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A Nice Differential Equation 

SyberMath
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24 окт 2024

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Комментарии : 15   
@emersonchaves567
@emersonchaves567 День назад
Audio is a bit blown
@scottleung9587
@scottleung9587 День назад
Cool!
@Charlykili
@Charlykili День назад
The audio is saturated. Check what that is in the record program you use. Maybe it is just a misconfiguration Keep doing these videos, man! You explain very well always
@NuTahn
@NuTahn День назад
Nice video! If I were to solve this problem I would probably write down y1=c and y2=cx+d and give up😂
@thegiganerd395
@thegiganerd395 День назад
You should look for the case when c=0
@mcwulf25
@mcwulf25 День назад
Probably explodes
@thegiganerd395
@thegiganerd395 День назад
@@mcwulf25 nah, it would be simple; since the antiderivative of 1/x² is just -1/x (the +c is already on the other side). But still, it may give us a 3rd solution.
@andrejivonin2133
@andrejivonin2133 День назад
A linear function can be solution, or Just a constant
@mcwulf25
@mcwulf25 День назад
Right, because both sides will be zero.
@rajeshbuya
@rajeshbuya 20 часов назад
y = -2.log(x) also works
@rafaeldominguez-castro5655
@rafaeldominguez-castro5655 День назад
There is a bug in the vídeo. When is substitued c=a/2, a must disappear. However, both constant are maintained as independent. In the last integration, the integration constant has been forgotten.
@nopegaming2029
@nopegaming2029 День назад
before I watch this , Imma do a prediction , now y'•y'' is the same as ((y')²)'/2 now we make that equal to (y'')' and now we have (y')^2 +C1 = y" we can do a u= y' and then u' = u" then you have this u²+C1 = u' this is a seprable deffretial equation so we solve it with all cases C1 = 0 u'=u² u= -1/(x+C2) y'= -1(x+C2) y= -ln|x+C2|+C3 C1≠0 u'=u²+C1 u=√C1•tan(C1x+C2C1) y'=√C1•tan(C1x+C2C1) y=(√C1/C1)ln|sec(C1x+C2C1)|+C3 lets hope this is correct 😅
@Blaqjaqshellaq
@Blaqjaqshellaq День назад
What if c2=0?
@patrickmauran7316
@patrickmauran7316 14 часов назад
y=-2.log(x) + c
@Chubbity
@Chubbity День назад
There is a nice solution for y'y''=y''' with y = -2lnx
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