such that 0x = 6. It just so happens that there is no such number x.
@AwesomepianoTURTLES
@AwesomepianoTURTLES 2 года назад
@@omp199 But the expression 6/0 has no definition. Sin(x) has a definition and if you evaluate the limit quantitatively you will get numbers back as your x increases since sin is defined across the reals. There’s just no answer to the limit itself because it never converges to one number, therefore it doesn’t exist. The question itself is defined very well, while 6/0 doesn’t even mean anything. Asking how many times does 0 go into 6 is nonsensical, but asking if the y value on a unit circle converges to a single number as your angle increases indefinitely makes a lot of sense but has no answer
@omp199
@omp199 2 года назад
@@AwesomepianoTURTLES I can define 6 / 0 as the unique number a such that 0a = 6. I can define the limit of sin(x) as x tends to infinity as the unique number b such that for any ε greater than 0, there exists a number k such that for all x > k, the absolute value of sin(x) - b is less than ε. There. I have given definitions for both. It just so happens that there is no number a that satisfies the first definition, and no number b that satisfies the second definition. So what's the difference?
@NirateGoel
@NirateGoel 2 года назад
@@omp199 0a=6 would define 6 as equaling 0 though. That's not a definition.
@omp199
@omp199 2 года назад
@@NirateGoel No, it wouldn't. I didn't give a definition of the number 6. I defined the _expression_ "6 / 0" as the unique number a such that 0a = 6. That is not a definition of the number 6. It is a definition of the _expression_ "6 / 0". As it happens, there is no number a that satisfies that definition, just as there is no number b that satisfies the definition of the limit of sin(x) as x tends to infinity that I gave in my comment above.
@guidomazzeo3767
@guidomazzeo3767 3 года назад
I would love to have the indeterminate family t-shirt jajajaja
@reelbeenz
@reelbeenz Год назад
'has no real value' hit too close to home
@GayAnnabeth
@GayAnnabeth 3 года назад
one of my favourite examples with the 1^infinity I.F. is when you have the limit of 1 to some function f(x), where f(x) is approaching inifinity, because to deal with it you change from lim 1^f(x) to 1^lim f(x)
@radupopescu9977
@radupopescu9977 2 года назад
1^infinity, can be any value, or no value, and it is case by case. (-1)^infinity is also interesting....
@GayAnnabeth
@GayAnnabeth 2 года назад
@@radupopescu9977 well in the case of just a normal 1, the result should be one it's when we approach 1 that things get wonky
@neilgerace355
@neilgerace355 3 года назад
1:12 If the symbol means "positive square root", then no, there is no positive square root of -9, even in complex numbers. 3i is not a positive number, as positive numbers are real numbers.
@adb012
@adb012 3 года назад
Well, in means principal value. In real numbers the principal value is the positive root.
@fgvcosmic6752
@fgvcosmic6752 3 года назад
Is 3i not a positive complex number?
@neilgerace355
@neilgerace355 3 года назад
@@fgvcosmic6752 There's no ordering of complex numbers, so we don't know which ones are greater than zero, unless the number is purely real.
@adb012
@adb012 3 года назад
@@fgvcosmic6752 Nope. It is a complex number with a positive imaginary part (which, by the way, in the number 3i, or -2+3i for the sake of it, the imaginary PART is 3, the real number that goes wit the i, not 3i)
@angelmendez-rivera351
@angelmendez-rivera351 3 года назад
@@neilgerace355 There is no total ordering on the complex numbers for which complex addition and complex multiplication are isotonic binary functions, but this is irrelevant. The symbol, by definition, refers to the positive-real-part-or-positive-imaginary-part-or-zero-square root. In other words, define C+ := {z is an element of C: 0 = z or 0 < Re(z) or 0 = Re(z) and 0 < Im(z)}. Consider the function sq : C+ -> C, z |-> z·z = z^2. sq is a bijection, and therefore, there exists an inverse function sq^(-1) = sqrt. This is the function which mathematicians, by consensus, call the square root function in complex algebra, and it has codomain C+. This codomain serves as an extension of the idea of "nonnegative real numbers" to complex numbers, albeit with no total ordering. In fact, this idea is useful even outside the topic of nth roots in complex analysis.
