A NICE USA OLYMPIAD ALGEBRAIC EQUATION: Check!!

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How to solve this math problem
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Explore the interesting world of exponential equations with varying bases and unlock the power of exponentiation! In this educational video, we delve into the concept of exponential equations where the base is not a constant value. Learn the fundamentals, discover the properties, and master solving equations with different bases, all explained clearly and concisely. Join us on this exponential journey and level up your mathematical prowess!
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2 окт 2024

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Комментарии : 36

@AISEDIONFESTUS-yf2lz 3 месяца назад

Thanks!

@Alamaths 3 месяца назад

Thank you so much.❤

@remixgameyt1172 3 месяца назад

My answer before watching: x=0

@Alamaths 3 месяца назад

Thank you

@jeffthebracketman 3 месяца назад

Wrong 0/0 = undefined

@remixgameyt1172 3 месяца назад

@@jeffthebracketman what? are you stupid? (x+7)(x+8)(x+9)(x+10)/(x-7)(x-8)(x-9)(x-10) if x=0 (0+7)(0+8)(0+9)(0+10)/(0-7)(0-8)(0-9)(0-10)=(7*8*9*10)/(-7*-8*-9*-10)=(1*1*1*1)/(-1*-1*-1*-1)=1/1=1

@harrymatabal8448 3 месяца назад

Mr Remi you are another great man to admire well done

@ChavoMysterio 3 месяца назад

@@jeffthebracketman the only roots that would make the equation undefined is 7, 8, 9 or 10.

@Alamaths 3 месяца назад

Hello My Dear Family😍😍😍 I hope you all are well 🤗🤗🤗 If you like this video about How to solve this math problem Please like and subscribe to my channel as it helps me a lot，🙏🙏🙏🙏 ❤❤❤❤❤❤❤❤❤❤❤

@prime423 3 месяца назад

This is a pattern which repeats. Look at the original equation. Its obvious zero is a solution. This is a combination of 4 consecutive integers. The difference is in signs..The explanation is more important than the solution. This pattern is often seen in tests for mathletes.

@Alamaths 3 месяца назад

Thank you

@kshitishmahata8614 3 месяца назад

If you are not familiar to sumout any problem , why are you demonstrating like othes , steps are incomplete

@Alamaths 3 месяца назад

Thank you. Have you subscribed?

@moonlightsonata4866 3 месяца назад

Why don't you let a=x^2+17x+71 and b=x^2-17x+71? It will be much easier.

@Alamaths 3 месяца назад

Okay. Next time thank you. Have you subscribed? ❤❤

@harrymatabal8448 3 месяца назад

I have watched a lot of videos but this one really impressed me. Excellent work Mr Alamaths. Makes you think

@Alamaths 3 месяца назад

Wow, thanks

@recanibiat7633 3 месяца назад

X=0 solution évidente ! c n est pas la peine de continuer même c faut/ c b1 x=0 Vous faites durer la vidéo pour avoir des sous c pas gentil!!!

@Alamaths 3 месяца назад

Thank you. Have you subscribed?

@Alamaths 3 месяца назад

Are you a professor?

@ChavoMysterio 3 месяца назад

Numerator (x+7)(x+8)(x+9)(x+10) (x²+17x+70)(x²+17x+72) Let a=x²+17x (a+70)(a+72) (a+70)(a+70+2) Let y=a+70 y(y+2) Denominator (x-7)(x-8)(x-9)(x-10) (x²-17x+70)(x²-17x+72) Let b=x²-17x (b+70)(b+72) (b+70)(b+70+2) Let z=b+70 z(z+2) [y(y+2)]/[z(z+2)]=1 (y²+2y)/(z²+2z)=1 y²+2y=z²+2z y²-z²+2y-2z=0 (y-z)(y+z)+2(y-z)=0 (y-z)(y+z+2)=0

@ChavoMysterio 3 месяца назад

y-z=0 y=z a+70=b+70 a=b x²+17x=x²-17x 2x²+34x=0 x²-17x=0 x(x-17)=0 x=0 ❤ x-17=0 x=17 ❤

@ChavoMysterio 3 месяца назад

y+z+2=0 y+z=-2 a+70+b+70=-2 a+b+140=-2 a+b=-142 x²+17x+x²-17x=-142 2x²=-142 x²=-71 |x|=i√71 x=±i√71 ❤❤

@Alamaths 3 месяца назад

But x=0 is the correct answer @@ChavoMysterio

@ChavoMysterio 3 месяца назад

@@Alamaths remember, there are more than just one root, including the non real roots.

@Alamaths 3 месяца назад

@@ChavoMysterio yes. Thanks