God bless you man. Chem final 14hours(tomorrow) and here i am pulling off an all nighter. Wish i had saw this video before hand because i spent 3 days on this topic with our notes and it didnt make any sense. Your videos with practice taught me in 30minutes
I was feeling extremely disassociated and was trying to watch videos about it, even though I know I shouldn't. I am glad I ended up here. This made my day. I miss studying chemistry!
Omg u cleared my years of doubts so easily.. our professor take weeks to finish one topic still it's hard understand the concept properly.. im glad i found this vedio ❤❤
I have a question. The concentration of HCl you mention in the video is the one remaining after the reaction completing or it is the total one of the initial HCl when the reaction has not happened yet? May your guys explain it for me? thanks a lot
since HCl is a strong acid so we can't write HCl in the denominator. And so we can't calculate Ka for strong acids like HCl. Its Ka is infinite. Is not it?
+Qudratol Wazir You are correct. HCl is a strong acid and essentially dissociates completely. We would never actually calculate the Ka for HCl because our answer would be nonsensical. We can still write the equilibrium expression for the dissociation for HCl because theoretically, nothing dissociates completely. It is reported that the Ka for HCl is 1.3 x 10^6 depts.washington.edu/eooptic/links/acidstrength.html. I'm not entirely sure how this value was determined (for a Ka, it is essentially infinite since it is greater than 1).
Thz Sir,however I have a question, for example if the dissociation constant of water is 1M`2 , it means 1 mole of hydrogen and hydroxide ions are present in 1 litre of water at 25°C.(btw I knew the number is incorrect).So, my question is if the dissociation constant of a certain acid is 1M, which stands for mol and which stands for 1 dm3 of solution?
at 3:18 you say that the biggest value Ka could be is 1...but wouldn't that mean that only half the acid is dissociated (same number in denominator and numerator)? Thanks!
why didn't you add the 1.32x10^-3 before subtracting them from the .1M? The H+ and CH3COO- are both 1.32x10^-3. If they ended up with a 2:1 instead of 1:1 ratio, wouldn't that change the answer?
Are you confused of how c.H+ went from 0M to 1.32x10^-3M? The professor took the fact that the concentration would be the same for the products according the same coefficient. You need to understand what more about the coefficients.