@HedinnBjornsson
@HedinnBjornsson 2 года назад
Another kind of “no solution” equation could be 2x+1=2x+5
@P4R5
@P4R5 Год назад
You've basically written down x=x+1 in a camouflaged way
@joschistep3442
@joschistep3442 Год назад
Actually, you've written 1 = 5, and thats a wrong statement.
@corruptconverter2616
@corruptconverter2616 Год назад
0=±4, of course
@purim_sakamoto
@purim_sakamoto 3 года назад
やあ老師 とてもわかりやすかったです😍😍😍
@dracmeister
@dracmeister 2 года назад
A way to look at division by 0 is to look into division as a subtraction: Say you have x/y, You subract y from x until you get y > x, x's remaining value is the remainder and how many times you had to subtract y from x to achieve y > x is the quotient. If you have 6/0. You would subtract 0 from 6, so 6-0. This would go on forever. So does that mean 6/0 is infinite? No. Because, finite values can never DEFINE infinity hence UNDEFINED.
@mahdial-harafsheh2170
@mahdial-harafsheh2170 3 года назад
Can you solve this integral : Integral of t^n/(1+t)^n dt, t from 0 to infinity .
@guitar_jero
@guitar_jero 3 года назад
Does not converge. You could try t/(1+t)^n which is 1/(n-1)(n-2) for n greater than 2
@linggamusroji227
@linggamusroji227 3 года назад
Since lim [t^n/(1+t)^n] as t-->infinite = 1 is not zero, then the integral diverges
@carolinamarcmar
@carolinamarcmar 3 года назад
Teddy is adorable 💖
@greengreninja5725
@greengreninja5725 2 года назад
The indeterminate family is just a code name for things that make my calculator scream.
@xCorvus7x
@xCorvus7x 2 года назад
I feel „no solution“ should rather be called „no solution _under given conditions_“, such as seeking the solution in some specified set (e. g. natural numbers) or imposing restraints such as demanding certain computational qualities. „No real value“ is just a special case of that. Furthermore, the equations asking for numbers whose absolute value or (positive) square root is negative are also undefined. No solution whatsoever exists because none has been defined that would be consistent with the definitions of those functions.
@brunolevilevi5054
@brunolevilevi5054 3 года назад
hey blackpenredpen, I'm still kinda confused, isn't 0/0 by itself indeterminate? Since if you have 0/0 = x then 0x = 0, therefore x can be any number, but if you have 1/0 just saying it is equal to a number doesnt make sense, so its undefined. Or is 0/0 only indeterminate in the context of limits?
@pkmnfrk
@pkmnfrk 3 года назад
Indeterminate means that the formula, as written, does not give a sensible answer. However, as you have noted, for 0x=0, x can be all numbers. That's not a useful result, and none of the infinite number of answers can be said to be _the_ answer. Thus, undefined. (Contrast to, eg f(x) = sqrt(x) for x = 4, which also has multiple answers, +2 and -2, but they are finite and definite)
@brunolevilevi5054
@brunolevilevi5054 3 года назад
@@pkmnfrk sqrt x only gives postive values, its a function, so f(4) is 2 and not 2 and -2. That would be the case if you were talking about y^2 = x
@angelmendez-rivera351
@angelmendez-rivera351 3 года назад
"Indeterminate" is a mathematical description that applies only to expressions containing limits. 0/0 is not indeterminate. lim f(x)/g(x) (x -> c), with lim f(x) (x -> c) = lim g(x) (x -> c) = 0, is indeterminate. 0/0 is not indeterminate. 0/0 is an abbreviation for 0·0^(-1), where 0^(-1) is the symbol representing the multiplicative inverse of 0. Since the multiplicative inverse of 0 does not exist in any of the standard mathematical structures we work with, the symbol 0/0 is just said to be "undefined," although it is well-defined if you work in a wheel.
