You blew my mind with the carbohydrate name reason. My professor never mentioned that and this is such an easy and great way to remember the basic formula for them. You are amazing!
my teacher, google, science website, and my textbook failed to help me really understand epimer. You sir did what I thought was impossible. Thank you so much I really appreciate it. I wish you where my lecturer.
Every time I search for topics on biochem I come across his lectures but when I see so many writings on his board, I feel like I'm going to get lost. All in all, I do get a good understanding from his lectures.
All the students in my class really appreciate your efforts in explaining the different content of Biochemistry. You are a great teacher. Thank You Very Much for Your Help :)
Hey. Love your lectures. Very helpful for biochem courses. I think there is a mistake in one of the wedge and dash diagram in the second column under the fischer projection. The wedge and dash diagram drawn from the fischer projection should have the OH groups going into the board (dashed) and the H coming out of the board (wedged). Another way to remedy it would be to switch the end carbons. Thanks again for all of your videos.
God richly bless you for making learning so easy 🙂 after class if I don't get anything right you always explain it right for me ... thank you so very much 🥰
Is that 3rd 3D depiction on top right correct? Because if you move the CHO to the left, shouldn't the two H(s) be pointing towards us with the 2 OH(s) pointing away?
Silent Language And yes, both examples given in this lecture are epimers, which is actually fine. Thats because all epimers are diastereoisomers but the converse is not true; all diastereoisomers are not epimers.
Structure of D-mannose is not correct. At carbon 2 there should be H on the right and OH on the left.. so it becomes an epimer of glucose which differs at just C2.
l have qoustion please : when l said the« same form of sugar» that is means like glucose and fructose ? or it's means the L and D for the same sugar ?!
fantastic lecture. grateful for it but that's not mannose. If you did the d version that is had the last chiral carbon"s OH group on the right then the OH groups of the 2nd and 3rd carbon atoms will be on the left. D glucose and d mannose are NOT epimers
I'm still a bit confused on how to see the difference with whether the molecule has a aldehyde or ketone group. I can't find the difference in the configuration of the atoms in each group to see how one would identify this.
