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Absolute Value of a Function (pt2 quadratic) • [7.2c] Pre-Calculus 11 

the AllAroundMathGuy
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21 окт 2024

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Комментарии : 42   
@jesseroebuck168
@jesseroebuck168 5 лет назад
Explained it a lot better than my text book. Thanks!
@AllAroundMathGuy
@AllAroundMathGuy 4 года назад
You're welcome, and I'm glad you found it helpful! 🙂
@rylandira9298
@rylandira9298 3 года назад
a trick: watch movies on Flixzone. I've been using it for watching loads of movies recently.
@darielelisha6311
@darielelisha6311 3 года назад
@Ryland Ira Definitely, been watching on Flixzone for since november myself :D
@theunderstars...
@theunderstars... 9 месяцев назад
Couldn’t figure this out until I watched this video. Thank you!
@AllAroundMathGuy
@AllAroundMathGuy 6 месяцев назад
You're welcome! Glad this was helpful! 🙂
@TatiannaPara
@TatiannaPara 9 месяцев назад
this video series has been really helpful, thanks very much for taking the time
@AllAroundMathGuy
@AllAroundMathGuy 6 месяцев назад
You are very welcome, and I'm glad to hear that it has been helpful! 🙂
@toluwanimiikotun9853
@toluwanimiikotun9853 4 года назад
wow this is awesome .. simple and straight forward
@AllAroundMathGuy
@AllAroundMathGuy 4 года назад
Thanks so much! 😃
@tatiana1310
@tatiana1310 4 года назад
Hi! Thank you so much! But, what if I have something like thiis | x-1| + |x^2-2x|?
@offthepathworks9171
@offthepathworks9171 4 месяца назад
My issue here is - how would we come up to those piecewise pieces algebraically vs. just logically / graphically?
@AllAroundMathGuy
@AllAroundMathGuy 2 месяца назад
Sorry I missed this when you asked. The algebraic expression for the two pieces is the piecewise function -- one part that has the exact equation that is given, and the the other part that is the opposite, ie. the negative of what is given. To determine where each part occurs, you need the x-intercepts as found in the video. You could test a point in each interval to see where the original function is positive or negative, and then 'flip' the parts that are negative with a negative sign in front.
@adilformuly4568
@adilformuly4568 3 года назад
An amazing explanation. Must appreciate!
@AllAroundMathGuy
@AllAroundMathGuy 3 года назад
Thanks! Glad you liked it! 🙂
@livolofsson9634
@livolofsson9634 3 года назад
Such a good explanation! Thanks a lot!
@ibsashafi8696
@ibsashafi8696 Год назад
Amazing explanation and logic... keep it up Boss
@AllAroundMathGuy
@AllAroundMathGuy Год назад
Thank you - glad you found it useful! 🙂
@yaqoobmusab8066
@yaqoobmusab8066 4 года назад
Simple and straight to the point 👌👌
@AllAroundMathGuy
@AllAroundMathGuy 4 года назад
Glad you found it useful! 🙂
@pavneetkaur4245
@pavneetkaur4245 2 года назад
Thank you so much! Now I won't fail my quiz!
@paramsran1861
@paramsran1861 2 года назад
How did u write so quick 1:59
@Shivam-zk1rf
@Shivam-zk1rf 4 года назад
Thanx a lot keep up the good work
@AllAroundMathGuy
@AllAroundMathGuy 3 года назад
Thank you very much! 🙂
@nadooabaagu9734
@nadooabaagu9734 Год назад
Great explanation thank you!
@AllAroundMathGuy
@AllAroundMathGuy Год назад
You're welcome - glad it was helpful! 🙂
@Not_BhiLZA
@Not_BhiLZA 2 года назад
Thanks from UK
@AllAroundMathGuy
@AllAroundMathGuy 2 года назад
You're welcome! 🙂
@adonaybirru3810
@adonaybirru3810 3 года назад
Great man I like it
@AllAroundMathGuy
@AllAroundMathGuy 3 года назад
Thanks! Glad you like it! 🙂
@jabtechnologies873
@jabtechnologies873 Год назад
Thank you🎉
@AllAroundMathGuy
@AllAroundMathGuy Год назад
You’re welcome! 🙂
@karanjoshi1211
@karanjoshi1211 2 года назад
Thank you soo much! This helped a ton!
@entlemavuso9095
@entlemavuso9095 3 года назад
amazing ! thank you
@AllAroundMathGuy
@AllAroundMathGuy 3 года назад
You're welcome! 🙂
@liyaziiii3026
@liyaziiii3026 3 года назад
Thank you:D
@AllAroundMathGuy
@AllAroundMathGuy 3 года назад
You're welcome! 🙂
@CardiolBee
@CardiolBee Год назад
Perfect
@AllAroundMathGuy
@AllAroundMathGuy Год назад
Thanks! 🙂
@adivhahoratshimolo2671
@adivhahoratshimolo2671 7 месяцев назад
🎉
@waterlilly8330
@waterlilly8330 2 года назад
Thank you :-)
@AllAroundMathGuy
@AllAroundMathGuy 2 года назад
You are welcome! 🙂
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