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8.2 Predicate Logic: Using the Rules of Inference 

Mark Thorsby
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Professor Thorsby explains how to use the rules of inference in predicate logic using the the Universal Generalization, Universal Instantiation, Existential Generalization, and Existential Instatiation rules.

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25 июл 2024

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Комментарии : 39   
@dt-gamer4021
@dt-gamer4021 4 месяца назад
From 100 level - 300 level, wednesday 13th of March 2024 will be the day I will be writing my last symbolic logic exam in Philosophy department, university of Lagos, Nigeria. All thanks to you Prof. Mark Thorbsy for making symbolic logic easy for me all through the years✨🙇🏾‍♂️😮‍💨
@TomideAdeleke
@TomideAdeleke 9 лет назад
dude, you made this sound not as complicated as my professor made it
@cameronjones8648
@cameronjones8648 9 лет назад
Typo @ 19:08 the conclusion is (x)(Px -> Cx)
@mrguysnailz4907
@mrguysnailz4907 8 лет назад
+Cameron Jones bless you, I came right to the comments looking for something to prove I'm not mad
@stevenf5902
@stevenf5902 3 года назад
I noticed that too! Phew!
@lisarobertson630
@lisarobertson630 10 лет назад
It's so helpful to just hear/see another way of explaining the rules and how to approach the proofs. And it's especially helpful for me since we are using this same book. Thank you!
@ShaneFolden
@ShaneFolden 5 лет назад
Mr. Thorsby, you have completely saved me from my terrible logic professor, thank you so much
@thomassomerville198
@thomassomerville198 10 лет назад
You the man Thorsby
@EightTwoFourWeddingStudios
@EightTwoFourWeddingStudios 10 лет назад
very helpful lecture. glad i found this video. you make things alot more understandable then my professor. keep up the good work :)
@brendanvega-shoemaker6438
@brendanvega-shoemaker6438 3 года назад
Still helpful in 2021
@CandidGestures
@CandidGestures 8 лет назад
This was SO helpful for my final, thank you!
@naharulhayat
@naharulhayat 6 лет назад
this is a gem....thank you...thank you so much
@Garb0e
@Garb0e 11 лет назад
Great lecture, thank you!
@Scurvied
@Scurvied 10 лет назад
Your psychiatrist/doctor/college grad example confused me a bit since you wrote (x)(Px->Dx) in the conclusion instead of (x)(Px->Cx)
@madeachanneljusttocomment2632
@madeachanneljusttocomment2632 8 лет назад
Thank you so much for this it helped a lot
@israali5414
@israali5414 7 лет назад
thaaannnnnnnnkkk yyooouuuu sooooooooooo mcchhh for this video. it was of great help. this will help me score full.❤
@francescopiazza4882
@francescopiazza4882 4 года назад
Great lesson!
@darianjh722
@darianjh722 10 лет назад
You are amazing!!!
@PhilosophySama
@PhilosophySama 3 года назад
You’re the man !!!
@natashaoliveira1293
@natashaoliveira1293 9 лет назад
can someone explain how he used constructive dilemma in example #9?
@bobbyjones8938
@bobbyjones8938 9 лет назад
How come you don't use universal quantifier simple, you just got x
@kevinsweeney2809
@kevinsweeney2809 6 лет назад
Thanks!!
@anikethinge5904
@anikethinge5904 6 лет назад
lavang elaichi..tuya maichi
@filipalaureano1868
@filipalaureano1868 8 лет назад
What's the difference between a constant and a variable? How do I distinguish them?
@Babyssx_breath
@Babyssx_breath 9 лет назад
Can you do a video on invalidity ( predicate logic )
@agatau8190
@agatau8190 5 лет назад
Dziękuję
@sallytamer90
@sallytamer90 11 лет назад
prof. Mark can you please do # 6 in the homework because i tried to do it and i got stuck after line 4 . thanks
@JohnnieCYP
@JohnnieCYP 5 лет назад
Oh, Hi Mark!
@0cards0
@0cards0 5 лет назад
what does he say at 35:05 ? "you can never instantiate an..?"
@sanomi4492
@sanomi4492 6 лет назад
Great video. But how can we recognize the scope of qualifiers. Like Q12, ∃x Ax → ∀x(Bx → Cx), why doesn't ∃ cover the first arrow? In short, why is ∃x( Ax )→ ∀x(Bx → Cx) correct instead of ∃x( Ax → ∀x(Bx → Cx) )?
@draspotnuk
@draspotnuk 4 года назад
how do you prove whether something is wrong, or the argument is invalid? I've been having a hard time grasping this with PL.
@maxpercer7119
@maxpercer7119 2 года назад
28:10 instead of calling the constant implied by Ex Fx a 'mechanical device' it might be better to call it an auxiliary constant, since the existential instantiation gives the (previously not used) constant an auxiliary or perfunctory (stand-in) role. The referent of this auxiliary constant is a real thing, though we may not be able to pinpoint what or who exactly it is. Whatever it is, it exists and we call it 'a'. But i wonder how the axioms of predicate logic actually allow for this, since in a given model the constants refer to specific fixed objects. The constant 'a' refers to some specific individual or object, it is not available as a 'constant placeholder' so to speak. I guess you could make a 'without loss of generality' meta-logical argument - ignore what 'a' previously referred to and use it now to label the referent of Ex Fx.
@learnwithsid2044
@learnwithsid2044 6 лет назад
Prove that ~ B → ~ (A and (A → B)) by Rules of inference
@francescopiazza4882
@francescopiazza4882 4 года назад
36:17 clearly invalid...
@Austin_Schulz
@Austin_Schulz 8 лет назад
You really didn't have to instantiate twice for #9. Rather, it can look like this: 1. (x)(Ax>Bx) 2. ~Bm / (3x)~Ax 3. Am>Bm (1 UI) 4. ~Am (2,3 MT) 5. (3x)~Ax (4 EG)
@mrguysnailz4907
@mrguysnailz4907 8 лет назад
+Papa Schulz your profile pic makes serious comments coming from you strangely hilarious.
@Austin_Schulz
@Austin_Schulz 8 лет назад
MrGuySnailz Right back atcha.
@mrguysnailz4907
@mrguysnailz4907 8 лет назад
I guess :^)
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