@octavylon9008
@octavylon9008 3 года назад
Why sqrt(x) = -5 doesnt work ? sqrt(25) = ± 5 , not just +5
@semicolumnn
@semicolumnn 2 года назад
i think the square root always gives positive results, and if you want plus or minus 5 you should have the equation x²=25
@AaronWGaming
@AaronWGaming 2 года назад
NRV was always the shorthand my teachers understood was me saying "no real value" when in school...
@baacloud
@baacloud Год назад
after 20 years thank you SO much for being the person to teach me precisely why anything divided by zero is called "undefined." it's sweet justice for my young self who kept hearing the same "well what if you had six slices of pizza and had to distribute it to zero people???" with no elaboration
@bienvenidos9360
@bienvenidos9360 Год назад
There will be no transaction. Nothing is taking place. No slices can be distributed if there isn't a value to distribute them to. The pizza rots because no one's there to take it??
@karryy01
@karryy01 3 года назад
The ultimate level that finish your homework instantly: "I don't know"
@Ferraco05
@Ferraco05 3 года назад
6/0 = 17 with remainder 6 🌚
@angelmendez-rivera351
@angelmendez-rivera351 3 года назад
LOL
@QuirkyView
@QuirkyView Год назад
That's the first time I've heard long division explained like that. I always thought of it as "How many times does the outside number fit into the inside number?" So when dividing by 0 the answer would be infinity, which is not a number and so calculators could and should say NaN. The way you described division changes that. Though I'd honestly say "no solution" rather than undefined still.
@GreystripeWarrior
@GreystripeWarrior 2 года назад
really cool video
@Felixr2
@Felixr2 3 года назад
An easy way to look at 0^0 is by just looking at the general pattern with exponents. An exponent is in the form a^b. Every time we increase b by 1, we multiply by a, and every time we decrease b by 1, we divide by a. We also say that a^1 = a. Using this, we can determine that a^0 = a/a, so 0^0 = 0/0, which is undefined. Note that for every a =/= 0, a/a = 1, which is consistent with the definition of a^0 (and arguably is where the definition comes from).
@zacknattack
@zacknattack Год назад
0^0 is an empty product, just like any other number to the 0th power. The result of an empty product is 1. The real reason 0^0 is an issue is because a^b is discontinuous at 0^0, so l'hopital's rule must be used if that is the result.
@timelsen2236
@timelsen2236 10 месяцев назад
Using L'Hospital on lnx^x I got infinity , but directly got 1
@liab-qc5sk
@liab-qc5sk 3 года назад
11:42 :the answer is in wheel theory YAY teddy!!!
@kenrickchung8176
@kenrickchung8176 3 года назад
So you would say, no complex value or something like that 🤣
@liab-qc5sk
@liab-qc5sk 3 года назад
@Lakshya Gadhwal read about en.wikipedia.org/wiki/Wheel_theory
@liab-qc5sk
@liab-qc5sk 3 года назад
@Lakshya Gadhwal sorry best thing that i can to you is reading about algebric structures like groups and rings than maybe you will understand better
@angelmendez-rivera351
@angelmendez-rivera351 3 года назад
@Lakshya Gadhwal The value of 8/0 in the complex wheel is equal to /0. There is no simpler way of expressing this number using other complex numbers, because /0 is not a complex number: it is its own number in the wheel... much like how i = sqrt(-1) is its own number in the complex numbers, not more simply expressible using real numbers alone.
@J3ff_K1ng
@J3ff_K1ng Год назад
This video gives me another question, how computer do limits? For example the sin doesn't have a solution and other things are just see what it seems to approximate so how computers see that?
@MG-Raiden
@MG-Raiden 2 года назад
I can’t believe the first one defined me in three words.
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