6V DC to 100V DC Voltage Boost Converter Circuit - Electronics

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This electronics video explains how to design a simple DC to DC voltage boost converter circuit. This circuit increased the voltage from 6V to well over 100V for up to a maximum of 140V.
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Опубликовано:

30 дек 2019

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Комментарии : 26

@nearobserver29 4 года назад

Sir, When u will show ur face😞, U are legend sir

@frncsldd8236 4 года назад

Happy new year bro! Thanks for knowledge.

@adriansacks282 4 года назад

I wonder how many times he had to redo the video bc he showed his hand

@backupaccount2104 3 года назад

@@simonabogoevska2299 literally same

@j5892000 3 года назад

Well.. seeing as the method he used to draw youd never see his hand

@chirpplays455 4 года назад

Thanks a lot. This really helped for my organic chemistry class

@godson200 4 года назад

Was that a compliment or a joke?

@FREE_FREE 2 года назад

ABSOLUTELY AWSOME !!OUTSTANDING!! AND PUT in SUCH A GREAT WAY FOR UNDERSTANDING....I learned a great deal ....Thanks for taking the time to make this Video.....(Piece) 'Very helpfull'

@ForgottenHero 4 года назад

This was very interesting!

@quinsorochan7833 4 года назад

You gotta start using a Breadboard my guy

@paulmacgiollacaoine8619 4 года назад

Nice video, can you explain the use of the transistor in series with the Motor? What does it achieve and why connect the collector back to the base?

@SuperG3FR 4 года назад

Wow that's genius

@successthruknowledge 13 дней назад

cool circuit. I wonder if you made the motor do any work would that reduce the voltage from the inductor? Also what does the collector do on the transitor? Which way will the current go? through the collector or the emitter?

@Hopeless_and_Forlorn 4 года назад

Try using the term "turns," in place of "coils" when talking about inductors. The transformer you used has two coils, but each coil has many turns of wire. In this case, it is the iron core of the transformer that gave you the inductance you need, more than the number of turns. BTW, Is the cutting board in the video a pun on "breadboard," or do you not actually have any breadboards in your lab? They are awfully cheap to own.

@tpshen1451 2 года назад

Will it work if you replaced the motor with a 555 timer oscillator circuit? Because it's pretty awkward to put a motor in such circuit

@physicsandmathematics8248 3 года назад

Can you please tell the values of the components you used? And would the circuit work if I replaced the bulb with an LED?

@kinglucos5146 4 года назад

His shadow revealed 11:58

@user-rx2tk1cb1y Год назад

Hi interesting video, I use already the boost-converter technique in combination with Bedini motor of Newman Motor to load a 470µF capacitor (max 400 volt) up to 170 Volt and than discharge this capacitor to recharge lead 12/24 volt batteries. So rather than recharging batteries with at a constant rate using known chargers, I experienced that a DC-Pulsed technique is maybe faster and potentially rejuvenate the battery as well. If you could bring up a calculated example ? That would be interesting in terms of scaling larger engines.

@smibawazir4761 3 года назад

im going to power up an ebike. im using a 14.8 lipo battery. it is capable of 715 amps. the motor is capable of 110V and 7 amps. i need a decent 10X stepup circuit. can you guide me?

@mahboobali9667 4 года назад

You can increase your voltage by just voltage doubler circuit

@j5892000 3 года назад

Wait isnt the polarity the same as the battery and then when the magnetic field collapse the poles switch on the inductor

@basmannetjeee-fr Год назад

what type of transformer is that?

@scyther0194 3 года назад

I'm inlove with you sir 💖😺

@techview6933 4 года назад

Very Nice!!!! First comment!!

@TheShawna1 2 года назад

So the flow from the battery to the inductor while the switch is closed is D.C. when the switch opens and the magnetic field collapses, A high voltage spike occurs the current +/- Change ie "Alternate" Passes through the Diode which rectifies the High voltage to D.C. Charges the capacitor when the switch closes again the Diode blocks the high voltage D.C. from returning "Discharging" back to the battery and powers the Load.Ok now I understand better.Thanks.jim