A Nice Algebra Math Problem Solve By Math Tutor Susharma

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24 май 2024

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Комментарии : 14

@Pranoghoshal 7 дней назад

Awesome❤❤❤

@wides1982 10 дней назад

b = 19 / (a + 1) - 1, because 19 is a prime number => 1. a + 1 = 19 => b = 0 => a + b = 18 2. a + 1 = -19 => b = -2 => a + b = -20

@s.gsaiphilip8813 Месяц назад

Why 19 + 1 on RHS simply disappear

@tamarshahverdyan2723 23 дня назад

#8 #

@d4django Месяц назад

good

@MARTINWERDER 19 дней назад

The initial equation is : a+ab+b=18 Please ckeck your solution a+b=18. a+b=10 with a=9, b=1 will give 9+9x1+1=18 and is a correct solution.

@alexanderbrinkley4332 17 дней назад

Check your addition. 9 + 9*1 + 1 = 19, not 18.

@anonym5847 Месяц назад

Why a+1 can not be equal to ±9.5, and b+1=±2? And how about a+1=3 and b+1=6⅓? Etc. What a fucking method of solving equations? Are you sure you study algebra in America and not in Zimbabawa?

@pelledanasten1615 Месяц назад

Bro does not know what "a and b are integers" means💀💀💀

@ranjanpatankar3618 Месяц назад

@@pelledanasten1615 I believe it will be easier to understand the solution if we find possible values of (a,b) pair. Check out (a,b) values (0,18), (18,0), (-2,-22) and (-22,-2). In all these case a+ab+b will equal 18. You can derive these 4 pairs from the intermediate steps shown by the author. These 4 cases of (a,b) will lead to the soluton a+b = 18 or -22.

@adw1z Месяц назад

Read the question before writing a stupid comment there are obviously (uncountable) infinitely many solutions without the restriction otherwise as (a+1)(b+1) = 19, so: a + b = {a - 1 + 19/(a+1) ; a real\{-1}}